\(\frac{56-x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\left(56-x\right)2=34\cdot3=102\)

\(\Rightarrow56-x=102\div2\)

\(\Rightarrow56-x=51\)

\(\Rightarrow x=56-51\)

\(\Rightarrow x=5\)

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2\)

\(\Rightarrow x=1853\)

\(56-\frac{x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2=1853\)

Ta có : 

    56-x/34=144/96

=>     x/34=56-144/96

=>    x/34=109/2

Áp dụng tích chất 2 phân số bằng nhau thì 2 tích chéo bằng nhau ta có:

   x/34=109/2 <=> x.2=34.109

                     => x.2 =3706

                    => x     =3706:2

                   => x      =1853

Vậy x=1853

 x= 56 *96 / 34 * 144

x=5376/4896

5 nha e

giúp mik k lun nhé cả cách làm và đáp số

x là 1853

         x/34 = 56 - 144/96

         x/34 = 109/2

         x/34 = 1853/34

=> x = 1853

X/34=56-144/96

x/34=109/2

x=109x34:2=1853

giả giúp mình nhé

Sửa đề xí nha:

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{3706}{34}\Rightarrow x=3706\)

◥ὦɧ◤ŤŔầŃ VăŃ ĤùŃĞ™​ sai đáp số rồi kìa

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{56\cdot2-3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34\)

\(\Rightarrow2x=3706\)

\(\Rightarrow x=3706:2=1853\)

Vậy x = 1853

X/34 = 56 - 144/96

X/34 = 109/2

X/34 = 3706/34

=> X= 3706

X/34 = 56 - 144/96

X/34=109/2

X/34 = 3706/34

=>x=3706

       \(\frac{x-144}{10}+\frac{x-130}{12}+\frac{x-112}{14}+\frac{x-106}{16}+\frac{x-96}{17}=15\)

\(\Leftrightarrow\)\(\frac{x-144}{10}-1+\frac{x-130}{12}-2+\frac{x-112}{14}-3+\frac{x-106}{16}-4+\frac{x-96}{17}-5=0\)

\(\Leftrightarrow\)\(\frac{x-154}{10}+\frac{x-154}{12}+\frac{x-154}{14}+\frac{x-154}{16}+\frac{x-154}{17}=0\)

\(\Leftrightarrow\)\(\left(x-154\right)\left(\frac{1}{10}+\frac{1}{12}+\frac{1}{14}+\frac{1}{16}+\frac{1}{17}\right)=0\)

\(\Leftrightarrow\)\(x-154=0\)  (do   1/10 + 1/12 + 1/14 + 1/16 + 1/17  khác   0)

\(\Leftrightarrow\)\(x=154\)

Vậy...

Hình như đề có gì sai nha bạn.

\(\frac{3}{34}+\frac{34}{34}.\frac{3}{4}=\frac{3}{34}+1.\frac{3}{4}=\frac{3}{34}+\frac{3}{4}=\frac{57}{68}\)

\(\frac{23}{3}.\frac{56}{6}+\frac{86}{78}=\frac{23}{3}.\frac{28}{3}+\frac{43}{39}=\frac{644}{9}+\frac{28}{3}=\frac{728}{9}\)

\(\frac{3}{45}:\frac{1}{4}=\frac{1}{15}.4=\frac{4}{15}\)

\(\frac{5}{34}-\frac{3}{6}=\frac{5}{34}-\frac{1}{2}=\frac{3}{4}\)

oh my god!!!mk mới lp 6 nên ko giải đc....khó wá!

meo meo!

#adinamoto#

ta có: \(\frac{x}{3}=\frac{y}{4}=k\Rightarrow\hept{\begin{cases}x=3k\\y=4k\end{cases}}\)

mà xy = 144 => 3k.4k = 144

                            12k²  = 144

                               k² = 12

=> \(k=\sqrt{12}\) hoặc \(k=-\sqrt{12}\)

=> x = 3k = \(3.\sqrt{12}\) ....

...

bn tự lm típ nha

giải tiếp đi bạn