a: =>3x=10+14=24

=>x=8

b: =>25-30-x=-19

=>-5-x=-19

=>x+5=19

=>x=14

c: =>15-x=12+14=26

=>x=-11

d: =>4x+11-x-34=67

=>3x-23=67

=>3x=90

=>x=30

e: =>-x-14=289-36-289=-36

=>x+14=36

=>x=22

a) 3x=24
     x=8
b) 25-30-x=-19
    25-30+19=x
     14=x
c) 15-x=26
         x=-11
d) 4x+11-x-34=67
    3x=90
      x=30
e) -14-x= -36
          x=-14 -36
          x= 22
      
 

Sao ban chui ban ay?

3-(17-x)=289-(36+289)

3-(17-x)=-36

   17-x=-36+3

    17-x=39

         x=17-39

         x=-22

Nho cho mk nhe!!!!!!

3-(17-x)=289-(36+289)

3-(17-x)=-36

    17-x=39

         x=17-39

         x=-22

Vay x=-22

Nho cho mk 1 h nha!!!

\(\text{3 - ( 17 - x ) = 289 - ( 36 + 289 )} \)

\(\text{=> 3 - 17 + x = 289 - 289 - 36}\)

\(\text{=> -14 + x = 0 - 36}\)

\(\text{=> x - 14 = -36}\)

\(\text{=> x = -36 + 14}\)

\(\text{=> x = -22}\)

\(\text{Vậy : x = -22}\)

nhanh giúp tôi

de thui 

nhung bây giờ mk bận 

nên ko giải hộ bn được

chúc bn hoc tốt!

hihi

a) \(\left(3x+5\right)^2=289\)

\(\left(3x+5\right)^2=17^2\)

\(3x+5=17\)

\(3x=12\)

\(x=4\)

b: \(\Leftrightarrow-37+57+x=20\)

hay x=0

a.

\(3-\left(17-x\right)=289-\left(36+289\right)\)

\(3-17+x=289-36-289\)

\(x=\left(289-289\right)+\left(-36-3+17\right)\)

\(x=-22\)

b.

\(x-73=\left(-35\right)+\left|-55\right|\)

\(x-73=-35+55\)

\(x=-35+55+73\)

\(x=93\)

c.

\(\left|x\right|-3=2\)

\(\left|x\right|=3+2\)

\(\left|x\right|=5\)

\(x=\pm5\)

Vậy x = 5 hoặc x = -5

d.

\(\left|x+1\right|=5\)

\(x+1=\pm5\)

TH1:

\(x+1=5\)

\(x=5-1\)

\(x=4\)

TH2:

\(x+1=-5\)

\(x=-5-1\)

\(x=-6\)

Vậy x = 4 hoặc x = -6

a, \(3-17+x=289-36-289\)

\(\Rightarrow x-14=-36\)

\(\Rightarrow x=-22\)

\(b,x-73=\left(-35\right)+\left|-55\right|\)

\(\Rightarrow x-73=\left(-35\right)+55\)

\(\Rightarrow x-73=20\)

\(\Rightarrow x=93\)

\(c,\left|x\right|-3=2\)

\(\Rightarrow\left|x\right|=5\)

\(\Rightarrow x=\pm5\)

\(d,\left|x+1\right|=5\)

\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+1=5\\x+1=-5\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=4\\x=-6\end{array}\right.\)

3-(17-x)=289-(36+289)

<=> 3-17+x=289-36-289

<=> -14+x=-36 => x=-22

25-(x+5)=-45-(15-45)

<=> 25-x-5=-45-15+45

<=> 20-x=-15=> x=35

34-(21-x)=(3747-30)-3747

<=> 334-21+x=3747-30-3747

<=> 313+x=-30=> x=-343

3 - ( 17 - x ) = 289 - ( 36 + 289 )

3 - 17 + x = 289 - 36 - 289

- 14 + x = - 36

          x = ( - 36 ) - ( - 14 )

          x= - 22

25 - ( x + 5 ) = - 45 - ( 15 - 45)

25 - x - 5 = - 45 - 15 + 45

20 - x = - 15

      x = 20 - ( - 15 )

      x = 35

34 - ( 21 - x ) = ( 3747 - 30 ) - 3747

34 - 21 + x = 3747 - 30 - 3747

13 + x = - 30

       x = ( - 30 ) - 13

       x = - 46

Xin lỗi bn mk nhầm

34-(21-x)=(3747-30)-3747

<=> 34-21+x=3747-30-3747

<=> 13+x=-30

<=> x=-43

\(B=\left(x-3\right)^2+\left(x-11\right)^2\)

\(=x^2-6x+9+x^2-22x+121\)

\(=2\left(x^2-14x+49\right)+32\)

\(=2\left(x-7\right)^2+32\)

Ta có: \(\left(x-7\right)^2\ge0\Leftrightarrow2\left(x-7\right)^2+32\ge32\)

Vậy \(MinB=32\Leftrightarrow x=7\)

\(C=\left(x+1\right)\left(x-2\right)\left(x-3\right)\left(x-6\right)\)

\(=\left(x+1\right)\left(x-6\right)\left(x-2\right)\left(x-3\right)\)

\(=\left(x^2-5x-6\right)\left(x^2-5x+6\right)\)

Đặt \(c=x^2-5x\)lúc này \(C\)thành: \(C=\left(c-6\right)\left(c+6\right)=c^2-36\)

Mà: \(c^2\ge0\forall c\Leftrightarrow c^2-36\ge-36\Leftrightarrow C\ge-36\)

Dấu '' = '' xảy ra: \(c=0\)

\(\Leftrightarrow x^2-5x=0\)

\(\Leftrightarrow x\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-5=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=5\end{cases}}\)

Vậy \(MinC=-36\Leftrightarrow\orbr{\begin{cases}x=0\\x=5\end{cases}}\)

sửa đề : \(C=\left(x+1\right)\left(x-2\right)\left(x-3\right)\left(x-6\right)\)

\(=\left(x^2-5x-6\right)\left(x^2-5x+6\right)\)

Đặt \(x^2-5x-6=t\)

\(t\left(t+12\right)=t^2+12t=t^2+2.6t=t^2+2.6t+36-36\)

\(=\left(t+6\right)^2-36\ge-36\)

Dấu ''='' xảy ra khi \(t=6\Rightarrow x^2-5x=0\Leftrightarrow x\left(x-5\right)=0\Leftrightarrow x=0;x=5\)

Vậy GTNN của C bằng -36 khi x = 0 ; x = 5