(1^+2^2+3^2+....+2021^2)*(91-273:3)
tinh nhanh : (1^2+2^2 +3^ 2+4^2+...1000^2). ( 91-273 :3)
(12+22...+10002).(91-273:3)
=(12+22...+10002).(91-91)
=(12+22...+10002).0
=0
tinh : (12+22+32+........+20122)x(91-273 : 3)
=(12+22+...+20122)(91-91)
=(12+22+...+2012).0
=0
Tính nhanh : (12 +22+32+…+20122)(91-273:3)
(12+22+32+…10002) (91-273:3)
\(=\left(1^2+...+1000^2\right)\left(91-91\right)\)
\(=\left(1^2+...+1000^2\right)0\)
\(=0\)
(12+22+32+…10002) (91-273:3)
= ( ... ) . 0
=0
Ta có:
(12+22+32+…10002) (91-273:3)
= (12+22+32+…10002) (91-91)
=(12+22+32+…10002) .0
=0
Học tốt and HAND!!
k mk nhe
Tính nhanh: (12+22+32+....+10002).(91-273:3)
91-273:3=91-91=0
=>(12+22+32+...+1002)(91-273:3)=(12+22+32+...+1002).0=0
Thực hiện phép tính:
(12+22+32+....+20122)(91-273:3)
Bài 3. Tính nhanh :
( 12+22+33+........+20202) . ( 91 - 273 : 3 )
91 -273:3=91-91=0
Thực hiện phép tính
\(\left(1^2+2^2+3^2+...+2012^2\right).\left(91-273:3\right)\)
( 12 + 22 + 32 +....+ 20122 ). (91 - 91) = (12 + 22 + 32 +....+ 20122) . 0 = 0
[91-273/3]x[12+22+32+...+20122]
=[91-91]x[12+22+32+...+20122]
=0x[12+22+32+...+20122]
=0
Tính:
(1 mũ 2 + 2 mũ 2 + 3 mũ 2 + ..... +1000 mũ 2) . (91-273:3)
tìm x: