`@` `\text {Ans}`

`\downarrow`

`2^x = 16`

`=> 2^x = 2^4`

`=> x = 4`

Vậy, `x = 4.`

____

`2^x*16 = 1024`

`=> 2^x =`\(2^{10}\div2^4\)

`=> 2^x = 2^6`

`=> x = 6`

Vậy, `x = 6`

______

`2^x - 26 = 6`

`=> 2^x = 6 + 26`

`=> 2^x = 32`

`=> 2^x = 2^5`

`=> x = 5`

Vậy, `x = 5`

`3^x*3 = 243`

`=> 3^x * 3 = 3^5`

`=> 3^x = 3^5 \div 3`

`=> 3^x = 3^4`

`=> x = 4`

Vậy, `x = 4.`

a) 2x(x - 5) - x(2x + 3) = 26

⇒ 2x² - 10x - 2x² - 3x = 26

⇒ -13x = 26

⇒ x = -2

chúc bạn học tốt 

a) \(\frac{-x}{2}+\frac{2x}{3}+x+\frac{1}{4}+2x+\frac{1}{6}=\frac{3}{8}.\)

\(\frac{-x}{2}+\frac{2x}{3}+3x+\frac{5}{12}=\frac{3}{8}\)

\(x.\left(-\frac{1}{2}+\frac{2}{3}+3\right)+\frac{5}{12}=\frac{3}{8}\)

\(x\cdot\frac{19}{6}=-\frac{1}{24}\)

x = -1/76

b) \(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)

\(\frac{3}{2x+1}+\frac{2.5}{2.\left(2x+1\right)}-\frac{2.3}{3.\left(2x+1\right)}=\frac{6}{13}\)

\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)

\(\frac{3+5-2}{2x+1}=\frac{6}{13}\)

\(\frac{6}{2x+1}=\frac{6}{13}\)

=> 2x + 1 = 13

2x = 12

x = 6

Ta có: 2x(x – 5) – x(3 + 2x) = 26

      ⇔ 2 x 2  – 10x – 3x – 2 x 2  =26

      ⇔ - 13x = 26

      ⇔ x = - 2

Ta có: 2x(x – 5) – x(3 + 2x) = 26

      ⇔ 2x2 – 10x – 3x – 2x2 =26

      ⇔ - 13x = 26

      ⇔ x = - 2

\(2x\left(x-5\right)-x\left(3+2x\right)=26\)

\(\Leftrightarrow2x^2-10x-3x-2x^2=26\)

\(\Leftrightarrow-13x=26\)

\(\Leftrightarrow x=-2\)

Bài làm:

Ta có: \(2x\left(x-5\right)-x\left(3+2x\right)=26\)

\(\Leftrightarrow2x^2-10x-3x-2x^2-26=0\)

\(\Leftrightarrow-13x=26\)

\(\Rightarrow x=-2\)

2x( x - 5 ) - x( 3 + 2x ) = 26

<=> 2x² - 10x - 3x - 2x² = 26

<=> -13x = 26

<=> x = -2

2x(x-5) - x(3+2x) = 26

<=> 2x^2 -  10x - 3x - 2x^2 = 26

<=> -13x=26

<=> x = -2

2x(x-5) - x (3+2x) = 26 

=> 2x² - 10x - 3x - 2x² = 26

=> (2x² - 2x²) + (-10x - 3x) = 26

=>  -13x = 26

=> x = 26 : (-13) 

=> x = -2

2x(x-5)-x(3+2x)= 26

2x²-10x-3x-2x²= 26

            -13x        = 26

                  x        = -2