(1/2+1/6+1/12+1/20+...+1/90) x 100 = ?
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 = x - ( 2 + 4 + ... + 100 )
Mk cần gấp ai nhanh mk tick
A= 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90
=1/(1.2)+1/(2.3)+1/(3.4)+1/(4.5) +1/(5.6)+1/(6.7)+1/(7.8) +1/(8.9)+1/(9.10)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5.+1/5-1/6... +1/9-1/10
=1-1/10
=9/10
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}=x-\left(2+4+..+100\right)\)
Gọi \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)là \(A\)
\(\left(2+4+...+100\right)\)là \(B\). Ta có :
\(A=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{9}-\frac{1}{10}\)
\(A=\frac{1}{1}-\frac{1}{10}=\frac{9}{10}\)
Số số hạng của \(B\)là: \(\left(100-2\right)\div2+1=50\)
Tổng của \(B\)là: \(\left(2+100\right)\times50\div2=2550\)
\(\Rightarrow\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}=x-\left(2+4+..+100\right)=\frac{9}{10}=x-2550\)
\(\Rightarrow x=2550+\frac{9}{10}=2550+0,9=2550,9\)
tính hợp lí :1/100 -1/90-1/72-1/56-1/42-1/30-1/20-1/12-1/6-1/2
1/100 - 1/90 - 1/72 - 1/56 - 1/42 - 1/30 - 1/20 - 1/12 - 1/6 - 1/2 = -0,833
(1/2+1/6+1/12+...+1/72+1/90) : x = 9/20
=> (1/1.2 + 1/2.3 + 1/3.4 + ... + 1/8.9 + 1/9.10) : x = 9/20
=> (1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/8 - 1/9 + 1/9 - 1/10) : x = 9/20
=> (1 - 1/10) : x = 9/20
=> 9/10 : x = 9/20
X = 9/10 : 9/20 = 2
Tìm X
(x-1/2)*(1/2+1/6+1/12+1/20+....+1/90)=1/3
2 x - 1/6 + 1/12 +1/20+...+1/90 = 3/11
\(2\times x-\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}=\frac{3}{11}\)
\(2\times x-2\times\frac{1}{12}+\left(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)=\frac{3}{11}\)
\(2\times\left(x-\frac{1}{12}\right)+\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)=\frac{3}{11}\)
\(2\times\left(x-\frac{1}{12}\right)+\left(\frac{1}{3}-\frac{1}{10}\right)=\frac{3}{11}\)
\(2\times\left(x-\frac{1}{12}\right)+\frac{7}{30}=\frac{3}{11}\)
\(2\times\left(x-\frac{1}{12}\right)=\frac{13}{330}\)
\(x-\frac{1}{12}=\frac{13}{660}\)
\(x=\frac{17}{165}\)
\(2x-\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}=\frac{3}{11}\)
\(\Rightarrow2x-\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)=\frac{3}{11}\)
\(\Rightarrow2x-\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)=\frac{3}{11}\)
\(\Rightarrow2x-\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)=\frac{3}{11}\)
\(\Rightarrow2x-\left(\frac{1}{2}-\frac{1}{10}\right)=\frac{3}{11}\)
\(\Rightarrow2x-\frac{2}{5}=\frac{3}{11}\)
\(\Rightarrow2x=\frac{3}{11}+\frac{2}{5}\)
\(\Rightarrow2x=\frac{37}{55}\)
\(\Rightarrow x=\frac{37}{55}:2\)
\(\Rightarrow x=\frac{37}{110}\)
Vậy \(x=\frac{37}{110}\)
_Chúc bạn học tốt_
B1: THỰC HIỆN PHÉP TÍNH
a, A=1+22+24+.................+2100
b, B=(1+2+3+...+90)x (12x34-6x68):(1/3+1/4+1/5+1/6) ( đấu / là đấu a phần b)
c, C=-1/90-1/72-1/50-1/42-1/30-1/20-1/12-1/6-1/2
B2, TÌM X BIẾT
3x/2x-1/+1=(-2)2-3x(-2)3
Bài 1:
a) A=1+22+24+.................+2100
2A=(1+22+24+.................+2100)
2A=2+23+...+2101
2A-A=(2+23+...+2101)-(1+22+24+.................+2100)
A=2101-1
b)bạn tự làm
c) C=-1/90-1/72-1/50-1/42-1/30-1/20-1/12-1/6-1/2
\(=-\left(\frac{1}{90}+\frac{1}{72}+...+\frac{1}{2}\right)\)
\(=-\left(\frac{1}{10.9}+\frac{1}{9.8}+...+\frac{1}{2.1}\right)\)
\(=-\left(\frac{1}{10}-\frac{1}{9}+\frac{1}{9}-\frac{1}{8}+...+\frac{1}{2}-1\right)\)
\(=-\left(\frac{1}{10}-1\right)\)
\(=-\left(-\frac{9}{10}\right)=\frac{9}{10}\)
Bài 2:
cứ tính lần lượt là ra
Thực hiện phép tính:
a, 1/100-1/90-1/72-1/56-1/42-1/30-1/20-1/12-1/6-1/2
b, (7/29-14/211+21/768):(5/29+20/212+25/1280)2
làm được câu a thui
\(\frac{1}{100}=\frac{1}{10.10}\);\(\frac{1}{90}=\frac{1}{9.10}\);...
Suy ra \(\frac{1}{10.10}-\frac{1}{9.10}-\frac{1}{8.9}-\frac{1}{7.8}-\frac{1}{6.7}-...-\frac{1}{1.2}\)
\(\frac{1}{10}-\frac{1}{10}-\frac{1}{10}-\frac{1}{9}-...-1-\frac{1}{2}\)
\(\frac{1}{10}-\frac{1}{2}\)
\(-\frac{4}{10}\)
Bài 1 :
S1= 1/6 + 1/12 + 1/20 + 1/42 + ...........+ 1/90 + 1/110
S2 = 1/2.15 + 1/15.3 + 1/3.21 + ............+ 6/87.90
Bài 2:
1) x . 5 + x : 100 = 25,-5
2) ( x-7 ) . ( 4x -8 ) = 0
3) 1/1/35 : (1/5 – 1/7 ) – 3/ 3x-2 = 1/1/14: ( 1/2 -1/7)
4 )1/1/3 + 1/6 + 1/10 + ……. + 2/ x.(x+1) = 16/9
Bài 1 :
S1= 1/6 + 1/12 + 1/20 + 1/42 + ...........+ 1/90 + 110
S2 = 1/2.15 + 1/15.3 + 1/3.21 + ............+ 6/87.90
Bài 2:
1) x . 5 + x : 100 = 25,-5
2) ( x-7 ) . ( 4x -8 ) = 0
3) 1/1/35 : (1/5 – 1/7 ) – 3/ 3x-2 = 1/1/14: ( 1/2 -1/7)
4 )1/1/3 + 1/6 + 1/10 + ……. + 2/ x.(x+1) = 16/9