pt <=> (2-x/2009 + 1) = (1-x/2010 + 1) + (1 - x/2011)

<=> 2011-x/2009 = 2011-x/2010 + 2011-x/2011

<=> 2011-x/2009 - 2011-x/2010 - 2011-x/2011 = 0

<=> (2011-x).(1/2009-1/2010-1/2011) = 0

<=> 2011-x=0 ( vì 1/2009-1/2010-1/2011 khác 0 )

<=> x=2011

Vậy x=2011

Tk mk nha

Trả lời :

          Bạn kia trả lời đúng rồi !

Hok tốt nha !

35 x 3/4 +45,5 x 75/100 + 20,5 x75% - 0,75 

= 35. 0,75 + 45,5 . 0,75+ 20,5 . 0,75 - 0,75.1

= 0,75( 35+45,5 + 20,5 -1)

= 0,75.100

= 75

1.A= 1.2.3+2.3.4+...+29.30.31+x=15

\(4A=1.2.3.4+2.3.4.\left(5-1\right)+...+29.30.31.\left(32-28\right)+4x=60\)

\(\Rightarrow4A=1.2.3.4+2.3.4.5-1.2.3.4+...+29.30.31.32-28.29.30.31+4x=60\)

Từ đó suy ra nha bạn

2.\(\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{x\left(x+1\right)}=\frac{2007}{2009}\)

\(=\frac{2}{2\left(2+1\right)}+\frac{2}{3.\left(3+1\right)}+...+\frac{2}{x\left(x+1\right)}=\frac{2007}{2009}\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2007}{2009}\)

\(=2.\left(\frac{1}{2}-\frac{1}{x+1}\right)=\frac{2007}{2009}\\ =1-\frac{2}{\left(x+1\right)}=\frac{2007}{2009}\)

\(\Rightarrow\frac{2}{x+1}=\frac{2}{2009}\Rightarrow x+1=2009\Rightarrow x=2008\)

Ta có:\(\frac{x-1}{2013}+\frac{x-2}{2012}=\frac{x-3}{2011}+\frac{x-4}{2010}\)

\(\Rightarrow\left(\frac{x-1}{2013}-1\right)+\left(\frac{x-2}{2012}-1\right)=\left(\frac{x-3}{2011}-1\right)+\left(\frac{x-4}{2010}-1\right)\)

\(\Rightarrow\frac{x-2014}{2013}+\frac{x-2014}{2012}=\frac{x-2014}{2011}+\frac{x-2014}{2010}\)

\(\Rightarrow\frac{x-2014}{2013}+\frac{x-2014}{2012}-\frac{x-2014}{2011}-\frac{x-2014}{2010}=0\)

\(\Rightarrow\left(x-2014\right).\left(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\right)=0\)

Vì \(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\ne0\)nên để biểu thức =0 

\(\Leftrightarrow x-2014=0\Rightarrow x=2014\)

Ta cTa có: 2013 x − 1 + 2012 x − 2 = 2011 x − 3 + 2010 x − 4 ⇒ 2013 x − 1 − 1 + 2012 x − 2 − 1 = 2011 x − 3 − 1 + 2010 x − 4 − 1 ⇒ 2013 x − 2014 + 2012 x − 2014 = 2011 x − 2014 + 2010 x − 2014 ⇒ 2013 x − 2014 + 2012 x − 2014 − 2011 x − 2014 − 2010 x − 2014 = 0 ⇒ x − 2014 . 2013 1 + 2012 1 − 2011 1 − 2010 1 = 0 
1 = 0

chúc bn hok tốt @_@

Ta có :

\(\frac{x-3}{y-2}=\frac{2}{3}\)\(\Rightarrow\)\(\frac{x-3}{2}=\frac{y-2}{3}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có :

\(\frac{x-3}{2}=\frac{y-2}{3}=\frac{x-3-\left(y-2\right)}{2-3}=\frac{x-3-y+2}{-1}=\frac{4-3+2}{-1}=\frac{3}{-1}=-3\)

Do đó :

\(\frac{x-3}{2}=-3\Rightarrow x=\left(-3\right).2+3=-6+3=-3\)

\(\frac{y-2}{3}=-3\Rightarrow y=\left(-3\right).3+2=-9+2=-7\)

