a x b = 125

Suy ra ; 125 chia hết cho a, b

125 = 5 x 25

Vậy nếu a = 5 thì b = 25

       nếu b = 25 thì a = 5 

a, x x 34 = 98982 – 75692

x x 34 = 23290

x = 23290 : 34

x = 685

b, x + 38758 = 754 x 125

x + 38758 = 94250

x = 94250 – 38758

x = 55492

a) 2016 - 100.(x+31)=2⁷:2³ 

<=> 2016 - 100.(x+31) = 2⁴ = 16

<=> 100.(x+31) = 2016 - 16 = 2000

<=> x+31 = 2000:100 = 20

<=> x = 20 - 31 = -11

b) (x+8)³ = 125

<=> (x+8)³ = 5³ 

<=> x+8 = 5

<=> x = 5 - 8

<=> x = -3

a) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

b) \(3^x+25=26\times2^2+2\times3^0\)

\(3^x+25=26\times4+2\times1\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(3^x=3^4\)

\(x=4\)

(2x+1)3 = 125 

a)<=> (2x+1)3 = 53

<=> 2x+1 = 5

<=> 2x = 4

<=> x = 2

3^x+25=26 . 2^2 + 2. 3^0

b)3^x+25=104 +2

3^x+25=106

3^x=106+25

3^x=81=3^4

=> x=4                                                                      

a) \(\left(2x-1\right)^4=16\)

\(\)TH1: \(\left(2x-1\right)^4=2^4\)

\(=>2x-1=2\)

\(2x=2+1\)

\(2x=3\)

\(x=\dfrac{3}{2}\)

TH2: \(\left(2x-1\right)^4=\left(-2\right)^4\)

\(=>2x-1=-2\)

\(2x=-2+1\)

\(2x=-1\)

\(x=\dfrac{-1}{2}\)

Vậy x = \(\dfrac{3}{2}\) hoặc x = \(\dfrac{-1}{2}\)

________--

b) \(\left(2x+1\right)^3=125\) ( mình nghĩ đề bài đúng là vầy )

\(\left(2x+1\right)^3=5^3\)

\(=>2x+1=5\)

\(2x=5-1\)

\(2x=4\)

\(x=4:2\)

\(x=2\)

Vậy x = \(2\)

a)  1 3 + 2 3 : x = − 7

⇔ 2 3 : x = − 7 − 1 3 ⇔ 2 3 : x = − 22 3 ⇔ x = 2 3 : − 22 3 ⇔ x = − 1 11

b)  2 3 : x = 1 , 4 − 12 5

⇔ 2 3 : x = − 7 5 ⇔ x = 2 3 : − 7 5 ⇔ x = − 10 21

c)  4 , 5 − 2 x .1 4 7 = 11 14

⇔ 4 , 5 − 2 x = 11 14 : 11 7 ⇔ 9 2 − 2 x = 1 2 ⇔ 2 x = 4 ⇔ x = 2

3:

a: 3^x*3=243

=>3^x=81

=>x=4

b; 2^x*16^2=1024

=>2^x=4

=>x=2

c: 64*4^x=16^8

=>4^x=4^16/4^3=4^13

=>x=13

d: 2^x=16

=>2^x=2^4

=>x=4