cho 2 bieu thuc:A=101 x50 ;B= 50x49+53x50
khong thuc hien tinh hay su dung tinh chat cua phep tinh de so sanh gia tri so cua A va B
Tinh gia tri bieu thuc:a.3^2^3^0 b.5^2^0^3
cho bieu thuc:A=1/3^2+1/3^3+1/3^4+...+1/3^98+1/3^99
chung to A<1/2
Ta có: \(A=\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^{99}}\)
\(3A=\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{98}}\)
\(3A-A=\left(\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{98}}\right)-\left(\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^{99}}\right)\)
\(2A=\frac{1}{3}-\frac{1}{3^{99}}\)
\(A=\frac{1}{6}-\frac{1}{2\times3^{99}}\)
Vì \(\frac{1}{2\times3^{99}}>0\) nên \(\frac{1}{6}-\frac{1}{2\times3^{99}}
Đỗ Văn Hoài Tuân trả lời đúng rùi.
Cho bieu thuc:A=1/500+1/501+1/502+...+1/599
Chung to rang 1/6<A<1/5
cho 2 bieu thuc:
A=(\(\sqrt{20}\) -\(\sqrt{45}\) +3\(\sqrt{5}\) ).\(\sqrt{5}\) va B=\(\dfrac{x+1-2\sqrt{x}}{\sqrt{x}-1}\) +\(\dfrac{x+\sqrt{x}}{\sqrt{x}+1}\) (Dieu kien: x>0, x khac 1
a) Rut gon bieu thuc A va B
b)Tim cac gia tri cua x de gia tri cua bieu thuc A bang 2lan gia tri B
a: \(A=\left(2\sqrt{5}-3\sqrt{5}+3\sqrt{5}\right)\cdot\sqrt{5}=2\sqrt{5}\cdot\sqrt{5}=10\)
\(B=\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}-1}+\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{\sqrt{x}+1}\)
\(=\sqrt{x}-1+\sqrt{x}=2\sqrt{x}-1\)
b: A=2B
=>\(10=4\sqrt{x}-2\)
=>\(4\sqrt{x}=12\)
=>x=9(nhận)
cho a>0;b>0va a+b\(\le\)\(4\)
tim gia tri nho nhat cua bieu thuc:A=\(\frac{2}{a^2+b^2}+\frac{35}{ab}+2ab\)
cho bieu thuc:A= \(\left(\frac{1}{x-1}+\frac{x}{x^3-1}.\frac{x^2+x+1}{x+1}\right):\frac{2x+1}{x^2+2x+1}\)
a,rút gọn biểu thức A ?
b,tính giá trị của biểu thức A khi x=1/2 ?
cho \(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=2\) ;\(\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=2\)
tinh gia tri bieu thuc:A=\(\left(\frac{a}{x}\right)^2+\left(\frac{b}{y}\right)^2+\left(\frac{c}{z}\right)^2\)
Cho bieu thuc
D=1/3 + 2/3^2 + 3/3^3 + ........+ 100/3^100 + 101/3^101
tinh gia tri cua bieu thuc:a, nam phan tam cong ba phan tam chia hai phan ba bang
b, mot phan bay muoi hai nhan mot tram bon muoi bon phan hai muoi ba cong mot phan bon muoi sau
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