a)\(3^8:3^4+2^2.2^3\)\(=3^4+2^5\)

                                    \(=81+32\)

                                    \(=113\)

b)\(3.4^2-2.3=3.\left(4^2-3\right)\)

                          \(=3.13\)

                          \(=39\)

Học tốt nha!!!

5 mũ 2-( x-3 phần 4) mũ 2=4 mũ 2

có ai giải hộ mink ik ạ

a) -3/4.x - x = 1

=> x.(-3/4 - 1) = 1

=> x . -7/4       = 1

=> x                = 1 : -7/4

=> x                = -4/7

b) x⁵ = (2.x)⁴

=> x⁵ = 2⁴ . x⁴

=> x⁵ : x⁴ = 2⁴

=> x^{5 - 4}   = 16

=> x          = 16

\(-\frac{3}{4}\cdot x-x=1\)

\(\Rightarrow x\left(-\frac{3}{4}-1\right)=1\)

\(\Rightarrow-\frac{7}{4}x=1\)

\(\Rightarrow x=-\frac{4}{7}\)

\(x^5=\left(2x\right)^4\)

\(\Rightarrow x^5=16x^4\)

\(\Rightarrow x^5-16x^4=0\)

\(\Rightarrow x^4.x-16x^4=0\)

\(\Rightarrow x^4\left(x-16\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x^4=0\\x-16=0\end{cases}\Rightarrow}x=16\)

\(a,-\frac{3}{4}.x-x=1\)

\(\Rightarrow x.\left(-\frac{3}{4}-1\right)=1\)

\(\Rightarrow x.\left(-\frac{7}{4}\right)=1\)

\(\Rightarrow x=-\frac{4}{7}\)

\(b,x^5=\left(2.x\right)^4\)

\(\Rightarrow x^5=2^4.x^4\)

\(\Rightarrow x^5:x^4=2^4\)

\(\Rightarrow x^{5-4}=16\)

\(\Rightarrow x=16\)

7(x - 3) - x(3 - x)

= (x - 3)(7 + x)

chỉ bt có v mà k bt có đúng k 

1 ) 7 ( x - 3 ) - x ( 3 - x ) 

= 7 ( x - 3 ) + x ( x - 3 )

= ( x - 3 ) ( 7 + x )

2 ) 4x² - 6x + 3 - 2x

= 4x² - 2x - 6x + 3

= 2x ( 2x - 1 ) - 3 ( 2x - 1 )

= ( 2x - 1 ) ( 2x - 3 )

3 ) ( 4 - x ) - 4x + x²

= ( 4 - x ) - x ( 4 - x )

= ( 4 - x ) (  1 - x )

4 ) x² - 2xy + y²

= ( x - y )²

1, \(7\left(x-3\right)-x\left(3-x\right)=7\left(x-3\right)+x\left(x-3\right)\)

\(=\left(x-3\right)\left(x+7\right)\)

2,\(4x^2-6x+\left(3-2x\right)=4x^2-8x+3\)

\(=4x^2-6x-2x+3=2x\left(2x-3\right)-\left(2x-3\right)\)

\(=\left(2x-3\right)\left(2x-1\right)\)

3,\(\left(4-x\right)-4x+x^2=x^2-5x+4\)

\(=x^2-x-4x+4=x\left(x-1\right)-4\left(x-1\right)=\left(x-1\right)\left(x-4\right)\)

4,\(x^2-2xy+y^2=\left(x-y\right)^2\)

2.4^x - 1 = 128

=> 4^x - 1 = 64

=> x - 1 = 3

=> x = 4

b, 17.4^2 + 83.16 

= 17.16 + 83.16

= 16(17 + 83)

= 16.100

= 1600

c, a^5 . 10^10.a^15

= a^20.10^10

d, 3{65 - [5(4 + 2.3) - 15] : 7}

= 3{65 - [5(4 + 6) - 15] : 7}

= 3{65 - [5.10 - 15] : 7}

= 3{65 - [50 - 15] : 7}

= 3{65 - 35 : 7}

= 3{65 - 5}

= 3.60

= 180

đã đi học ở trường đâu, học nhà cô à

bạn biết câu trả lời ko

nếu biết mong bạn giúp mình

a) 128 - 3(x + 4) = 23

             3(x + 4) = 128 -23

             3(x + 4) = 105

                x + 4  = 105 : 3

                x + 4  = 35

                x        = 35 - 4

                x        = 31

\(a.128-3\left(x+4\right)=23.\)

\(3\left(x+4\right)=128-23\)

\(3\left(x+4\right)=105\)

\(x+4=105:3=35\)

\(x=35-4=31\)

\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)

\(\left(4x+28\right)\cdot3=175-55=120\)

\(4x+28=120:3=40\)

\(4x=40-28=12\)

\(x=12:4=3\)

a, \(128-3.\left(x+4\right)=23\)

\(\Rightarrow\) \(3.\left(x+4\right)=105\)

\(\Rightarrow\) \(x+4=35\)

\(\Rightarrow\) \(x=31\)

b, \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(\Rightarrow\) \(\left(4x+28\right).3+55=175\)

\(\Rightarrow\) \(\left(4x+28\right).3=120\)

\(\Rightarrow\) \(4x+28=40\)

\(\Rightarrow\) \(4x=12\)

\(\Rightarrow\) \(x=3\)

\(2^{x+1}=4=2^2\Rightarrow x+1=2\Rightarrow x=1\)

\(2^{x-1}=4=2^2\Rightarrow x-1=2\Rightarrow x=3\)

\(2^x.4=128=4.32=4.2^5\Rightarrow x=5\)

\(3^{x-2}.9=81=9.9=9.3^2\Rightarrow x-2=2\Rightarrow x=4\)

\(\frac{3^{x+1}}{9}=3\Rightarrow3^{x+1}=27=3^3\Rightarrow x=2\)

\(41-2^x=9\Rightarrow2^x=41-9=32=2^5\Rightarrow x=5\)

Quá 20h rồi không biết được ko
 

Bn ơi cái bài 1,2 sai

giúp vs