\(A=\frac{\left(5^2\right)^3\cdot5^5}{6\cdot5^{10}}\)

\(A=\frac{5^{2+3}\cdot5^5}{6\cdot5^{10}}\)

\(A=\frac{5^5\cdot5^5}{6\cdot5^{10}}\)

\(A=\frac{5^{5+5}}{6\cdot5^{10}}\)

\(A=\frac{5^{10}}{6\cdot5^{10}}\)

\(\Rightarrow A=\frac{1}{6}\)

\(A=\frac{25^3.5^5}{6.5^{10}}=\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^5.5^5}{6.5^{10}}=\frac{1}{6}.\)

Bài này là bài đại trà của lp 6 bn ạ, ko phải lp 7

A = 25³.5⁵/6.5¹⁰

A = (5²)³.5⁵/6.5¹⁰

A = 5⁶.5⁵/6.5¹⁰

A = 5¹¹/6.5¹⁰

A = 5/6

\(\frac{5^3.5^8}{25^4}\)

\(=\frac{5^{11}}{25^4}\)

\(=\frac{48828125}{390625}\)

\(\frac{5^3.5^8}{25^4}=\frac{5^8.5^3}{\left(5^2\right)^4}\)

\(\Rightarrow\frac{5^8.5^3}{5^8}=5^3=125\)

Hk tốt

     5³ .5⁸ / 25⁴

= 5¹¹ / ( 5² )⁴

= 5¹¹ / 5 ⁸

= 5³

= 125

Tk cho mk nha ae!!!!!!! Ai chơi Liên quân mobile thì kb nha.

=2^12.3^4.(3-1)/2^12.3^5(3+1)-5^10.7^3.(1-7)/5^9.7^3.(1+2^3)

2/3.4-5.(-6)/9

=1/6-(-10/3)

1/6+10/3

7/2

What ???????????????

a;47.69-31(-41)

=3243-(-1271)

=4514

b,(-14)(-25)+25(-11)

=350+(-275)

=75

c,(-127).57+(-43).127

=(-7239)+(-5461)

=-12700

e,(-25).68+(-34).(-250)

=(-1700)+8500

=6800

f,(-2)^3.(-3)^2

=(-8).9

=-72

 Câu d, cậu ghi ko rõ đề nên tớ ko làm

NHỚ TICK NHA

\(A=\frac{25^3.5^5}{6.5^{10}}=\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^6.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)

\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.2^3.3^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^8.3^3}{2^6.3^4}=\frac{4}{3}\)

\(A=\frac{25^3.5^3}{6.5^{10}}=\frac{5^6.5^3}{6.5^{10}}=\frac{5^9}{6.5.5^9}=\frac{1}{30}\)
\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.2^3.3^3}{2^6.3^4}=\frac{2^8.3^3}{2^6.3^4}=\frac{2^2}{3}=\frac{4}{3}\)
\(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}=\frac{5^3\left(3^3+3^2-1\right)}{6^3\left(3^3+3^2-1\right)}=\frac{5^3}{6^3}\)

ngu dễ mà không biết làm mày là đồ con lợn

a = 4/5 nha

Dễ mà bạn

Phạm Hồng Anh k tớ nhé

a) \(\frac{6^{15}+6^{13}}{6^{12}}=\frac{6^{13}.\left(6^2+1\right)}{6^{12}}=6.37=222\)

b) \(\frac{2^6.5^7}{10^6}=\frac{2^6.5^6.5}{10^6}=\frac{10^6.5}{10^6}=5\)

a, Ta có: \(A=\frac{6^{15}+6^{13}}{6^{12}}=\frac{6^{12}\left(6^3+6\right)}{6^{12}}=6^3+6\) \(=222\)

b, Ta có: \(B=\frac{2^6.5^7}{10^6}=\frac{2^6.5^6.5}{10^6}=\frac{\left(2.5\right)^6.5}{10^6}\) \(=\frac{10^6.5}{10^6}=5\) 

a)

\(\frac{6^{15}+6^{13}}{6^{12}}\)=\(\frac{6^{12}\times\left(6^3+6\right)}{6^{12}}\)= 6³ +6=222

b)

\(\frac{2^6\times5^7}{10^6}\)=\(\frac{2^6\times5^6\times5}{10^6}\)= 5

Đúng thì k nha

\(A=\frac{125^{100}}{5^{298}}\cdot\frac{2^{160}}{4^{80}}=>A=\frac{\left(5^3\right)^{100}}{5^{298}}\cdot\frac{2^{160}}{\left(2^2\right)^{80}}\)

\(=>A=\frac{5^{300}}{5^{298}}\cdot\frac{2^{160}}{2^{160}}=>A=5^2\cdot1=>A=25\)

\(A=\frac{125^{100}}{5^{298}}.\frac{2^{160}}{4^{80}}\)

    \(=\frac{\left(5^3\right)^{100}}{5^{298}}.\frac{2^{160}}{\left(2^2\right)^{80}}\)

    \(=\frac{5^{300}}{5^{298}}.\frac{2^{160}}{2^{160}}\)

    \(=5^2.1=25\)

Vậy \(A=25\)

\(A=\frac{125^{100}}{5^{298}}.\frac{2^{160}}{4^{80}}=\frac{\left(5^3\right)^{100}}{5^{298}}.\frac{2^{160}}{\left(2^2\right)^{80}}\)

                                          \(=\frac{5^{300}}{5^{298}}.\frac{2^{160}}{2^{160}}\)

                                           \(=5^2.1\) 

                                             \(=25\)

Đặt \(A=\frac{1}{4.9}+\frac{1}{9.14}++\frac{1}{14.19}+......+\frac{1}{44.49}\)

\(A=\frac{1}{5}.\left(\frac{5}{4.9}+\frac{5}{9.14}+\frac{5}{14.19}+.....+\frac{5}{44.49}\right)\)

\(A=\frac{1}{5}.\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+\frac{1}{14}-\frac{1}{19}+.....+\frac{1}{44}-\frac{1}{49}\right)\)

\(A=\frac{1}{5}.\left(\frac{1}{4}-\frac{1}{49}\right)=\frac{1}{5}.\frac{45}{196}=\frac{9}{196}\)

Đặt \(B=\frac{1-3-5-7-.......47-49}{89}\)

\(B=\frac{1-\left(3+5+7+......+47+49\right)}{89}\)

Từ 3 -> 49 có: (49-3):2+1=24(số hạng)

=>\(3+5+7+....+47+49=\frac{\left(49+3\right).24}{2}=624\)

=>\(B=\frac{1-624}{89}=\frac{-623}{89}=-7\)

Vậy \(\left(\frac{1}{4.9}+\frac{1}{9.14}+\frac{1}{14.19}+....+\frac{1}{44.49}\right).\frac{1-3-5-,,,,,-49}{89}=A.B=\frac{9}{196}.\left(-7\right)=-\frac{9}{28}\)