e, (-25).(-13).8.(-4).125

= (-25).(-4).8.125.(-13)

= 100.1000.(-13)=-1300000

f, 38.(-43)+43.(-79)-(-43).17

= 38.(-43)+(-43).79-(-43).17

= (-43).(38+79-17)

= (-43).100=-4300

a) ( -7) . 11 + 7 . ( - 89 )

= 7 . (-11) + 7 . (-89)

= 7 . [(-11)+(-89)]

= 7 . (-100)

= -700

b, (-57).(67-34)-67.(34-57)

= -57.67+57.34-67.34+67.57

= 34(57-67)=34.(-10)=-340

c, (17-25)-(-37-25+17)

= 17-25+37+25-17

=37

d, -(-72-25+17)+(-72+17)

= 72+25-17-72+17= 25

d. 54-54+67-37+10
=40

e. 326+174-43-57
=400

f. 351+149-875-125
=-500

\(2018\times\frac{3}{4}+2018\times\frac{1}{4}-2018\)

\(=2018\times\left(\frac{3}{4}+\frac{1}{4}-1\right)\)

\(=2018\times0=0\)

B-a:tương tự bài A

b,\(\frac{14}{18}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)

\(=\frac{7}{9}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)

\(=\frac{7}{9}\times\left(\frac{8}{5}-\frac{3}{5}\right)\)

\(=\frac{7}{9}\times1=\frac{7}{9}\)\

thanks

B-a,\(\frac{3\times125+3\times125}{6\times43+6\times57}=\frac{2\times3\times125}{6\times\left(43+57\right)}\)

\(=\frac{3\times250}{6\times100}=\frac{5}{2\times2}=\frac{5}{4}\)

thanks

A) 2018*3/4+2018*1/4-2018

=2018*(3/4+1/4)-2018

=2018*4/4-2018

=2018*1-2018

=2018-2018

=0

bn thông cảm mình có việc bận,chút nữa mình trả lời câu B

a) (326 - 43) + (174 - 57)

= 326 - 43 + 174 - 57

= (326 + 174) - (43 + 57)

= 500 - 100

= 400

b) (351 - 875) - (125 - 149)

= 351 - 875 - 125 + 149

= (351 + 149) - (875 + 125)

= 500 - 1000

= -500

c) - 418 - (-218 - (-118 - (-318 + 2012)))

= -418 - (-218 -(-118 + 318 - 2012))

= -418 - (-218 + 118 - 318 + 2012)

= -418 + 218 - 118 + 318 - 2012

= -2012

d) (-2) + 7 + (-12) + 17 + ... + (-52) + 57

= 5 + 5 + ... + 5

= 5.12

= 60

e) (-30) + (-29) + ... + 48 + 49 + 50

= 31 + 32 + ... + 49 + 50 (20 số hạng)

= \(\dfrac{\left(31+50\right).20}{2}\)

= 810

Bài 1: Tính hợp lí:

a) (326 - 43) + ( 174 -57)

= 326 - 43 + 174 -57

= (326 + 174) - (43 + 57)

= 500 - 100

= 400

b) (351 - 875) - (125 - 149)

= 351 - 875 - 125 - 149

= (875 + 125) - (351 + 149)

= 1000 - 500

= 500

biểu thức đâu

a: \(A=49+\dfrac{8}{23}-14-\dfrac{8}{23}-5-\dfrac{7}{32}=30-\dfrac{7}{32}=\dfrac{953}{32}\)

b:

Sửa đề: \(B=71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{51}\right)\)

 \(B=71+\dfrac{38}{45}-43-\dfrac{8}{45}+1+\dfrac{17}{51}\)

\(=71-43+1+1\)

=28+2=30

khó quá

a: \(A=49+\dfrac{8}{23}-14-\dfrac{8}{23}-5-\dfrac{7}{32}=30-\dfrac{7}{32}=\dfrac{953}{32}\)

b:

Sửa đề: \(B=71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{51}\right)\)

 \(B=71+\dfrac{38}{45}-43-\dfrac{8}{45}+1+\dfrac{17}{51}\)

\(=71-43+1+1\)

=28+2=30

a) \(\dfrac{\left(-3\right)^{10}\cdot15^5}{25^3\cdot\left(-9\right)^7}\)

\(=-\dfrac{3^{10}\cdot3^5\cdot5^5}{5^6\cdot3^{14}}\)

\(=\dfrac{-3}{5}\)

b: \(\dfrac{4^{30}\cdot3^{43}}{2^{57}\cdot27^{15}}\)

\(=\dfrac{2^{60}\cdot3^{43}}{2^{57}\cdot3^{45}}\)

\(=8\cdot\dfrac{1}{9}=\dfrac{8}{9}\)

b, SSH: (30-20):1+1+11

    Tổng: (30+20)*11:2+275

Tạm thế đã

c, 64 * 25 + 35 * 25 + 25

= 64 * 25 + 35 * 25 + 25 * 1

= (64 + 35 + 1) * 25

= 100 * 25

= 2500