ta cos:

119/120=1-1/120

118/119=1-1/119

mà: 119<120

nên: 119/120>118/119

Ta có : \(1-\frac{119}{120}=\frac{1}{120}\)

\(1-\frac{118}{119}=\frac{1}{119}\)

mà 119 < 120

\(\Rightarrow\frac{1}{120}< \frac{1}{119}\)

\(\Rightarrow1-\frac{1}{120}>1-\frac{1}{119}\)

\(\Rightarrow\frac{119}{120}>\frac{118}{119}\)

vậy.....

trạng nguyên tiếng việt nha bạn

\(~~~HD~~~\)

\(\frac{90}{93}=1-\frac{3}{93};\frac{190}{193}=1-\frac{3}{193}\)

Vì: 93<193 nên: \(\frac{3}{93}>\frac{3}{193}\Rightarrow\frac{90}{93}< \frac{190}{193}\)

Vậy: \(\frac{90}{93}< \frac{190}{193}\)

ta có :

\(\frac{90}{93}< \frac{190}{193}\)

\(\frac{90}{93}=\frac{190}{193}\)

Vì \(\frac{90}{93}=\frac{190}{193}\)bỏ số 1 đi thì bằng \(\frac{90}{93}=\frac{90}{93}\)

Hk tốt

k nhé

Ta có : [ ( 2/193 - 3/386 ) * 193/17 + 32/34 ] : [ ( 7/2001 + 11/4002 ) * 2001/25 + 9/2 ] .

=> [ 2/193 * 193/17 - 3/386 * 193/17 + 32/34 ] : [ 7/2001 * 2001/25 + 11/4002 * 2001/25 + 9/2 ] .

=> [ 2/17 - 3/34 + 32/34 ] : [ 7/25 + 11/50 + 9/2 ] .

=> [ 4/34 - 3/34 + 32/34 ] : [ 14/50 + 11/50 + 225/50 ] .

=> 33/34 : 5 .

=> 33/34 * 1/5 .

=> 33/170 .

Tính bằng cách thuận tiện nhất:

\(=\left[\left(\frac{2}{193}\cdot\frac{193}{17}\right)-\left(\frac{3}{386}\cdot\frac{193}{17}\right)+\frac{32}{34}\right]:\left[\left(\frac{7}{2001}\cdot\frac{2001}{25}\right)+\left(\frac{11}{4002}\cdot\frac{2001}{25}\right)+\frac{9}{2}\right]\)

\(=\left[\left(\frac{2}{17}-\frac{3}{17}\right)+\frac{32}{34}\right]:\left[\left(\frac{7}{25}+\frac{11}{50}\right)+\frac{9}{2}\right]\)

\(=\left(-\frac{1}{17}+\frac{32}{34}\right):\left(\frac{1}{2}+\frac{9}{2}\right)\)

\(=\frac{15}{17}+5\)

\(=\frac{100}{17}\)

~ học tốt ~

So sánh phân số bằng cách so sánh phần hơn với đơn vị của phân số:

Ta có: 195/193 - 1 = 195/193 - 193/193 = 2/193

và 2009/2007 - 1 = 2009/2007 - 2007/2007 = 2/2007

Vì: 2/2007 < 2/193 nên 2009/2007 < 195/193

Ta có :

\(\frac{195}{193}\)- 1 = \(\frac{2}{193}\)

   \(\frac{2009}{2007}\)= \(\frac{2}{2007}\)

      Vì \(\frac{2}{193}>\frac{2}{2007}\)nên \(\frac{195}{193}>\frac{2009}{2007}\)

Ta thấy :

\(\frac{195}{193}-1=\frac{2}{193}\)

\(\frac{2009}{2007}-1=\frac{2}{2007}\)

      Vì \(\frac{2}{193}>\frac{2}{2007}\) \(\Rightarrow\frac{195}{193}>\frac{2009}{2007}.\)

\(\left(\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right):\left(\left(\frac{7}{1931}+\frac{11}{3862}\right)\cdot\frac{1931}{25}+\frac{9}{2}\right)\)

= \(\left(\left(\frac{4}{386}-\frac{3}{386}\right)\cdot\frac{193}{17}+\frac{33}{34}\right):\left(\left(\frac{14}{3862}+\frac{11}{3862}\right)\cdot\frac{1931}{25}+\frac{9}{2}\right)\)

= \(\left(\frac{1}{186}\cdot\frac{193}{17}+\frac{33}{34}\right):\left(\frac{25}{3862}\cdot\frac{1931}{25}+\frac{9}{2}\right)\)

= \(\left(\frac{1}{34}+\frac{33}{34}\right):\left(\frac{1}{2}+\frac{9}{2}\right)\)

= \(1:5\)

= \(\frac{1}{5}=0,2\)

\(M=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right] \)

     \(=\left(\frac{2}{17}-\frac{3}{34}+\frac{33}{34}\right):\left(\frac{7}{25}+\frac{11}{50}+\frac{9}{2}\right)\)

       \(=\frac{4-3+33}{34}:\frac{14+11+225}{50}=1:5=0.2\)

\(=\left(\frac{1}{386}-\frac{193}{17}+\frac{33}{34}\right):\left(\frac{25}{3862}\cdot\frac{1931}{25}+\frac{9}{2}\right)\)

\(=\left[\frac{1}{386}-\left(\frac{193}{17}-\frac{33}{34}\right)\right]:\left(\frac{1}{2}+\frac{9}{2}\right)\)

\(=\left(\frac{1}{386}-\frac{386}{34}\right)\div5\)

\(=\frac{1}{386}\cdot\frac{1}{5}-\frac{386}{34}\cdot\frac{1}{5}=\frac{1}{1930}-\frac{386}{170}=\)là 1 phân số âm.

B= 38416

 A= 38407

suy ra A < B

\(\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1931}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{9}{2}\right]\)

\(=\left[\left(\frac{4}{386}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{14}{3862}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{9}{2}\right]\)

\(=\left(\frac{1}{386}.\frac{193}{17}+\frac{33}{34}\right):\left(\frac{25}{3862}.\frac{1931}{25}+\frac{9}{2}\right)\)

\(=\left(\frac{1}{34}+\frac{33}{34}\right):\left(\frac{1}{2}+\frac{9}{2}\right)\)

\(=1:5\)

\(=\frac{1}{5}\)