Question

(1^+2^2+3^2+....+2021^2)*(91-273:3)

Answer 1

\(\left(1^2+2^2+3^2+...+2021^2\right)\cdot\left(91-273:3\right)\)
\(=\left(1^2+2^2+3^2+...+2021^2\right)\cdot\left(91-91\right)\)
\(=\left(1^2+2^2+3^2+...+2021^2\right)\cdot0\)
\(=0\)

Answer 2

(12+22+32+...+20212)⋅(91−273:3)
=(12+22+32+...+20212)⋅(91−91)=(12+22+32+...+20212)⋅(91−91)
=(12+22+32+...+20212)⋅0=(12+22+32+...+20212)⋅0
$=0$

Answer 3

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Answer 4

(1^2+2^2+...+2021^2) x (91-273:3)

= (1^2+2^2+....+2021^2) x (91-91)

= (1^2+2^2+....+2021^2) x 0

= 0

Answer 5

(12+22+32+...+20212)⋅(91−273:3)
=(12+22+32+...+20212)⋅(91−91)=(12+22+32+...+20212)⋅(91−91)
=(12+22+32+...+20212)⋅0=(12+22+32+...+20212)⋅0
$=0$