\(\dfrac{2xX-4,36}{0,125}=0,25x42,9-11,7x0,25+0,25x0,8\)
Những câu hỏi liên quan
tìm x
\(\frac{2xx-4,36}{0,125}\)=8
a) Tìm x, biết .\(\frac{2xX-4,36}{0,125}=0,25x42,9-11,7x0,25+0,25x0,8\)
Ta có:
0,25 . 42,9 - 11,7 . 0,25 + 0,25 . 0,8
= 0,25 ( 42,9 - 11,7 + 0,8 )
= 0,25 . 32
= 8
\(\frac{2.x-4,36}{0,125}=8\)
\(\Rightarrow\left(2.x-4,36\right):0,125=8\)
\(\Rightarrow2x-4,36=8.0,125=1\)
\(2x=1+4,36=5,36\)
\(x=5,36:2=2,68\)
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\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11,7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=5,36:2=2,68\)
Bài 1 : Tìm X
a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8
b) 104,5 x X -14,1 x X + 9,6 x X = 25
c) \(\frac{5xX}{x-13}=\)49 x 0,5 - 7 x 0,5 + 0,25
d) 13,44 x X - ( 1,6 + x ) x 0,5 -3,7 x ( x - 0,9 ) = 13, 618
#)Giải :
a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8
\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )
\(\frac{2xX-4,36}{0,125}=\)0,25 x 32
\(\frac{2xX-4,36}{0,125}=8\)
\(2xX-4,36=8x0,125\)
\(2xX-4,36=1\)
\(2xX=1+4,36\)
\(2xX=5,36\)
\(X=5,36:2\)
\(X=2,68\)
#~Will~be~Pens~#
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#)Next :
b) 104,5 x X - 14,1 x X + 9,6 x X = 25
( 104,5 - 14,1 + 9,6 ) x X = 25
100 x X = 25
X = 25 : 100
X = 0,25
#~Will~be~Pens~#
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b,
104,5.x-14,1.x+9,6.x=25
x(104,5-14,1+9,6)=25
x.100=25
x=25:100
x=0,25
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Xem thêm câu trả lời
tìm x biết; 2*x-4,36/0,125=0,25*42,9-11,7*0,25+0,25*0,8
2*x-4,36/0,125=0,15*42,9-11,7*0,25+0,25*0,8 tìm x
\(2x-\frac{4.36}{0.125}=0.15\times42.9-11.7\times0,25\times0.8\)
\(2x-\frac{872}{25}=\frac{819}{200}\)
\(2x=\frac{819}{200}+\frac{872}{25}=\frac{1559}{40}\)
\(x=\frac{1559}{40}\times\frac{1}{2}=\frac{1559}{80}\)
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2xX+X:0,125=10
2xX+X:0,125=10
2xX+Xx1/8=10
Xx(2+1/8)=10
Xx2,125=10
X=10:2,125
X=80/17
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x:0,125=10-2xX
X =1,25-0,25xX
x+0,25xX=1,25
x =1
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Câu hỏi:
\(\frac{2.x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\frac{2x-4.36}{0.125}=0.25\cdot42.9-11.7\cdot0.25+0.25\cdot0.8\)
\(\frac{2x-4.36}{0.125}=0.25\left(42.9-11.7+0.8\right)\)
\(\frac{2x-4.36}{0.125}=0.25\cdot32\)
\(\frac{2x-4.36}{0.125}=8\)
2x - 4.36 = 8 * 0.125 = 1
2x = 1 + 4.36 = 5.36
x = 5.36 : 2 = 2.68
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1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)
\(A=\dfrac{1}{2}-\dfrac{1}{4}\)
\(A=\dfrac{2}{4}-\dfrac{1}{4}\)
\(A=\dfrac{1}{4}\)
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\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)
\(D=\dfrac{77}{39}+\dfrac{3}{2}\)
\(D=\dfrac{271}{78}\)
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\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)
\(C=\dfrac{5}{2}-\dfrac{3}{2}\)
\(C=1\)
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\(\dfrac{-3}{10}\)-0,125+\(\dfrac{-7}{10}\)+1,125
`-0,125 + (-7)/10 + 1,125`
`= ( -0,125 + 1,125) + (-7)/10`
`= 1 + (-7)/10`
`= 10/10 + (-7)/10`
`= 3/10`
`#``QAnhh`
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