đúng ,mình k 2 nhé

x^4-2x^3-x^2-2x^3+4x^2+2x-6

=x^4+3x^2+2x-6

=x^4-x^3+x^3-x^2+4x^2-4x+6x-6

=x^3.(x-1)+x^2.(x-1)+4x.(x-1)+6.(x-1)

=(x^3+x^2+4x+6).(x_1)

nhớ cho mk nha

bạn tác sai hay sao ý 
-2x^3-2x^3 sao lại hết đc nhìn kĩ lại đi

hình như mk bam sai that

\(=x^2\left(x^2+2x+1\right)+x+1\)

\(=x^2\left(x+1\right)^2+x+1\)

\(=\left(x+1\right)\left[x^2\left(x+1\right)+1\right]\)

\(=\left(x+1\right)\left(x^3+x^2+1\right)\)

\(x^4+2x^3+x^2+x+1\)

\(=x^2\left(x+1\right)^2+\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+x^2+1\right)\)

Hướng dẫn thôi :

a) x ( x + 2 ) ( x^2 - 6x + 4 )

b) ( x + 1 ) ( x + 2 ) ( x - 2 )

cách làm cơ

b) x^3 + x^2 - 4x - 4

= x^2 ( x + 1 ) - 4 ( x + 1 )

= ( x + 1 ) ( x^2 - 2^2 )

= ( x + 1 ) ( x + 2 ) ( x - 2)

1: \(x^2-2x-24=\left(x-6\right)\left(x+4\right)\)

2: \(x^2-8x+15=\left(x-3\right)\left(x-5\right)\)

3: \(x^2-9x+14=\left(x-2\right)\left(x-7\right)\)

\(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\\ =\left(x+4\right)^2\left(x^2-1\right)-\left(x^2-1\right)\\ =\left(x^2-1\right)\left[\left(x+4\right)^2-1\right]\\ =\left(x-1\right)\left(x+1\right)\left(x+4-1\right)\left(x+4+1\right)\\ =\left(x-1\right)\left(x+1\right)\left(x+3\right)\left(x+5\right)\)

\(= (x+4)^2(x^2-1)-(x^2-1)=[(x+4)^2-1](x^2-1)\)

\(=(x+4-1)(x+4+1)(x-1)(x+1)\)

\(=(x+3)(x+5)(x-1)(x+1)\)

\(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\)

\(=\left(x+4\right)^2\left(x^2-1\right)-\left(x^2-1\right)\)

\(=\left(x^2-1\right)\left[\left(x+4\right)^2-1\right]\)

\(=\left(x^2-1\right)\left(x+3\right)\left(x+5\right)\)

a, = [(x-2).(x+1)]^2+(x-2)^2

    = (x-2)^2.(x+1)^2+(x-2)^2

    = (x-2)^2.[(x+1)^2+1]

    = (x-2)^2.(x^2+2x+2)

Tk mk nha

b)  \(6x^5+15x^4+20x^3+15x^2+6x+1\)

\(=6x^5+3x^4+12x^4+6x^3+14x^3+7x^2+8x^2+4x+2x+1\)

\(=\left(2x+1\right)\left(3x^4+6x^3+7x^2+4x+1\right)\)

\(=\left(2x+1\right)\left(3x^4+3x^3+3x^2+3x^3+3x^2+3x+x^2+x+1\right)\)

\(=\left(2x+1\right)\left(x^2+x+1\right)\left(3x^2+3x+1\right)\)