\(pt\Leftrightarrow\frac{29-x}{21}+1+\frac{27-x}{23}+1+...=0\)

\(\Leftrightarrow\frac{50-x}{21}+\frac{50-x}{23}+\frac{50-x}{25}+\frac{50-x}{27}+\frac{50-x}{29}=0\)

\(\Leftrightarrow\left(50-x\right)\left(\frac{1}{21}+\frac{1}{23}+\frac{1}{25}+\frac{1}{27}+\frac{1}{29}\right)=0\)

Do \(\frac{1}{21}+\frac{1}{23}+\frac{1}{25}+\frac{1}{27}+\frac{1}{29}>0\) nên 50 - x = 0 hay x = 50.

pt<=>29-x/21+1+27-x/23+1+...=0

<=>50-x/21+50-x/23+50-x/25+50-x/27+50-x/29=0

<=>(50-x).(1/21+1/23+1/25+1/27+1/29)=0

Do 1/21+1/23+1/25+1/27+1/29>0 nên 50-x=0 hay x=50

a) \(27\cdot75+25\cdot27-150\cdot2023^0\)

\(=27\cdot\left(75+25\right)-150\cdot1\)

\(=27\cdot100-150\)
\(=2700-150\)

\(=2550\)

b) \(3^x+3^{x+1}+16\cdot4=2^2\cdot5^2\)

\(\Rightarrow3^x+3^x\cdot3=100-64\)

\(\Rightarrow3^x\cdot\left(1+3\right)=36\)

\(\Rightarrow3^x\cdot4=36\)

\(\Rightarrow3^x=36:4\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

a) 27.75 + 25.27 - 150.2023⁰

= 27.(75 + 25) - 150.1

= 27.100 - 150

= 2700 - 150

= 2550

b) 3ˣ + 3ˣ⁺¹ + 16.4 = 2².5²

3ˣ.(1 + 3) + 64 = 4.25

3ˣ.4 + 64 = 100

3ˣ.4 = 100 - 64

3ˣ.4 = 36

3ˣ = 36 : 4

3ˣ = 9

3ˣ = 3²

x = 2

a, 39 x 213 + 87 x 39 

= 39 x ( 213 + 87)

= 39 x 300

= 11700

b. 27 x 75 + 25 x 27 - 150 

= 27 x ( 75 + 25 ) - 150 

= 27 x 100 - 150

= 2700 - 150 

= 2550

a) 39  x 213 + 87 x 39

= 39 x ( 213 + 87 )

= 39 x 300

= 11700

b) 27 x 75 + 25 x 27 - 150 

= 27 x ( 75 + 25 ) - 150

= 27 x 100 - 150

= 2700 - 150

= 2550

a, 39x(213+87)

=39x300

=?

b,27x(75+25)-150

=27x100-150

=?

a)\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

=\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\frac{3^2}{5^2}\)

=\(x+\frac{1}{5}=\frac{3}{5}\)

\(x=\frac{2}{5}\)

b)\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=\frac{24}{27}\)

=\(x=-\frac{35}{27}\)

a) \(x=\frac{1}{27}\)

b) \(x=\frac{2}{5}\)

25.(75+25)-100

=25.100-100

=2500-100

=2400

= 25. (75+27) - 150

= 25.102 - 150

= 2550 -150

=240