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cái này là rút gọn biểu thức

bạn ơi!! 2⁸ +1 chứ, bn xem lại đề cấy

3(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

=(4 - 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

=(2² - 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

=(2⁴ - 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

=(2⁸ - 1)(2⁸ + 1)(2¹⁶ + 1)

=(2¹⁶ - 1)(2¹⁶ + 1)

=(2³² - 1)

mình áp dụng hằng đẳng thức A² - B²=(A - B)(A + B)

Đặt A=3(2² +1)(2⁴+1)(2⁸+1)(2¹⁶+1)

=(4-1)(2²+1)(2⁴+1)(2⁸+1)(2¹⁶+1)

=[(2²-1)(2²+1)](2⁴+1)(2⁸+1)(2¹⁶+1)

=(2⁴-1)(2⁴+1)(2⁸+1)(2¹⁶+1)

=(2⁸-1)(2⁸+1)(2¹⁶+1)

=(2¹⁶-1)(2¹⁶+1)

=2³²-1

3(2² +1)(2⁴+1)(2⁸+1)(2¹⁶+1) = (2² -1)(2² +1)(2⁴+1)(2⁸+1)(2¹⁶+1) = (2⁴-1)(2⁴+1)(2⁸+1)(2¹⁶+1) = (2⁸-1)(2⁸+1)(2¹⁶+1) 

= (2¹⁶-1)(2¹⁶+1) = 2³²-1

=2³²-1

mk chịu

Đặt A=3(22 +1)(24+1)(28+1)(216+1)

=(4-1)(2^2+1)(2^4+1)(28+1)(2^16+1)

=[(2^2-1)(2^2+1)](2^4+1)(2^8+1)(2^16+1)

=(2^4-1)(2^4+1)(2^8+1)(2^16+1)

=(2^8-1)(2^8+1)(2^16+1)

=(2^16-1)

Theo mình ý a bn làm đc

goi y nha A=1/2.(3^2-1)(3^2+1)....(3^32+1)

\(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)

\(=\left(6x+1-6x+1\right)^2\)

\(=2^2=4\)

\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)

\(=2^{32}-1\)

a) \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)

 \(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left(6x-1\right)-2\left(1+6x\right)\left(6x-1\right)\)

\(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left[\left(6x-1\right)-2\left(1+6x\right)\right]\)

\(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left(6x-1-2-12x\right)\)

\(=36x^2+12x+1+\left(6x-1\right)\left(-6x-3\right)\)

\(=36x^2+12x+1+\left(-36x^2-12x+3\right)\)

\(=36x^2+12x+1-36x^2-12x+3\)

\(=4\)

câu b làm thế nào vậy