11-(13-x)=(13-11)

=>11-13+x=2

=>x-2=2

=>x=4

Tìm x

11/12-(5/42-x)=-(15-11/13)

=>11/13-(5/42-x)=184/13

=>5/42-x=11/13- (-184/13)

=>5/42-x=15

=>x=5/42-15

=>x=-625/42

5/42-x=11/13- [-(15-11/13)]=11/13+15-11/13

5/42-x=(11/13-11/13)+15=15

x=5/42-15=5/42-630/42

x=-625/42

Vậy x=-625/42

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)

\(\frac{-5}{42}+x=-\frac{15}{28}+\left(\frac{11}{13}-\frac{11}{13}\right)\)

\(\frac{-5}{42}+x=-\frac{15}{28}\)

\(x=-\frac{15}{28}+\frac{5}{42}\)

\(x=-\frac{45}{84}+\frac{10}{84}\)

\(x=-\frac{35}{84}\)

Vậy \(x=-\frac{35}{84}\).

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)

\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)

\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)

\(x=\frac{5}{42}-\frac{15}{28}\)

\(x=-\frac{5}{12}\)

vậy \(x=-\frac{5}{12}\)

                              Bài làm :

Ta có :

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

\(\Leftrightarrow\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)

\(\Leftrightarrow\frac{5}{42}-x=\frac{11}{13}-\frac{113}{364}\)

\(\Leftrightarrow\frac{5}{42}-x=\frac{15}{28}\)

\(\Leftrightarrow x=\frac{5}{42}-\frac{15}{28}=-\frac{5}{12}\)

Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

=> x + 1 = 0 ( vì 1/10 + 1/11 + 1/12 - 1/13 - 1/14  khac 0 )  

=> x = -1