Ai lam minh tik cho nha
Tinh gia tri bieu thuc sau :
B = (1-1-2)×(1-1/3)×(1-1/4)×(1-1/5)...... (1-1/2003)×(1-1/2004
tinh gia tri bieu thuc
B = ( 1- 1/2) x ( 1 - 1/3 ) x ( 1 - 1/4) x ( 1 - 1/5 ) ......... ( 1 - 1/2003) x ( 1 - 1/ 2004)
/ LÀ PHÂN SỐ NHÉ
B= (1-1/2)* (1-1/3)*...............(1-1/2004)
= 1/2*2/3*........* 2003/2004
=(1*2*3*...*2003)/(2*3*4*...*2004)
= 1/2004
k cho mình nha
tinh gia tri bieu thuc:
m=1/1+2+1/1+2+3+1/1+2+3+4+1/1+2+3+4+5=....
Giúp mình voi minh can gap lam cac ban oi
1+2+1+2+3+1+2+3+4+1+2+3+4+5
=(1+2)x4+3x3+4x2+5
=3x4+9+8+5
=12+9+8+5
=34
tinh gia tri cua bieu thuc B={1(1/5).[4.(3+1/3-3/7-3/53)]/[3+1/3-3/7-3/53]}:{[4+4/17+4/19+4/2003]/5+5/17+519+5/2003]}
cho bieu thuc a=-1/3+1/3^2-1/3^3+1/3^4-1/3^5+...+1/3^100 tinh gia tri cua bieu thuc b=4/a/+1/3^100
bai nay lam sao hon so nha tinh gia tri bieu thiuc 3/4 + 2 1/5 * 3 3/4 cau hai 11/4 - 2 1/5 chia 3 3/4 giup mk nha mk ko bit lam nan ni nhanh k tik cho
Tinh gia tri cua bieu thuc \(D=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}\)
Nho giai va tring bay cach lam cho minh luon nha ^_^
tinh gia tri bieu thuc
A = \(3+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}}\)
\(B=-5+\frac{1}{1-\frac{1}{2+\frac{1}{1-\frac{1}{4}}}}\)
Ai làm nhanh nhat minh tk cho
\(A=3+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{4}{3}}}}=3+\frac{1}{1+\frac{1}{1+\frac{3}{4}}}\)
\(=3+\frac{1}{1+\frac{1}{\frac{7}{4}}}=3+\frac{1}{1+\frac{4}{7}}=3+\frac{1}{\frac{11}{4}}=3+\frac{4}{11}=\frac{37}{11}\)
\(B=-5+\frac{1}{1-\frac{1}{2+\frac{1}{\frac{3}{4}}}}=-5+\frac{1}{1-\frac{1}{2+\frac{4}{3}}}\)
\(=-5+\frac{1}{1-\frac{1}{\frac{10}{3}}}=-5+\frac{1}{1-\frac{3}{10}}=-5+\frac{1}{\frac{7}{10}}=-5+\frac{10}{7}=\frac{-25}{7}\)
cho x+y =1 . tinh gia tri cua bieu thuc A=x^3+y^3+3xy
chox-y=1. tinh gia tri cua bieu thuc B=x^3-y^3-3xy
cho x+y=1 . tinh gia tri cua bieu thuc C=x^3+y^3+3xy(x^2+y^2)+6x^2*y^2(x+y)
Câu 1: Ta có: A = \(x^3+y^3+3xy=x^3+y^3+3xy\times1=x^3+y^3+3xy\left(x+y\right)\)
\(=\left(x+y\right)^3=1^3=1\)
Câu 2: Ta có: \(B=x^3-y^3-3xy=\left(x-y\right)\left(x^2+xy+y^2\right)-3xy\)
\(=x^2+xy+y^2-3xy=x^2-2xy+y^2=\left(x-y\right)^2=1^2=1\)
Câu 3: Ta có: \(C=x^3+y^3+3xy\left(x^2+y^2\right)-6x^2.y^2\left(x+y\right)\)
\(=x^3+y^3+3xy\left(x^2+2xy+y^2-2xy\right)+6x^2y^2\)
\(=x^3+y^3+3xy\left(x+y\right)^2-3xy.2xy+6x^2y^2\)
\(=x^3+y^3+3xy.1-6x^2y^2+6x^2y^3\)
\(=x^3+y^3+3xy\left(x+y\right)=\left(x+y\right)^3=1^3=1\)
cho x2+2xy +x+y+1=5.
gia tri cua bieu thuc m= 2(x+1)(y+1)-x(1-x)-y la :...
lam giup minh nha may ban
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