\(\frac{1}{125}\cdot x+\frac{7}{8}=2\)

\(\frac{1}{125}\cdot x=2-\frac{7}{8}\)

\(\frac{1}{125}\cdot x=\frac{9}{8}\)

\(x=\frac{9}{8}:\frac{1}{125}\)

\(x=\frac{9}{8}\cdot125\)

\(x=\frac{1125}{8}\)

\(\frac{1}{125}\times x+\frac{7}{8}=2\)

\(\frac{1}{125}\times x=2-\frac{7}{8}\)

\(\frac{1}{125}\times x=\frac{16}{8}-\frac{7}{8}\)

\(\frac{1}{125}\times x=\frac{9}{8}\)

\(x=\frac{9}{8}\div\frac{1}{125}\)

\(x=\frac{9}{8}\times125\)

\(x=\frac{1125}{8}\)

\(\frac{1}{125}\cdot x+\frac{7}{8}=2\)

=>\(\frac{1}{125}\cdot x=2-\frac{7}{8}\)

=> \(\frac{1}{125}\cdot x=\frac{9}{8}\)

=>\(x=\frac{9}{8}:\frac{1}{125}\)

=>\(x=\frac{9}{8}\cdot125\)

=>\(x=\frac{1125}{8}\)

150-x=125+7

           150-x=132

                 x=150-132

                 x=18

trình độ bạn mà đặt câu này à? dễ quá

5

4.2x – 3 = 125

4.2x = 125 + 3

4.2x = 128

2x = 128 : 4

2x = 32

2x = 25

x = 5

Vậy x = 5

\(7-x=8-\left(-7\right)\)

\(\Rightarrow7-x=15\)

\(\Rightarrow x=7-15=-8\)

=> 7 - x = 15

=> x = -8

Bài 1 :

\(8^7-2^{18}\)

\(=\left(2^3\right)^7-2^{18}\)

\(=2^{21}-2^{18}\)

\(=2^{18}\left(2^3-1\right)\)

\(=2^{18}\cdot7\)

\(=2^{17}\cdot2\cdot7\)

\(=2^{17}\cdot14⋮14\left(đpcm\right)\)

TAO MỚI LỚP4

\(1,8^7-2^{18}=\left(2^3\right)^7-2^{18}=2^{21}-2^{18}=2^{17}.\left(2^4-2\right)=2^{17}.14⋮14\)

\(2,2014.\left|x-12\right|+\left(x-12\right)=2013.\left|12-x\right|\)

\(2014.\left|x-12\right|+\left(x-12\right)=2013.\left|x-12\right|\)

\(\Rightarrow\left|x-12\right|=-\left(x-12\right)^2\Rightarrow\hept{\begin{cases}x-12=0\\-\left(x-12\right)=0\end{cases}\Rightarrow x=12}\)

p/s: làm tắt =) ko hiểu ib vs mk

Ta có:

1/2+1/4+1/8+1/16+1/32=31/32

Vì có 5 tổng=> ta gọi phần còn lại là 5X

=>5X+31/32=2

=>5X+31/32=64/32

=>5X=64-32-31/32

=>5X=33/32

=>X=33/32:5

=>X=33/160

  64/32 chứ không phải là 64-32 đâu nha