2017*4+2017*62+2017*35-2017

=2017*(4+62+35-1)

=2017*100

=201700

2006*42+2006*39+2006*21-2006*2

=2006*(42+39+21-2)

=2006*100

=200600

 k mik đi

A , 201700

B, 200600

a) 2017*4+2017*62+2017*35-2017

=2017*(4+62+35)-2017*1

=2017*(101-1)

=2017*100

=201700

b)2006*42+2006*39+2006*21-2006*2

=2006*(42+39+21-2)

=2006*100

=200600

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

a)67/63 x 15/3 + 15/31 x 11/21

Thiếu đề

b)15/31 x 34/63 - 11/21 x 15/31

=15/31 x ( 34/63 -11/21)

= 15/31 x  1/63=  5/651

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: 

\(2018\cdot2018-2017\cdot2019\)

\(=2018^2-\left(2018-1\right)\left(2018+1\right)\)

\(=2018^2-\left(2018^2-1\right)\)

\(=2018^2-2018^2+1\)

\(=1\)

\(2018.2018-2017.2019\)

\(=2018^2-\left(2018-1\right)\left(2018+1\right)\)

  \(=2018^2-\left(2018^2-1\right)\)

  \(=2018^2-2018^2+1\)

  \(=1\)

nhớ k đấy

2018*2018-2017*2019

=2018*(2019-1)-2017*2019

=2018*2019-2018-2017*2019

=2019-2018=1

a: \(=167\cdot\dfrac{67}{1000}+167\cdot\dfrac{33}{1000}=167\cdot\dfrac{1}{10}=\dfrac{167}{10}\)

2016 x 101 – 2016

= 2016 x 101 – 2016 x 1

= 2016 x ( 101 -1)

= 2016 x 100

= 201600

2017 x ( 101 - 1 ) = 2017 x 100

                            = 201700

= 54 x 997 + 54 x 2 + 998 + 54 x1

= 54 x ( 997 + 2 + 998 + 1)

= 54 x              1998

= 107 892

Có gì sai tthongg cảm nó!

ok

ok

5x25x2x8x199x4x125

=(5x2)x(25x4)x(8x125)x199

=10x100x1000x199

=1000000x199

=199000000

5x25x2x8x199x4x125

=(5x2)x(25x4)x(8x125)x199

=10x100x1000x199

=1000000x199

=199000000

5x25x2x8x199x4x125

=(5x2)x(25x4)x(8x125)x199

=10x100x1000x199

=1000000x199

=199000000