Vậy \(x=-3\)và \(y=-7\)

Ta có \(\frac{x-3}{y-2}=\frac{2}{3}\)

\(\Rightarrow3.\left(x-3\right)=2.\left(y-2\right)\)

\(\Rightarrow3x-9=2y-4\)        (1)

Từ x - y = 4 nên y = 4 + x . Thay  y = 4 + x vào ( 1) ta có 

\(3.\left(y+4\right)-9=2y-4\)

\(\Rightarrow3y+12-9=2y-4\)

\(\Rightarrow3y+3=2y-4\)

\(\Rightarrow3y-2y=-4-3\)

\(\Rightarrow y=-7\)

Do đó x = -3 

Vậy x = -3 và  y = -7

Ta có:

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2}{4}=\frac{3y-6}{9}\)

Áp dụng tính chất của dãy tỉ số = nhau ta có:

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{\left(2x-2\right)+\left(3y-6\right)-\left(z-3\right)}{4+9-4}\)

\(=\frac{\left(2x+3y-z\right)-5}{9}=\frac{50-5}{9}=\frac{45}{9}=5\)

\(\Rightarrow\begin{cases}x-1=2.5=10\\y-2=3.5=15\\z-3=4.5=20\end{cases}\)\(\Rightarrow\begin{cases}x=11\\y=17\\z=23\end{cases}\)

Vậy x = 11; y = 17; z = 23

\(\left|2x-3\right|=3-2\frac{3}{4}\)

\(\Rightarrow\left|2x-3\right|=3-\frac{11}{4}\)

\(\Rightarrow\left|2x-3\right|=\frac{1}{4}\)

\(\Rightarrow\orbr{\begin{cases}2x-3=\frac{1}{4}\\2x-3=\frac{-1}{4}\end{cases}\Rightarrow\orbr{\begin{cases}2x=\frac{13}{4}\\2x=\frac{11}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{13}{8}\\x=\frac{11}{8}\end{cases}}}\)

Vậy \(x=\frac{13}{8}\)hoặc \(x=\frac{11}{8}\)

Ta có: \(\left|2x-3\right|=3-2\frac{3}{4}\)

\(\Leftrightarrow\left|2x-3\right|=\frac{1}{4}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-3=\frac{1}{4}\\2x-3=-\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x=\frac{13}{4}\\2x=\frac{11}{4}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{13}{8}\\x=\frac{11}{8}\end{cases}}\)

\(\left|2x-3\right|=3-2\frac{3}{4}\)

\(\Leftrightarrow\left|2x-3\right|=3-\frac{11}{4}\)

\(\Leftrightarrow\left|2x-3\right|=\frac{1}{4}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-3=\frac{1}{4}\\2x-3=-\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{13}{8}\\x=\frac{11}{8}\end{cases}}\)

a) 3/4+ 1/4:x = 2/5

1/4:x = 3/4-2/5

1/4:x= 7/20

x= 7/20:1/4

x= 7/5

b) chưa học

c) 15/8-1/8: (x/4 - 0,5) = 5/4

1/8: (x/4 -1/2)= 15/8-5/4

1/8:( x/4 -1/2) =  5/8

x/4 - 1/2 = 1/8:5/8

x/4 -1/2= 1/5

x/4= 1/5+1/2

x/4 = 7/7

x/4= 7/7× 4/4

x/4= 28/28

4/4=28/28

phần c ko chắc chắn

đúng k nhé

\(\frac{1}{3}x-\frac{3}{5}=\frac{5}{6}x+2\)

\(\Leftrightarrow\frac{x}{3}-\frac{3}{5}=\frac{5x}{6}+2\)

\(\Leftrightarrow2x-\frac{18}{5}=5x+12\)

\(\Leftrightarrow2x-5x=\frac{18}{5}+12\)

\(\Leftrightarrow-3x=\frac{78}{5}\)

\(\Leftrightarrow3x=-\frac{78}{5}\)

\(\Leftrightarrow x=-\frac{26}{5}\)

Ps: đoạn nào không hiểu hỏi anh nhé. Nhớ k để tạo động lực cho anh nhé :33

                                                                                                                                                     # Aeri #