\(\left(x+3\right)\left(1-x\right)>0.\\ \Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x+3>0.\\1-x>0.\end{matrix}\right.\\\left\{{}\begin{matrix}x+3< 0.\\1-x< 0.\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x>-3.\\x< 1.\end{matrix}\right.\\\left\{{}\begin{matrix}x< -3.\\x>1.\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow-3< x< 1.\)

\(\left(x^2-1\right)\left(x^2-4\right)< 0.\\ \Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x^2-1< 0.\\x^2-4>0.\end{matrix}\right.\\\left\{{}\begin{matrix}x^2-1>0.\\x^2-4< 0.\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x^2< 1.\\x^2>4.\end{matrix}\right.\\\left\{{}\begin{matrix}x^2>1.\\x^2< 4.\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}\left[{}\begin{matrix}x< 1.\\x>-1.\end{matrix}\right.\\\left[{}\begin{matrix}x>2.\\x< -2.\end{matrix}\right.\end{matrix}\right.\\\left\{{}\begin{matrix}\left[{}\begin{matrix}x>1.\\x< -1.\end{matrix}\right.\\\left[{}\begin{matrix}x< 2.\\x>-2.\end{matrix}\right.\end{matrix}\right.\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}-1< x< 1.\\\left[{}\begin{matrix}x>2.\\x< -2.\end{matrix}\right.\end{matrix}\right.\\\left\{{}\begin{matrix}\left[{}\begin{matrix}x>1.\\x< -1.\end{matrix}\right.\\-2< x< 2.\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x>2.\\x< -2.\\-2< x< -1.\\1< x< 2.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x< -2.\\x>2.\end{matrix}\right.\)

nick dưới 10đ hỏi đáp ~ ko ai cần tk :))

\(\left|x\right|\ge0\)mà \(\left|-3\right|=3\)nên \(x\in\left\{3;-3;4;-4;5;-5;6;-6;....\right\}\)

\(3>x;x>3\)

\(x\) - (10 - \(x\)) = \(x\) - 22

\(x\) - 10 + \(x\) = \(x\) - 22

2\(x\) - 10 = \(x\) - 22

2\(x\) - \(x\)  = -22 + 10

\(x\)         = - 12

Dạ,em cảm ơn cô ạ!

\(49-x+12=30\)

\(49-x=30-12\)

\(49-x=18\)

\(x=49-18\)

\(x=31\)

Vậy \(x=31\)

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)=18\)

\(x+1+x+2+x+3=18\)

\(x+x+x+1+2+3=18\)

\(3x+6=18\)

\(x=18-6\)

\(3x=12\)

\(x=12:3\)

\(x=4\)

Vậy \(x=4\)

49-x=30-12=18

49-18=x

31=x=> x=31

3x+6=18

3x=18-6

3x=12

x=4

49 - x + 12 = 30

49 - x = 30 - 12

49 - x = 18

x = 49 - 18

x = 31

(x + 1) + (x + 2) + (x + 3) = 18

(x + x + x) + (1 + 2 + 3) = 18

3x + 6 = 18

3x = 12

x = 12 : 3

x = 4

= 93809060 nhé bạn

cảm ơn

126 +(-10)+345+(-116) = 345

126 + ( -10 ) + 345 + ( -116 )

= 345

mn ơi giúp tuii tui đang cần rất gấp đó ạ :(

x = (căn bậc hai(3)*căn bậc hai(13)*i+3)/6;x = -(căn bậc hai(3)*căn bậc hai(13)*i-3)/6;

bn viết sai chính tả mik ko trả lời nữa

mình làm theo yêu cầu sửa lại đề nha

Ta có :

\(\frac{4^{15}}{7^{30}}=\frac{\left(2^2\right)^{15}}{7^{30}}=\frac{2^{30}}{7^{30}}=\left(\frac{2}{7}\right)^{30}\)

\(\frac{8^{10}.3^{30}}{7^{30}.4^{15}}=\frac{\left(2^3\right)^{10}.3^{30}}{7^{30}.\left(2^2\right)^{15}}=\frac{2^{30}.3^{30}}{7^{30}.2^{30}}=\frac{\left(2.3\right)^{30}}{\left(7.2\right)^{30}}=\frac{6^{30}}{16^{30}}=\left(\frac{6}{16}\right)^{30}=\left(\frac{3}{8}\right)^{30}\)

vì \(\frac{2}{7}< \frac{3}{8}\)nên \(\left(\frac{2}{7}\right)^{30}< \left(\frac{3}{8}\right)^{30}\)

Vậy ...

quên là thế này nè đánh lộn 

  4^15/7^30 và 8^10.3^30/7^30.4^15