5^36=(5^3)^12=125^12

11^24=(11^2)^12=121^12

Vì 125^12>121^12=> 5^36>11^24

Vậy 5^36 > 11^24

Ta có :

\(5^{36}=\left(5^3\right)^{12}=125^{12}\)

\(11^{24}=\left(11^2\right)^{12}=121^{12}\)

Vì \(125>121\)\(\Rightarrow\)\(125^{12}>121^{12}\)

Hay \(5^{36}>11^{24}\)

Vậy  \(5^{36}>11^{24}\)

_Chúc bạn học tốt_

ta có:5^36=<5^3>^12=125^12

11^24=<11^2>^12=121^12

mà 125>121=>125^12>121^12 nên 5^36>11^24

Giải:

\(-a^2\left(3a-5\right)+4a\left(a^2-a\right)\)

\(=-3a^3+5a^2+4a^3-4a^2\)

\(=\left(-3a^3+4a^3\right)+\left(5a^2-4a^2\right)\)

\(=a^3+a^2\)

\(=a^2\left(a+1\right)\)

Vậy ...

=-5145

k mk nha bn

-39 . ( 5 - 99 ) + 99 . ( 10 - 99 )

= ( -39 ) . ( -94 ) + 99 . ( -89 )

= 3666 + ( -8811 ) 

= -5145

\(-39\cdot\left(5-99\right)+99\cdot\left(10-99\right)\)

\(=-39\cdot5-\left(-39\right)\cdot99+99\cdot10-99\cdot99\)

\(=-39\cdot5+39\cdot99+99\cdot10-99\cdot99\)

\(=-39\cdot5+99\cdot\left(39+10-99\right)\)

\(=-39\cdot5+99\cdot50\)

\(=-195+4950\)

\(=4755\)

{[( 10 * 2 * 3 ) * 5 ] + 2 - 2 * 6 } + ( 4 * 5 ) ^ 2

= [ ( 60 * 5 ) + 2 - 12 ] + 20^2

= [ 300 + ( -10 )] + 400

= 290 + 400

= 690

moi nguoi mik quen mat tong day la P=120+360+1235 nhe mong mn jup

Chia hết cho 5

Chia 2 dư 1; chia 3 dư 2; chia 9 dư 5

\(\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{5}{12}\\ =\dfrac{3}{12}-\dfrac{4}{12}+\dfrac{5}{12}\\ =\dfrac{3-4+5}{12}\\ =\dfrac{4}{12}\\ =\dfrac{1}{3}\)

\(\left(7.3^5-3^4+3^6\right):3^4\)

\(\Leftrightarrow\left(7.243-81+729\right):81\)

\(\Leftrightarrow2349:81\)

\(\Leftrightarrow29\)

\(\left(7.3^5-3^4+3^6\right)\div3^4\)

\(\Leftrightarrow\left(7.243-81+729\right)\div81\)

\(\Leftrightarrow2349\div81\)

\(\Leftrightarrow29\)

Đúng thì xin để lại một l - i - k - e nhé

45-|-15|:3

=45-15 :3

=45-5

=40

45 - | -15 | : 3

= 45 - 15 : 3

= 45 - 5 

= 40

\(45-|-15|\div3\)

\(=45-15\div3\)

\(=45-5\)

\(=40\)