3 x \(\frac{4}{11}\) = \(\frac{3}{1}\) x \(\frac{4}{11}\) = \(\frac{12}{11}\)

1 : \(\frac{5}{4}\) = \(\frac{1\times4}{5}\) = \(\frac{4}{5}\)

\(\frac{4}{5}\) x \(\frac{6}{7}\) + \(\frac{2}{3}\) = \(\frac{24}{35}\) + \(\frac{2}{3}\) = \(\frac{142}{105}\)

\(\frac{3}{4}\) + \(\frac{1}{2}\) : \(\frac{5}{6}\) = \(\frac{3}{4}\) + \(\frac{1}{2}\) x \(\frac{6}{5}\) = \(\frac{3}{4}\)+ \(\frac{6}{10}\) \(\frac{27}{20}\)

\(\frac{3}{4}\)+ \(\frac{1}{2}\) = \(\frac{3}{4}\) + \(\frac{2}{4}\)= \(\frac{5}{4}\)

1) \(\left(2x+3\right)^2=4x^2+12x+9\)

\(\left(3x+2\right)^2=9x^2+12x+4\)

\(\left(2x+5\right)^2=4x^2+20x+25\)

\(\left(2x+\dfrac{1}{3}\right)^2=4x^2+\dfrac{4}{3}x+\dfrac{1}{9}\)

\(\left(3x+\dfrac{1}{3}\right)^2=9x^2+2x+\dfrac{1}{9}\)

2)  \(\left(2x-3\right)^2=4x^2-12x+9\)

\(\left(3x-2\right)^2=9x^2-12x+4\)

\(\left(2x-5\right)^2=4x^2-20x+25\)

\(\left(2x-\dfrac{1}{3}\right)^2=4x^2-\dfrac{4}{3}x+\dfrac{1}{9}\)

\(\left(3x-\dfrac{1}{3}\right)^2=9x^2-2x+\dfrac{1}{9}\)

3) \(\left(2x-3\right)\left(2x+3\right)=4x^2-9\)

\(\left(3x-4\right)\left(3x+4\right)=9x^2-16\)

\(\left(2x-5\right)\left(2x+5\right)=4x^2-25\)

\(\left(x-\dfrac{1}{2}\right)\left(x+\dfrac{1}{2}\right)=x^2-\dfrac{1}{4}\)

\(\left(2x-\dfrac{1}{3}\right)\left(2x+\dfrac{1}{3}\right)=4x^2-\dfrac{1}{9}\)

1: \(\left(2x+3\right)^2=4x^2+12x+9\)

\(\left(3x+2\right)^2=9x^2+12x+4\)

\(\left(2x+5\right)^2=4x^2+20x+25\)

\(\left(2x+\dfrac{1}{3}\right)^2=4x^2+\dfrac{4}{3}x+\dfrac{1}{9}\)

\(\left(3x+\dfrac{1}{3}\right)^2=9x^2+2x+\dfrac{1}{9}\)

địt con mẹ bọn onlinemath sex

Sao toàn viết chữ thế ? Đọc sao nổi ? Viết lại ra số đi

\(a.\frac{2}{3}+\frac{1}{5}\cdot\frac{10}{7}\)

\(=\frac{2}{3}+\frac{1\cdot2}{1\cdot7}\)

\(=\frac{2}{3}+\frac{2}{7}=\frac{2\cdot7}{21}+\frac{2\cdot3}{21}=\frac{14}{21}+\frac{6}{21}=\frac{20}{21}\)

\(b.\frac{2}{7}\cdot\frac{4}{7}+\frac{2}{7}\cdot\frac{3}{7}\)

\(=\frac{2}{7}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)\)

\(=\frac{2}{7}\cdot\frac{7}{7}=\frac{2}{7}\cdot1=\frac{2}{7}\)

\(c.\left[-\frac{1}{4}+\frac{3}{10}\right]:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\left[-\frac{5}{20}+\frac{6}{20}\right]:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\frac{1}{20}:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\frac{1}{20}\cdot\left(-\frac{5}{3}\right)-\frac{7}{6}\)

\(=\frac{1\cdot\left(-1\right)}{4\cdot3}-\frac{7}{6}\)

\(=\left(-\frac{1}{12}\right)-\frac{7}{6}=\left(-\frac{1}{12}\right)-\frac{14}{12}=-\frac{15}{12}\)

bài 2 :a) \(2x-2\frac{2}{7}=2\frac{5}{7}\)

\(2x=2\frac{5}{7}-2\frac{2}{7}\)

\(2x=\left(2-2\right)+\left(\frac{5}{7}-\frac{2}{7}\right)\)

\(2x=0+\frac{3}{7}\)

\(2x=\frac{3}{7}\)

\(x=\frac{3}{7}:2=\frac{3}{7}\cdot\frac{1}{2}=\frac{3}{14}\)

\(b.\frac{17}{13x}=\frac{4}{39}\)

\(\Rightarrow13x\cdot4=17\cdot39\)

\(\Rightarrow13x\cdot4=663\)

\(\Rightarrow13x=663:4\)

\(\Rightarrow13x=165,75\)

\(\Rightarrow x=165,75:13\)

\(\Rightarrow x=12,75\)

\(****nha!!!!!!!!!!!!\)

dung may inh la tinh ra 

1,

\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)

\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)

\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)

\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)

\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)

\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)

4,

\(\frac{X+1}{5}=\frac{3}{7}\)

\(\Rightarrow\left(X-1\right).7=3.5\)

\(\Rightarrow7X-7=15\)

\(\Rightarrow7X=22\)

\(\Rightarrow X=\frac{22}{7}\)

\(\frac{X-3}{4}=\frac{1}{2}\)

\(\Rightarrow\left(X-3\right)2=1.4\)

\(\Rightarrow2X-6=4\)

\(\Rightarrow2X=10\)

\(\Rightarrow X=5\)

Tôi ko bt

Ta có 19/18=1+1/18

        2005/2004=1+1/2004

Vì 1/18>1/2004 nên 1+1/18 >1/2004 +1 hay 19/18>2005/2004

1. Ta có: \(\frac{19}{18}>\frac{18}{18}=1=\frac{2005}{2005}>\frac{2004}{2005}\)

hay: 19/18 > 1 > 2004/2005

Vậy 19/18 > 2004/2005

2. \(\frac{3}{6}=\frac{1}{2}=\frac{7}{14};\frac{2}{7}=\frac{4}{14};\frac{4}{7}=\frac{8}{14}\)

Vì 4/14 < 7/14 < 8/14

nên: 2/7 < 3/6 < 4/7.

3. \(\frac{12}{25};\frac{9}{5}=\frac{45}{25};\frac{3}{5}=\frac{15}{25};\frac{1}{25}\)

Vì 45/25 > 15/25 > 12/25 > 1/25

nên: 9/5 > 3/5 > 12/25 > 1/25

4. \(\frac{35}{42}+\frac{14}{42}=\frac{35+14}{42}=\frac{49}{42}\)

5. \(\frac{6}{16}+\frac{32}{16}=\frac{6+32}{16}=\frac{38}{16}=\frac{19}{8}\).

4)35/42+14/42=35+14/42=49/42=7/6

Câu 5 tương tự