Tìm x :x-125=412
Bài 1: a,315+2x=x+115 b,25-(30-x)=25-(-12+125) c,412-(40-2x)=72+x
a) 315 + 2x = x+115
<=> 2x-x = 115-315
<=> x = -200
Vậy x= -200
b) 25-(30-x)=25-(-12+125)
<=> 25-30+x = -88
<=> -5 + x =-88
<=> x = -83
Vậy x=-83
c) 412-(40-2x) = 72+x
<=> 412-40+2x=72+x
<=> 372 + 2x = 72+x
<=> 2x-x = 72-372
<=> x= -300
Vậy x=-300
Tim x biet: ( 315 + 2x ) - ( 125+ x) = 412
=> 315+2x-125-x=412
315+2x-125-x=412
315+2x+(-125)+(-x)=412
315+(-125)+2x+(-x)=412
190+2x+(-x)=412
x=412-190
x=222
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Tìm x, biết:
a) 4 1 2 − x = − 3 2 3
b) x − 2 2 3 = 3 1 3
a ) 4 1 2 − x = − 3 2 3 ⇒ x = 4 1 2 + 3 2 3 = 9 2 + 11 3 = 8 1 6 .
b ) x − 2 2 3 = 3 1 3 ⇒ x = 2 2 3 + 3 1 3 = 6
Tìm số nguyên x thỏa mãn:
a ) x 7 = x + 1 14 ; b ) 2 x + 5 3 = − 4 12 ;
Tìm x, biết
a) 2 4 5 + 50 : 2 3 x = − 51
b) 4 1 2 − 2 x .1 4 61 = 6 1 2
15 x ( 212121/434343 + 333333/353535)
639 x 721721/ 721 x 639639
327 x 412 + 400 / 328 - 412 -12
\(a)15.\left(\dfrac{212121}{434343}+\dfrac{333333}{353535}\right)\)
\(=15.\left(\dfrac{21}{43}+\dfrac{33}{35}\right)\)
\(=15.\dfrac{2154}{1505}\)
\(=\dfrac{6462}{301}\)
Tìm x:
a) x – 125 = 344
b) x + 125 = 266
x = 344 + 125
x = 469
b) x + 125 = 266
x = 266 - 125
x = 141
1: Tính
a) B = 2016 x 2016 - 2014 x 2018
b) 327 x 412 + 400 / 328 x 412 -12
c) ( 1234 x 567 - 667 ) : ( 567 + 1234 x 5
1 a/ B = 2016 . 2016 - 2014 . 2018
=\(2016^2-\left(2016-2\right).\left(2016+2\right)\)
= \(2016^2-2016.\left(-2+2\right)\\\)
=\(2016^2-2016.0 \)
= \(2016^2\)
1: Tính
a) B = 2016 x 2016 - 2014 x 2018
= (2016 x 2016) - (2014 x 2018)
= 4064256 - 4064252
= 4
b) 327 x 412 + 400 / 328 x 412 -12
= (327 x 412 + 400) / ( 328 x 412 - 12)
= 135124 / 135124
= 1
c) ( 1234 x 567 - 667 ) : ( 567 + 1234 x 5)
= (1234 x 567 - 667) : (567 + 1234 x 566)
= [1234 x 566 + (1234 - 667)] / (1234 x 566 + 567)
= (1234 x 566 + 567) / (1234 x 566 + 567)
= 1
để thiếu bạn ơi
125-(30+x+125)=(x-237)-(8-237) tìm x
125-30-x-125=x-237-8+237
-30-x=x-8
=> -30=2x-8
=> x=-11