\(\frac{5.2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}=\frac{5.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}{3^2.\left(2^{17}\right)^2}=\frac{5.2^{13}.2^{22}-2^{36}}{3^2.2^{34}}\)

\(=\frac{5.2^{35}-2^{35}.2}{3^2.2^{34}}=\frac{2^{35}\left(5-2\right)}{3^2.2^{34}}=\frac{2^{35}.3}{3^2.2^{34}}=\frac{2^{34}.2.3}{3^2.2^{34}}=\frac{2}{3}\)

\(\frac{5.4^{15}.9^9.4.3^{20}.8^9}{5.2^9.6^{16}-7.2^{29}.27^6}\)=\(\frac{5.2^{59}.3^{38}}{13^9.2^{34}.3^{16}-7.2^{29}.3^{18}}\)=\(\frac{5.2^{59}.3^{38}}{13^92^5.2^{29}.3^{16}-7.3^2.2^{29}.3^{16}}\)=\(\frac{5.2^{29}.3^{38}}{2^{29}.3^{16}.\left(13^9.2^5-7.3^2\right)}\)

=\(\frac{5.2^{29}.3^{22}.3^{16}}{2^{29}.3^{16}.\left(13^9.2^5-7.3^2\right)}\)= \(\frac{5.3^{22}}{13^9.2^5-7.3^2}\)

nếu làm tiếp đc thì tk Đ cho mk, còn không thì tk cả 2 na !

bạn có ghi nhầm đề ko ?

c) \(3^{11}:3^9-147:7^2\)

= \(3^{\left(11-9\right)}-147:49\)

= \(3^2-3\)

= \(9-3\)

= \(6\)

a, A = \(\dfrac{3^{10}\times10+3^{10}\times6}{3^9\times2^4}\)

    A =  \(\dfrac{3^{10}\times\left(10+6\right)}{3^9\times2^4}\)

    A = \(\dfrac{3^{10}\times16}{3^9\times16}\)

    A = 3 

c, C = \(\dfrac{36^{10}\times25^{15}}{30^8}\)

    C = \(\dfrac{\left(6^2\right)^{10}.\left(5^2\right)^{15}}{30^8}\)

    C = \(\dfrac{6^{20}.5^{30}}{6^8.5^8}\)

   C  =  6¹².5²²

e, E = \(\dfrac{11\times3^{22}\times3^7-9^{15}}{2\times3^{14}}\)

   E  =  \(\dfrac{11\times3^{29}-3^{30}}{2\times3^{14}}\)

  E = \(\dfrac{3^{29}\times\left(11-3\right)}{2\times3^{14}}\)

 E = \(\dfrac{3^{15}\times8}{2}\)

E = 4 \(\times\) 3¹⁵

\(B=\frac{5.2^{14}.2^{22}-2^{36}}{2^{36}}\)\(B=\frac{2^{36}.\left(5-1\right)}{2^{36}}\)

\(B=4\)