Mọi người ơi, giúp em với ạ

a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)

=\(9^4.13:9^3=13.9=117\)

b) 100-(75-25)=100-50=50

\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)

\(< =>\left(52488+32805\right):\left(810-81\right)\)

\(< =>85293:729\)

\(< =>117\)

\(b,100-\left[75-\left(7-2\right)^2\right]\)

\(< =>100-\left[75-\left(5\right)^2\right]\)

\(< =>100-\left[75-25\right]\)

\(< =>100-50\)

\(< =>50\)

\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)

\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)

\(< =>\left[2^4\cdot32\right]-192:8^2\)

\(< =>\left[16\cdot32\right]-192:64\)

\(< =>512-3\)

\(< =>509\)

1, Ta có :

     \(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)

    \(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)

    \(x+\frac{3}{5}=\frac{3}{2}\)

    \(x=\frac{3}{2}-\frac{3}{5}\)

    \(x=\frac{15}{10}-\frac{6}{10}\)

    \(x=\frac{9}{10}\)

Vậy x = \(\frac{9}{10}\)

2, Ta có :

    \(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)

    \(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)

    \(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)

    \(\frac{3}{4}\div x=-\frac{5}{6}\)

    \(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)

    \(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)

    \(x=-\frac{9}{10}\)

Vậy x = \(-\frac{9}{10}\)

thanks bạn nha

\(\frac{16}{7}x\frac{3}{8}-\frac{1}{3}=\frac{6}{7}-\frac{1}{3}=\frac{11}{21}\)

\(\frac{12}{6}x\frac{6}{3}+\frac{12}{6}=2x2+2=4+2=6\)

\(\left(\frac{12}{6}+\frac{12}{6}\right)x12=\left(2+2\right)x12=4x12=48\)

học tốt~~~

16/7 x 3/8 - 1/3 = 11/21

12/6 x 6/3 + 12/6 = 12/6 + ( 6/3 + 1) = 12/6 + 3=5

(12/6 +12/6) x 12 = 4 x 12 = 48 

k mk nha

Hihi Thanks chị ạ !!

bạn có thể kiểm tra lại đề bài phần a không

Mình kiểm tra lại rồi ko sai nhưng bạn chỉ làm mỗi câu b thôi cũng đc

120-{14+2[+7-(x-2):2]}=32

=> 120 - (14+(14-2((x-2):2)))=32 

=> 120-32 = 14+14-2((x-2):2)

=> 88 - 28 =2((x-2):2)

=> 30 = (x-2):2

=> 60 = x-2

=> x= 62 

Ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) =  335

=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335

=> 10x + 120 = 335

=> 10x = 335 - 120

=> 10x = 215

=> x = 21,5 

ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) =  335

<=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335

<=> 10x + 120 = 335

=> 10x = 335 - 120

=> 10x = 215

vậy x = 21,5 

Ta có ; \(1\dfrac{1}{10}.1\dfrac{1}{11}.....1\dfrac{1}{2011}.1\dfrac{1}{2012}\)

\(=\dfrac{11}{10}.\dfrac{12}{11}.....\dfrac{2012}{2011}.\dfrac{2013}{2012}\)
 

\(=\dfrac{2013}{10}=201,3\)

1 \(\dfrac{1}{10}\)x 1\(\dfrac{1}{11}\)x 1\(\dfrac{1}{12}\) x...x 1\(\dfrac{1}{2011}\)x 1\(\dfrac{1}{2012}\)

=\(\dfrac{11}{10}\)x \(\dfrac{12}{11}\)x \(\dfrac{13}{12}\)x \(\dfrac{2012}{2011}\)x \(\dfrac{2013}{2012}\)