tìm x
A) (\(\chi\)x 0,25 + 1999) x 2000= (53+ 1999) x 2000
b) 71 + 65 x 4=\(\frac{\chi+140}{\chi}\)+ 260.
Ai biết làm thì giúp mik nhé
Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
tìm x
( x * 0,25 + 1999 ) * 2000 = ( 53 + 1999 ) * 2000
71 + 65 * 4 = \(\frac{x+140}{x}\) + 260
( X x 0,25+ 1999) x2000= ( 53+1999) x2000
( X x 0,25+ 1999) = ( 53+1999)x2000:2000
( X x 0,25+1999) =( 53+1999)
( X x 0,25+1999) = 2052
X+0,25 = 2052 - 1999
X+ 0,25 = 53
X = 53:0,25
X = 212
71+65 x4 = x+140/x + 260
x+140/x + 260= 71+65x4
x+140/x + 260=71 + 260
x+140/x=71
x/x +140/x=71
1+ 140/x=71
140/x=71-1
140/x=70
x=140/70
x=2
k nha linh
1 tìm x
a , ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10) + ..........+ ( x + 28 ) = 155
b, ( x x 0,25 + 1999 ) x 2000 = ( 53 + 1999 ) x 2000
c, 71 + 65 x 4 = \(\frac{x+140}{x}\)x 260
( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10) + ..........+ ( x + 28 ) = 155
10x + ( 1 + 4 + 7 + ... + 28 ) = 155
10x + 145 = 155
10x = 155 - 145
10x = 10
x = 10 : 10
Vậy x = 1
\(a,\left[x+1\right]+\left[x+4\right]+\left[x+7\right]+\left[x+10\right]+...+\left[x+28\right]=155\)
\(\Leftrightarrow x+1+x+4+x+7+x+10+...+x+28=155\)
\(\Leftrightarrow(x+x+x+...+x)+(1+4+7+...+28)=155\)
\(\Leftrightarrow10x+145=155\)
\(\Leftrightarrow10x=155-145\)
\(\Leftrightarrow10x=10\)
\(\Leftrightarrow x=1\)
\(b)(x\times0,25+1999)\times2000=(53+1999)\times2000\)
\(\Leftrightarrow(x\times0,25+1999)\times2000=4104000\)
\(\Leftrightarrow(x\times0,25+1999)=4104000:2000\)
\(\Leftrightarrow(x\times0,25+1999)=2052\)
\(\Leftrightarrow x\times0,25=2052-1999\)
\(\Leftrightarrow x\times0,25=53\)
\(\Leftrightarrow x=53:0,25=212\)
Câu c tự làm
tim x
a, ( x 0,25+1999).2000=(53+1999).2000
b, 71+65.4=x+140/x+260
a, ( x . 0,25+1999).2000=(53+1999).2000
=> 500x + 1999 . 2000 = 53 . 2000 + 1999 . 2000
=> 500x = 53 . 2000 + 1999 . 2000 - 1999 .2000
=> 500x = 53 . 2000
=> x = 53 . 2000 : 500
=> x = 53 . 4
=> x = 212
Tìm x :
a) \(\times.\left(0,25+1999\right).2000=\left(53.1999\right).2000\)
b) 71 + 65 x 4 = \(\frac{x+140}{x}+260\)
Tìm x :
a, x x1999=1999x199,8
b,[x x 0,25 +1999]x2000 =[53+1999]x2000
c,71 + 65x4=\(\frac{x+140}{x}\)+260
Bài 1:tìm x:
a) x+5*2-(32+16*3*6-15)= 0
b) (x*0,25+1999)*2000= (53+1999)*2000
c)x*2016=x:2016
d) (x+2)+(x+3)+.....................+ (x+100)= 5750-(x-1)
e) x+x:1/3:2/9+x:2/7= 252
g) 71+65*4=\(\frac{x+140}{x}\) + 260
h) x:0,1: 0,2: 0,3 :0,4 : 0,5 : 0,6 = 100000
Tìm \(x\):
a) ( \(x\)+ 1 ) + ( \(x\)+ 4 ) + ( \(x\)+ 7 ) + ( \(x\)+ 10 ) + .......+ ( \(x\)+ 28 ) = 155
b) ( \(x\)x 0,25 + 1999 ) x 2000 = ( 53 + 1999 ) x 2000
c) 71+ 65 x 4 = \(x\)+ \(\frac{140}{x}\)+ 260
AI LÀM NHANH , ĐẦY ĐỦ MK SẼ TICK NHÓE !!!!!
a) ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ... + ( x + 28 ) = 155
\(\Rightarrow\)( x + x + x + ... + x ) + ( 1 + 4 + 7 + 10 + ... + 28 ) = 155
\(\Rightarrow\)x10 + ( SSH: ( 28 - 1 ) : 3 + 1 = 10 ) = 155
\(\Rightarrow\)x10 + ( Tổng: ( 1 + 28 ) . 10 : 2 = 145 ) = 155
\(\Rightarrow\)x10 + 145 = 155
\(\Rightarrow\)x10 = 155 - 145 = 10
\(\Rightarrow\)x = 10 : 10 = 1
vậy x = 1
b) ( x . 0,25 + 1999 ) . 2000 = ( 53 + 1999 ) .2000
\(\Rightarrow\)500x + 3998000 = 106000 + 3998000
\(\Rightarrow\)500x + 3998000 = 4104000
\(\Rightarrow\)500x = 4104000 - 3998000 = 106000
\(\Rightarrow\)x = 106000 : 500 = 212
giải chi tiết giúp mình mình cảm ơn
\(71+65\cdot4=\frac{x+140}{x}+260\)
Ta có \(71+65\times4=\frac{x+140}{x}+26\)
\(\Rightarrow71+260=\frac{x+140}{x}+260\)
\(\Rightarrow\frac{x+140}{x}=71\)( triệt tiêu hai vế đi 260 )
\(\Rightarrow x+140=71x\)
\(\Rightarrow70x=140\)
\(\Rightarrow x=2\)
Vậy x = 2
\(71+65.4=\frac{x+140}{x}\)\(+260\)
\(71+260=\frac{x+140}{x}+260\)
=>\(\left(x+140\right):x=71\)
=>\(x+140=71x\)
=>\(71x-x=140\)
=>\(70x=140\)
=>\(x=140:70\)
=>\(x=2\)
Vậy x = 2
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