( Dấu chấm như . là nhân nhé ! )
A,
E = 1/3 + 1/6 + 1/10 + ........+ 1/55
B,
F = 2/1.3 + 2/3.5 + 2/5.7 +.........+ 3/13.15
C,
G = 3/1.3 + 3/3.5 + +3/5.7 + ..............+ 1/17.21
Câu 1 : B = 1/3 + 1/6 + 1/10 + ... + 1/45
Câu 2 : D = 3/1.3 + 3/3.5 + 3/5.7 + ... + 3/99.101
Câu 3 : E= 4/1.3 + 4/3.5 + 5/5.7 + ... + 4/205.207
Câu 4 : F= 1/1.4 + 1/4.7 + 1/10 + ...
- tổng này có 54 số hạng
Câu 5 : G= 1/5 + 1/45 + 1/117 + 1/221
- tổng này có 54 số hạng
Câu 2:
\(D=\dfrac{3}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\)
\(=\dfrac{3}{2}\cdot\dfrac{100}{101}=\dfrac{150}{101}\)
Câu 3:
\(E=2\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{205}-\dfrac{1}{207}\right)\)
\(=2\cdot\left(1-\dfrac{1}{207}\right)=2\cdot\dfrac{206}{207}=\dfrac{412}{207}\)
Câu 5:
\(G=\dfrac{1}{4}\left(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{17}\right)\)
\(=\dfrac{1}{4}\cdot\dfrac{16}{17}=\dfrac{4}{17}\)
Câu 1 : B = 1/3 + 1/6 + 1/10 + ... + 1/45
Câu 2 : D = 3/1.3 + 3/3.5 + 3/5.7 + ... + 3/99.101
Câu 3 : E= 4/1.3 + 4/3.5 + 5/5.7 + ... + 4/205.207
Câu 4 : F= 1/1.4 + 1/4.7 + 1/10 + ...
- tổng này có 54 số hạng
Câu 5 : G= 1/5 + 1/45 + 1/117 + 1/221
- tổng này có 54 số hạng
các bạn giải hộ mình nhé mình sẽ ủng hộ
mình sẽ ủng hộ bạn có câu trả lời đúng nhất nhé
Tính các tổng sau
1 :D = 1.3 +2.3+3.4+........+99.100
2 . E= 1.3 +3.5+5.7+.........+97.99
3.F= 2.4 + 4.6+ 6+8+..........+98.1009
4. G=1.4+2.5+3.6+........+97.100
Giúp mình nhé . Mình cần gấp
Câu a ,
E = 1/3 + 1/6 + 1/10 + ........ + 1/55
Câu B ,
F = 2/1.3 + 2/3.5 + 2/5.7 +.... + 2/13.15
F=1-1/3+1/3-1/5+1/5-1/7+......+1/13-1/15
F=1-1/15
F=14/15
t mink nha
a) \(E=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{55}\)
\(E=\frac{1}{1.3}+\frac{1}{2.3}+\frac{1}{2.5}+...+\frac{1}{55}\)
\(\frac{1}{2}E=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{10.11}\)
\(\frac{1}{2}E=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\)
\(\frac{1}{2}E=\frac{1}{2}-\frac{1}{11}\)
\(\frac{1}{2}E=\frac{9}{22}\Leftrightarrow E=\frac{9}{22}.2=\frac{9}{11}\)
b) \(F=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(F=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(F=\frac{1}{1}-\frac{1}{15}=\frac{14}{15}\)
\(E=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+..+\frac{1}{55}\)
\(E=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{110}\)
\(E=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+..+\frac{2}{10.11}\)
\(E=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)
\(E=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)
\(E=2.\frac{9}{22}=\frac{9}{11}\)
\(F=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(F=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}\)
\(F=\frac{1}{1}-\frac{1}{15}=\frac{14}{15}\)
Tính
A= 512 - 512/2 - 512/2^2 - 512/2^3 - ....- 512/210
E= 1 - 1/10 - 1/15 - 1/3 - 1/28 - 1/6 - 1/21
C= 11/1.3 + 47/3.5 + 107/5.7 + 191/7.9 +...+ 971/17.19
sai bet thang ngu nhu cho
( 1/1.3+1/3.5+1/5.7+1/7.9+1/9.11). X = 2/3
\(\text{Ta có:}\) \(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).x=\frac{2}{3}\)
\(\Leftrightarrow2.\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).x=\frac{2}{3}.2\)
\(\Leftrightarrow\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).x=\frac{4}{3}\)
\(\Leftrightarrow\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+.....+\frac{1}{9}-\frac{1}{11}\right).x=\frac{4}{3}\)
\(\Leftrightarrow\left(1-\frac{1}{11}\right)x=\frac{4}{3}\)
\(\Leftrightarrow\frac{10}{11}x=\frac{4}{3}\)
\(\Leftrightarrow x=\frac{4}{3}:\frac{10}{11}=\frac{22}{15}\)
Tìm y : ( 1/1.3 + 1/3.5 + 1/5.7 + 1/7.9 + 1/9.11 ) .y = 2/3.
( \(\frac{1}{1x3}\)+ \(\frac{1}{3x5}\)+....+\(\frac{1}{9x11}\)) x \(y\) = \(\frac{2}{3}\)
( \(\frac{2}{1x3}\)+ \(\frac{2}{3x5}\)+...+\(\frac{2}{9x11}\)) x \(y\) = \(\frac{4}{3}\) (nhân 2 vế lên với 2)
(1 - \(\frac{1}{3}\)+\(\frac{1}{3}\)-\(\frac{1}{5}\)+\(\frac{1}{5}\)- ...+ \(\frac{1}{9}\)- \(\frac{1}{11}\)) x \(y\)= \(\frac{4}{3}\)
( 1 - \(\frac{1}{11}\)) x \(y\)=\(\frac{4}{3}\)
\(\frac{10}{11}\) x \(y\) =\(\frac{4}{3}\)
\(y\) = \(\frac{4}{3}\): \(\frac{10}{11}\)
\(y\) = \(\frac{4}{3}\)x \(\frac{11}{10}\)
\(y\) =\(\frac{22}{15}\)
kết quả đúng nhưng mình ko hiểu bạn có thể giáng lại ko ?
tìm y
[ 1/1.3+1/3.5+1/5.7+1/7.9 ] . y = 2/3
\(\left[\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}\right].y=\frac{2}{3}\)
\(\Leftrightarrow\left[\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}\right].y=\frac{2}{3}\)
\(\Leftrightarrow\left[\frac{1}{1}-\frac{1}{9}\right].y=\frac{2}{3}\)
\(\Leftrightarrow\frac{8}{9}.y=\frac{2}{3}\)
\(\Leftrightarrow y=\frac{2}{3}:\frac{8}{9}\)
\(\Leftrightarrow y=\frac{3}{4}\)
Tính tổng :
B= 1/1.5+1/5.9+1/9.13+...+1/93.97
C= 3/1.3+3/3.5+3/5.7+...+3/97.99
D= 1/10+1/15+1/20+...+1/120
E= 2/15+2/35+2/63+...+2/399
Ai nhanh mk tick làm nhanh nhé mk cần gấp lắm
\(4.B=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{93.97}\)
\(4.B=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{93}-\frac{1}{97}\)
\(4.B=1-\frac{1}{97}\)
\(4.B=\frac{96}{97}\)
\(B=\frac{96}{97}:4\)
\(B=\frac{24}{97}\)