Bai 1:Rut gon ( 4x-1)3+(4x-3)(16x2+3)
rut gon:
N=2(2x + 5 )^2 - 3(1 + 4x )(1 - 4x)
N=2(2x + 5 )^2 - 3(1 + 4x )(1 - 4x)
= 2 (4x^2 + 20x + 25) - 3(1 - 16x^2)
= 8x^2 + 40x + 50 - 3 + 48x^2
= 56x^2 + 40x - 47
(.....????!!!!!!.....)
rut gon (4x^4-20x^3+13x^2+30x+9)/(4x^2-1)^2
Rut gon A=3x^3-7x^2+5x-1 / 2x^3-x^2-4x+3
4x^4-20x^3+13x^2+30X+9chia cho
(4x^2-1)^2
rut gon ho tui
rut gon bieu thuc (6x+7)(2x-3)-(4x+1)(3x-7/4)
(4x-3)(3x+2)-(6x+1)(2x-5)+1
rut gon bieu thuc
12x2 + 8x - 9x - 6 - 12x2 + 30x + 2x -5 + 1= 31x - 10
rut gon bthuc sau;/a/:a
/a/.a
3.(x-1)-2./x+3/
2./x-3/-/4x-1/
Rut gon bt
\(A=[\frac{(x-1)^2}{x^2+x+1}-\frac{1+4x-2x^2}{x^3-1}-\frac{1}{1-x}]^2:\frac{8x^3+1}{8x^2-4x+2}\)
rut gon cac bieu thuc
2x(2x+1)2 - 3x(x+3)(x-3) - 4x (x+1) 2
Ta có 2x(2x + 1)2 - 3x(x + 3)(x - 3) - 4x(x + 1)2
= 2x(4x2 + 4x + 1) - 3x(x2 - 9) - 4x(x2 + 2x + 1)
= 8x3 + 8x2 + 2x - 3x3 + 27x - 4x3 - 8x2 - 4x
= 8x3 - 3x3 - 4x3 + 8x2 - 8x2 + 2x + 27x - 4x
= x3 + 25x
a oi hinh nhu sai r con +16x2 nua co a , anh tinh lai ho e duoc kh
Kiều Trinh Vũ ko có + 16x2 nhá vì 8x2 - 8x2 = 0 nhá