8(%7#2;3786(23#;8%7;23#?3#](?;32%78(23;%(3*2;]34((46(;13846(1;58]63#;?%]3;?85?;3]%68%63(#8%,8632;6%]3;6?%8%,3]?8%23#;8%3#2;%68((14?+^#]?&$%3]3#;(+3]4}](#^&?+(:^?%+(},]?%]}^^?,}#]?,#6?*6*3,#3,](6,(6,3]?73%,]7?%]83#?87%3#,?7%,]?7%3#],?%+78)76}#,^*],)#+/(#})(#]}]7?3#68]7}#(])}7+)](^]74(3+)(+7/4?}(*@?/3#?7^{%79{}7^?#/})7},#(7?:%#?:%*)7#6}?/+?+(7^,;{*?%;{,?+?%^{},?+{#,/%?^&]{#,?,]{?^+3(?^&%3/?(+,3/?^%+?+^#/%3^?}%+#/%?^}?&?%}&#/,?%^+#?}/^+7(}7#+/6?)/}#+76)#/?}7+#/}??7+%/}#??{7#}+%?{,+}#^8^kết quả là *,%^*^#,#61?*%*^^?,#^?%$ chúc bạn học giỏi nhe :))) 

Bằng 5^57/7,71 cách giải 12:0,1+7/^1-729=5^57/7,71

5^57/7,71-3:3x2+2:4=5^57/7,71

Chúc bạn học giỏi nhe :)))) 👍👍👍👍👍👍👍👍👍 

Vậy thì D sẽ > 1/64 nha

Chu pa pi pồ nhà nhố.....!!!!

em nên gõ công thức trực quan để được hỗ trợ tốt nhất nhé

       D =           \(\dfrac{1}{7^2}\) - \(\dfrac{2}{7^3}\) + \(\dfrac{3}{7^4}\) - \(\dfrac{4}{7^5}\) +........+ \(\dfrac{201}{7^{202}}\) -  \(\dfrac{202}{7^{203}}\)

7 \(\times\) D  =  \(\dfrac{1}{7}\) -  \(\dfrac{2}{7^2}\) +  \(\dfrac{3}{7^3}\) - \(\dfrac{4}{7^4}\)  + \(\dfrac{5}{7^5}\) -.......- \(\dfrac{202}{7^{202}}\)

7D +D  =   \(\dfrac{1}{7}\) - \(\dfrac{1}{7^2}\) + \(\dfrac{1}{7^3}\) - \(\dfrac{1}{7^4}\) + \(\dfrac{1}{7^5}\) -.........-\(\dfrac{1}{7^{202}}\) - \(\dfrac{202}{7^{203}}\)

         D = (  \(\dfrac{1}{7}\) - \(\dfrac{1}{7^2}\) + \(\dfrac{1}{7^3}\) - \(\dfrac{1}{7^4}\) + \(\dfrac{1}{7^5}\) -.........-\(\dfrac{1}{7^{202}}\) - \(\dfrac{202}{7^{203}}\)) : 8

Đặt    B =      \(\dfrac{1}{7}\) - \(\dfrac{1}{7^2}\) + \(\dfrac{1}{7^3}\) - \(\dfrac{1}{7^4}\) + \(\dfrac{1}{7^5}\) -........+\(\dfrac{1}{7^{201}}\).-\(\dfrac{1}{7^{202}}\) 

  7   \(\times\) B = 1 - \(\dfrac{1}{7}\)+\(\dfrac{1}{7^2}\) - \(\dfrac{1}{7^3}\) + \(\dfrac{1}{7^4}\) - \(\dfrac{1}{7^5}\) +.........- \(\dfrac{1}{7^{201}}\)

7B + B   =  1 - \(\dfrac{1}{7^{202}}\)

          B   =  ( 1 - \(\dfrac{1}{7^{202}}\)) : 8

         D  =  [ ( 1 - \(\dfrac{1}{7^{202}}\)): 8  - \(\dfrac{202}{7^{203}}\)] : 8 

          D = \(\dfrac{1}{64}\) - \(\dfrac{1}{64.7^{202}}\) - \(\dfrac{202}{7^{203}.8}\) < \(\dfrac{1}{64}\)

Bằng 1%^77%/7100 vậy D sẽ > 1/64

D bé hơn hoặc lớn hơn hoặc bằng 1/64

Ta có: (7 -5) x 3 = 2 x 3 = 6

7 x 3 - 5 x 3 = 21 - 15 = 6

Vậy hai biểu thức đã có gía trị bằng nhau, hay:

(7 -5) x 3 = 7 x 3 - 5 x 3

Khi nhân một số hiệu với một số ta có thể lần lượt nhân số bị trừ, số trừ với số đó rồi trừ đi hai kết quả cho nhau.

Ta có: (7 -5) x 3 = 2 x 3 = 6

7 x 3 - 5 x 3 = 21 - 15 = 6

Vậy hai biểu thức đã có gía trị bằng nhau, hay:

(7 -5) x 3 = 7 x 3 - 5 x 3

Khi nhân một số hiệu với một số ta có thể lần lượt nhân số bị trừ, số trừ với số đó rồi trừ đi hai kết quả cho nhau.

cần gấp

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