\(\frac{4}{5}.x-x-\frac{3}{2}.x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)đề nảy hả

\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\) 

\(-\frac{1}{5}x-\frac{3}{2}x=-\frac{5}{6}-\frac{5}{6}\) 

\(-\frac{17}{10}x=-\frac{10}{6}\) 

\(x=\frac{50}{51}\)         

Bài làm:

Ta có: \(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)

\(\Leftrightarrow-\frac{17}{10}x=-\frac{5}{3}\)

\(\Rightarrow x=\frac{50}{51}\)

1) \(A=36x^2+12x+1=\left(6x+1\right)^2\ge0\)

\(minA=0\Leftrightarrow x=-\dfrac{1}{6}\)

2) \(B=9x^2+6x+1=\left(3x+1\right)^2\ge0\)

\(minB=0\Leftrightarrow x=-\dfrac{1}{3}\)

4) \(D=x^2-4x+y^2-8y+6=\left(x-2\right)^2+\left(y-4\right)^2-14\ge-14\) 

\(minD=-14\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=4\end{matrix}\right.\)

3) \(C=\left(x+1\right)\left(x-2\right)\left(x-3\right)\left(x-6\right)=\left(x^2-5x-6\right)\left(x^2-5x+6\right)=\left(x^2-5x\right)^2-36\ge-36\)

\(minC\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

5) \(E=\left(x-8\right)^2+\left(x+7\right)^2=2x^2-2x+113=2\left(x-\dfrac{1}{2}\right)^2+\dfrac{225}{2}\ge\dfrac{225}{2}\)

\(minE=\dfrac{225}{2}\Leftrightarrow x=\dfrac{1}{2}\)

e: Ta có: \(E=\left(x-8\right)^2+\left(x+7\right)^2\)

\(=x^2-16x+64+x^2+14x+49\)

\(=2x^2-2x+113\)

\(=2\left(x^2-x+\dfrac{113}{2}\right)\)

\(=2\left(x^2-2\cdot x\cdot\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{225}{4}\right)\)

\(=2\left(x-\dfrac{1}{2}\right)^2+\dfrac{225}{2}\ge\dfrac{225}{2}\forall x\)

Dấu '=' xảy ra khi \(x=\dfrac{1}{2}\)

\(\left(x+2\right)\left(2y+1\right)=2xy+x+4y+2\)

( x- 1/2) ²= 4

( x- 1/2) ²= 2²

=> x- 1/2 =2

     x         = 2+1/2

     x         = 5/2

Answer:

\(\left(x-\dfrac{1}{2}\right)^2=4\)

\(\left(x-\dfrac{1}{2}\right)^2=\left(\pm2\right)^2\)

TH1:  \(\left(x-\dfrac{1}{2}\right)^2=2^2\)

             \(x-\dfrac{1}{2}=2\)

             \(x=2+\dfrac{1}{2}\)

             \(x=\dfrac{5}{2}\)

TH2:  \(\left(x-\dfrac{1}{2}\right)^2=\left(-2\right)^2\)

             \(x-\dfrac{1}{2}=-2\)

             \(x=-2+\dfrac{1}{2}\)

             \(x=\dfrac{-3}{2}\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{-3}{2}\end{matrix}\right.\)

1) Thay x = -8 , ta có ;

(-8) - 2 x (-8) - 3 x (-8) - 4 x (-8 ) - 5 x (-8) = 104

2) Thay x = -8 , ta có ;

(-8 + 1)-2(-8 + 1)-3( -8 + 1 )- 4( -8 + 1 ) - 5( -8 + 1 ) =91

Đúng thì tick ko đúng thì thôi 

có ai ko giúp mình với

2^x(1/2+4)=288

=>2^x.9/2=288

=>2^x=64

=> x=6

WTH?? Toi giải cho rồi mà?