a) x = 2

b) x = 7.

c) x = 12

d) x = 45

e) x = 18.

f) x  = 10

a) x = 2.               

b) x = 7.

c) x= 12.

d)  x= 45.

e) x = 18.

f) x  = 10.

`a, (4x+5) : 3 -121:11=14`

`=> (4x+5) : 3 - 11=14`

`=> (4x+5) : 3 =14+11`

`=> (4x+5) : 3 = 25`

`=> 4x+5=25xx3`

`=>4x+5= 75`

`=> 4x=75-5`

`=>4x=70`

`=>x= 70/4`

`=>x= 35/2`

`b, 2+4+6+...+x=2450`

Số lượng của dãy là :

`(x-2)/2 + 1= (x-2)/2 +2/2= x/2`

Tổng số lượng là :

\(\dfrac{\left(x+2\right)\cdot\dfrac{x}{2}}{2}=\dfrac{\dfrac{x^2}{2}+\dfrac{2x}{2}}{2}=\dfrac{x\left(x+2\right)}{4}\)

\(\dfrac{x\left(x+2\right)}{4}=2450\)

\(\Rightarrow x\left(x+2\right)=2450\cdot4\\ \Rightarrow x\left(x+2\right)=9800\)

`=>x=98`

`c,` `1` nhân `32` sao?

`d, 2x+3x=1505`

`=> (2+3)x=1505`

`=> 5x=1505`

`=> x= 1505:5`

`=>x= 301`

x:34=200-32

x:34=268

x=134/17

x : 34 = 200 - 32

x : 34 = 168

     x   = 168 x 34

     x   = 5712

x:34=178

x= 178* 34

x= 6052

1)\(\left(x-280\right):35=56.5\)

\(\left(x-280\right):35=280\)

\(x-280=280.35\)

\(x-280=9800\)

\(x=9800+280\)

\(x=10080\)

2) \(\left(x-128+20\right):192=0\)

\(\Rightarrow\left(x-148\right):192=0\)

\(\Rightarrow x-148=0\)

\(\Rightarrow x=0+148\)

\(\Rightarrow x=148\)

3) \(460+85.4=\left(x+200\right).4\)

\(\Rightarrow\left(x+200\right).4=460+340\)

\(\Rightarrow\left(x+200\right).4=800\)

\(\Rightarrow x+200=800:4=200\)

\(\Rightarrow x+200=200\)

\(\Rightarrow x=200-200=0\)

4) \(x+5.2-\left(32+16.3:16-15\right)=0\)

\(\Rightarrow x+10-\left(32+3-15\right)=0\)

\(\Rightarrow x+10-20=0\)

\(\Rightarrow x+10=20\)

\(\Rightarrow x=20-10=10\)

nha m.n

\(a,\Rightarrow x+35=103\\ \Rightarrow x=68\\ b,\Rightarrow x+7=42\\ \Rightarrow x=35\\ c,\Rightarrow x-15=9\\ \Rightarrow x=24\\ d,\Rightarrow x+23=31\\ \Rightarrow x=8\\ e,\Rightarrow18-x=6\\ \Rightarrow x=12\\ f,\Rightarrow x+14=34\\ \Rightarrow x=20\\ g,\Rightarrow2x+1=21\\ \Rightarrow x=11\\ h,\Rightarrow3\left(x+1\right)=99\\ \Rightarrow x+1=33\Rightarrow x=32\\ i,5\left(x-3\right)=25\\ \Rightarrow x-3=5\\ \Rightarrow x=8\\ j,\Rightarrow8\left(2x+7\right)=88\\ \Rightarrow2x+7=11\Rightarrow x=2\\ k,\Rightarrow5\left(x+4\right)=85\\ \Rightarrow x+4=17\\ \Rightarrow x=13\)

a) Ta có \(0,625^{200}=\left(\dfrac{5}{8}\right)^{200}\) và \(0,5^{1000}=\left(\dfrac{1}{2}\right)^{1000}=\left(\dfrac{1}{2}\right)^{5.200}\) \(=\left[\left(\dfrac{1}{2}\right)^5\right]^{200}\) \(=\left(\dfrac{1}{32}\right)^{200}\). Mà hiển nhiên \(\left(\dfrac{5}{8}\right)^{200}>\left(\dfrac{1}{32}\right)^{200}\) nên suy ra \(0,625^{200}>0,5^{1000}\)

b) Ta thấy \(\left(-32\right)^{27}< 0\) trong khi \(\left(-27\right)^{32}>0\) nên đương nhiên \(\left(-32\right)^{27}< \left(-27\right)^{32}\)

c) Ta thấy \(-\dfrac{3}{2}>-2\) nên \(\left(-\dfrac{3}{2}\right)^5>\left(-2\right)^5\)

a) \(\frac{47}{32}>\frac{36}{46}\)Vì phân số \(\frac{47}{32}>1;\frac{36}{46}< 1\)nên \(\frac{47}{32}>\frac{36}{46}\)

b) \(\frac{199}{200}< \frac{200}{201}\)Vì \(\frac{199}{200}=\frac{199.201}{200.201};\frac{200}{201}=\frac{200.200}{201.200}\)

ta so sánh 199.201 và 200.200 

199.201 = 199.(200+1) = 199.200+199

200.200 = 200.(199+1) = 200.199+200

Vì 199.200 + 199 < 200.199+200 nên \(\frac{199}{200}< \frac{200}{201}\)

c) \(\frac{2012.2010}{2011.2011}=\frac{\left(2011+1\right).2010}{2011.\left(2010+1\right)}=\frac{2011.2010+2010}{2011.2010+2011}\)

\(\frac{2013.2009}{2014.2008}=\frac{2013.\left(2008+1\right)}{\left(2013+1\right).2008}=\frac{2013.2008+2013}{2013.2008+2008}\)

ta so sánh : \(\frac{2010}{2011}< \frac{2013}{2008}\) vì \(\frac{2010}{2011}< 1;\frac{2013}{2008}>1\)