Cho E=1/3+2/3^2+3/3^3+...+100/3^100
CMR: E<3/4
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Cho E= 1/3+2/3^2+3/3^3+...+100/3^100. Chứng minh rằng: E<3/4
@Đỗ Nguyễn Như Bình \(\frac{2}{3^2}\) hay là \(\frac{2^2}{3}\) hay là \(\left(\frac{2}{3}\right)^2\) vậy em???????????
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Cho E= 1/3+2/3^2+3/3^3+...+100/3^100. Chứng minh rằng: E<3/4
Cho E = 1/3 + 2/3^2 + 3/3^3 + ... + 100/3^100
CMR: E < 3/4
cho E=(1/3)+(2/3^2)+...+(100/3^100)Chung minh E<(3/4)
Cho E=1/3+2/3^2+3/3^3+....+100/3^100
Chứng minh rằng E < 3/4
ta có : 1+1+1+1+1+1+1+1x0
=> 1x8 = 8
mà kòn x vs 0 nữa :
=> tổng đó =0
=> 0<3/4
=> E<3/4
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Cho E=1/3+2/3^2+3/3^3+...+100/3^100
CMR: E<3/4
Cho E=1/3+2/32+3/33+....+100/3100. CMR E<3/4
:Cho E=1/3 + 2/3^2 + 3/3^3 + … + 100/3^100
cho E=1/3 +2/32 +3/33 +...+100/3100 . CMR : E<3/4