#include <bits/stdc++.h>
using namespace std;
long long n,a[1000001];
int main()
{
    cin>>n;
    for(int i=1;i<=n*2;i++)
    {
        cin>>a[i];

    }
    sort(a+1,a+n+1);
    sort(a+n+1,a+2*n+1,greater<long long>());
    for(int i=1;i<=n*2;i++)
    {
        cout<<a[i]<<" ";
    }
    return 0;
}

a. \(2^2.2^3.2^{15}=2^{20}\)

\(3^{24}.3^{14}=3^{38}\)

\(c.5^{16}.5^9=5^{25}\)

\(d.3^{12}.3^{15}=3^{27}\)

a: \(\dfrac{-8}{3}\cdot\dfrac{15}{24}=\dfrac{-8}{24}\cdot\dfrac{15}{3}=\dfrac{-1}{3}\cdot5=-\dfrac{5}{3}\)

b: \(=\dfrac{3}{4}\cdot\dfrac{1}{-9}=\dfrac{-1}{12}\)

c: \(x=-\dfrac{7}{6}+\dfrac{5}{8}=-\dfrac{13}{24}\)

d: \(x=-\dfrac{14}{25}-\dfrac{3}{4}=\dfrac{-56-75}{100}=\dfrac{-131}{100}\)

\(a)\frac{2}{5}+\frac{3}{10}-\frac{1}{2}\)

\(=\frac{4}{10}+\frac{3}{10}-\frac{5}{10}=\frac{1}{5}\)

\(b)\frac{8}{11}+\frac{8}{33}.\frac{3}{4}\)

\(=\frac{8}{11}+\frac{2}{11}=\frac{10}{11}\)

\(c)\frac{7}{9}.\frac{3}{14}:\frac{5}{8}\)

\(=\frac{1}{6}:\frac{5}{8}=\frac{4}{15}\)

\(d)\frac{5}{12}-\frac{7}{32}:\frac{21}{16}\)

\(=\frac{5}{12}-\frac{1}{6}=\frac{5}{12}-\frac{2}{12}=\frac{1}{4}\)

2/5 + 3/10 - 1/2

= 4/10 + 3/10 -5/10

=2/10

=1/5.

8/11 + 8/33 *3/4

=8/11 + 2/11

=10/11

7/9 *3/14 : 5/8

=1/3 *1/2 : 5/8

=1/6: 5/8

=1/3 * 4/5

=4/15

5/12 - 7/32 : 21/16

=5/12 - 1/6

=5/12 - 2/12

=1/4

B=4/9(1/3+2/3)+14/9=4/9+14/9=2/1

B = 2/1 = 2

B=4/9(1/3+2/3)+14/9

B=4/9+14/9

B=2/1

wow! mù mắt. Ido tính toán có khác!

C2:(32+1)x32:2=528

bạn tính thử xem đúng đấy.

wowwowwow

a: =>x=-7/6+5/8=-13/24

b: =>x=-14/25-3/4=-131/100

c: \(x=\dfrac{-33}{26}:\dfrac{-9}{13}=\dfrac{33}{26}\cdot\dfrac{13}{9}=\dfrac{11}{3}\cdot\dfrac{1}{2}=\dfrac{11}{6}\)

d: \(x=\dfrac{4}{9}:\dfrac{5}{3}=\dfrac{4}{9}\cdot\dfrac{3}{5}=\dfrac{12}{45}=\dfrac{4}{15}\)