=129140163> 48828125 

=> 3¹⁷ > 5 ¹¹

3^17>5^11 cần cách làm ko?

3¹⁷ = ( 3⁶ )¹¹ = 729¹¹

Vì 729¹¹ > 5¹¹ nên 3¹⁷ > 5¹¹

a: -3/4=-9/12

-5/6=-10/12

mà -9>-10

nên -3/4>-5/6

b: -5/17<0<2/7

c: 11/10>1>9/14

a) 11/9 > 0

-17/36 < 0

⇒ 11/9 > -17/36

b) -13/4 < -12/4 (= -3)

-11/5 > -15/5 (= -3)

⇒ -13/4 < -11/5

c) Do 5,510 < 5,580

⇒ -5,510 > -5,580

d) -171,3 < 0

0,25 > 0

⇒ -171,3 < 0,25

a) 11/9 > 0

-17/36 < 0

⇒ 11/9 > -17/36

b) -13/4 < -12/4 (= -3)

-11/5 > -15/5 (= -3)

⇒ -13/4 < -11/5

c) Do 5,510 < 5,580

-> -5,510 > -5,580

d) -171,3 < 0

0,25 > 0

-> -171,3 < 0,25

\(\frac{1}{3}^{17}=\frac{1}{3}và\frac{1}{5}^{11}=\frac{1}{5}\)

\(vì\frac{1}{3}>\frac{1}{5}\Rightarrow\frac{1}{3}^{17}>\frac{1^{ }}{5}^{11}\)

3¹⁷=129140163

5¹¹⁼9765625

Vì 129140163>9765625

Nên 3¹⁷>5¹¹

\(5^{30}=\left(5^3\right)^{10}=125^{10}\)

Vì 125¹⁰>124¹⁰=>5³⁰>124¹⁰

a,

\(5^{30}\)và  \(124^{10}\)

\(5^{30}=\left(5^3\right)^{10}=125^{10}\)

Vì \(125^{10}>124^{10}\)nên \(5^{30}>124^{10}\)

b, \(31^{11}\)và  \(17^{14}\)

\(31^{11}< 32^{11}=\left(2^5\right)^{11}=2^{55}\)

\(17^{14}< 16^{14}=\left(2^4\right)^{14}=2 ^{56}\)

Vì \(2^{55}< 2^{56}\)nên \(31^{11}< 17^{14}\)