a) 2 x 2 = 4              3 x 3 = 9

2 x 4 = 8              3 x 5 = 15

2 x 6 = 12              3 x 7 = 21

2 x 8 = 16              3 x 9 = 27

4 x 4 = 16              5 x 5 = 25

4 x 2 = 8              5 x 7 = 35

4 x 6 = 24              5 x 9 = 45

4 x 8 = 32              5 x 3 = 15

b) 200 x 4 = 800              300 x 2 = 600

200 x 2 = 400             300 x 3 = 900

400 x 2 = 800             500 x 1 = 500

100 x 4 = 400             100 x 3 = 300

Trả lời 1 câu thôi nhé em 100 nhân 4 bằng 400 nhá em

a) 2 x 2 =4 ......              3 x 3 = ..9....

2 x 4 = ....8..              3 x 5 = ...15...

2 x 6 = ....12..              3 x 7 = .21.....

2 x 8 = ..16....              3 x 9 = ..27....

4 x 4 = ...16...              5 x 5 = ...25...

4 x 2 = ...8...              5 x 7 = ..35....

4 x 6 = .....24.              5 x 9 = .45.....

4 x 8 = ..32....              5 x 3 = .15.....

b) 200 x 4 = 800......              300 x 2 =600 ......

200 x 2 = ..400....             300 x 3 = 900......

400 x 2 = .....800.             500 x 1 = ..500....

100 x 4 = ....400..             100 x 3 = .300.....

(x+1)+(x+4)+(x+7)+(x+10)=62

=>4x+22=62

=>4x=62-22

=>4x=40

=>x=10

t tôi nha bn

x+(1+4+7+10)=62

x+22=62

x=62-22

x=40

( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10 ) = 62

4x+ (1+4+7+10)=62

4x+22=62

4x=62-22

4x=40

x=40:4

x=10

(x+1)+(x+4)+(x+7)+(x+10)=62

( x + x + x + x ) + ( 1 + 4 + 7 + 10 ) = 62

4x + 22 = 62

4x = 62 - 22

4x = 40

x = 40 : 4

x = 10

(x + 1) + (x + 4) + (x + 7) + (x + 10) = 62

x + 1 + x + 4 + x + 7 + x + 10 = 62

4x + 22 = 62

4x = 40

=> x = 40 / 10 = 4

x= 4 nha bn

k mk nha

mk k lại cho!

\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+\left(x+10\right)=62\)

\(\Rightarrow x+1+x+4+x+7+x+10=62\)

\(\Rightarrow4x+22=62\)

\(\Rightarrow4x=40\)

\(\Rightarrow x=10\)

x+(1+4+7+10)=62

x+22=62

x=62-22

x=40

6 - 8 + 10 - 12 + ... - x = - 200

( 6 - 8 ) +( 10 - 12 ) + ... + ( x - 2 - x ) = - 200

( - 2 ) + ( - 2 ) + ... + ( - 2 ) = - 200 ( Có ( x - 6 ) : 2 + 1 = x : 2 - 3 + 1 = x : 2 - 2 số hạng - 2 )

( - 2 ) x x : 2 - 2 = 200

( - 2 ) x x : 2 = 202

x = - 202

a, 35 ⋮ (x+3) => (x+3) ∈ Ư(35) = {1;5;7;35} => x ∈ {2;4;32}

b, (x+7) ⋮ 25 và x < 100

Vì (x+7) ⋮ 25 => x+7 ∈ B(25) = {0;25;50;75;...}

Mà x < 100 => x+7 ∈ {0;25;50;75}

=> x ∈ {18;43;68}

c, (x+13) ⋮ (x+1)

Ta có: x+13 = x+1+12

Vì (x+1) ⋮ (x+1) nên để (x+13) ⋮ (x+1) thì 12 ⋮ (x+1)

=> (x+1) ∈ Ư(12) = {1;2;3;4;6;12} => x ∈ {0;1;2;3;5;11}

d, 91 ⋮ x; 26 ⋮ x và 10 < x < 30

Vì 91 ⋮ x; 26 ⋮ x => x ∈ ƯC(26;91)

Ta có: 26 = 2.13; 91 = 7.13

=> ƯCLN(26;91) = 13

=> x ∈ Ư(13) = {1;13}

Mà 10 < x < 30 => x = 13

e, (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 và x < 200

Vì (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 nên (x+2) ∈ BC(10;15;25)

Ta có: 10 = 2.5; 15 = 3.5; 20 =  2 2 . 5

=> BCNN(10;15;20) =  2 2 . 3 . 5 = 60

=> (x+2) ∈ B(60) = {0;60;120;180;...}

Mà x < 200 => x ∈ {58;118;178}

a)   x² + x = 0

=>   x( x+ 1 ) = 0

=>  x  = 0 

hoặc x = -1 

b)  b, (x-1)^x+2 = (x-1)^x+4

=>  x + 2    =   x  + 4 

=> 0x = 2 ( ktm)

Vậy ko có giá trị x nào thoả mãn đk 

d) Ta có: x-1/x+5 = 6/7

=>(x-1).7 = (x+5).6

=>7x-7 = 6x+ 30

=> 7x-6x = 7+30

=> x = 37

Vậy x = 37

e, x²/ 6= 24/25

=>  x²  . 25 = 6 . 24

 ⇒${}^{}.25=144$

$\Rightarrow {}^{}=144÷25$

$\Rightarrow {}^{}=5,76=2,{}^{}=\left(-2,{}^{}\right)$

$\Rightarrow x\in \left\{2,4;-2,4\right\}$

Vậy $x\in \left\{2,4;-2,4\right\}$

g, x-2/ x-1= x+4/ x+7

$\iff \left(x-2\right)\times \left(x+7\right)=\left(x+4\right)\times \left(x-1\right)$

$\iff {}^{}+7x-2x-14={}^{}-x+4x-4$

$\iff {}^{}-{}^{}+7x-2x+x-4x-14+4=0$

$\iff$$2x-10=0$

$\Rightarrow x=5$

\(200:25-\left(12-x\right)=4\\ 8-\left(12-x\right)=4\\ 12-x=8-4\\ 12-x=4\\ x=12-4\\ x=8\\ ---\\ \left(x-10\right).5=100-20.4\\ \left(x-10\right).5=100-80=20\\ x-10=\dfrac{20}{5}=4\\ x=4+10=14\)

a)\(200:25-\left(12-x\right)=4\)

\(\Rightarrow8-\left(12-x\right)=4\)

\(\Rightarrow12-x=8-4\)

\(\Rightarrow12-x=4\)

\(\Rightarrow x=12-4\)

\(\Rightarrow x=8\)

b) \(\left(x-10\right)\cdot5=100-20\cdot4\)

\(\Rightarrow\left(x-10\right)\cdot5=100-80\)

\(\Rightarrow\left(x-10\right)\cdot5=20\)

\(\Rightarrow x-10=4\)

\(\Rightarrow x=10+4\)

\(\Rightarrow x=14\)