Tim x de !2 x-3!- x=!2- x!
cho bieu thuc C = x^3 / x^2-4 -x/x-2 -2/x+2 cau a : tim gia tri cua x de bieu thuc C xac dinh cau b : tim x de C bang 0 cac c : tim gia tri nguyen cua x de C nhan gia tri duong
A = 2/ x-1 .tim dieu kien cua x de A la phan so . tim A khi x = 2 ; x = -3. tim dieu kien cua x de A la so nguyen ( A thuoc Z )
tim x de x-3 / 2-x=2/3
ta có \(\frac{x-3}{2-x}\)=\(\frac{2}{3}\)nên (x-3)3=(2-x)2
--->3x-9=4-2x
---->5x = 36 x =\(\frac{36}{5}\)
\(\frac{x-3}{2-x}=\frac{2}{3}\)
\(\Rightarrow\)\(3\left(x-3\right)\)\(=2\left(2-x\right)\)
\(\Rightarrow3x-9=4-2x\)
\(\Rightarrow3x+2x=4+9\)
\(\Rightarrow5x=13\)
\(\Rightarrow x=\frac{13}{5}\)
\(\frac{\sqrt{x}+1}{\sqrt{x}-2}+\frac{2\sqrt{x}}{\sqrt{x}+2}+\frac{2+5\sqrt{x}}{4-x}\)
a,rut gon
b,tim x de p duong
c,tim x de p = -5/2
d,tim x de p thuoc z
e,tim x de p >9/2
choP=(1/(x-2)-x^2/(8-x^3)*(x^2+2x+4)/(x+2)0/1/(x^2-4) tim DKXD va rut gon b tim Min p c tim x nguyen de p chia het cho x^2+1
bai1 :P=x+2/x+3-5/(x+3)(x-2)+1/2-x
a,Tim dkxd cua P
b,Rut gon bieu thuc P
c,tim x de P=-3/4
d,tim gia tri nguyen cua x de P cung co gia tri nguyen
e,tinh gia tri bieu thuc P khi x^2-9=0
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
1.Tìm x thuoc N de
x^2+2x-5 chia het cho x
2.tim x thuoc N de
x^2+x=132
3.tim x,y de
x^2+xy=5
4.tim a thuoc N de
a)a+10 chia het cho a-1
b)3a-6 chia hết cho 3a
Giúp mink với mink cần giúp rồi mink tick cho nhé
1.x=1;5
2.x=11
3.x=1;y=4
4.a)a=2;12 b)a=1;2
nho h cho minh nha
A=(x+1)/(x-2)+(x-1)/(x+2)+(x^2+3)/(4-x^2).tim x de A ko am
ĐKXĐ: \(x\ne\pm2\)
Ta có : \(A=\frac{x+1}{x-2}+\frac{x-1}{x+2}+\frac{x^2+3}{4-x^2}\)
\(=\frac{\left(x+1\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}+\frac{\left(x-1\right)\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{x^2+3}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x^2+3x+2}{\left(x-2\right)\left(x+2\right)}+\frac{x^2-3x+2}{\left(x-2\right)\left(x+2\right)}-\frac{x^2+3}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x^2+3x+2+x^2-3x+2-x^2-3}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x^2+1}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x^2+1}{x^2-4}\)
Vì \(x^2+1=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}>0\forall x\)
\(\Rightarrow\)Để A không âm thì \(x^2-4>0\)(do \(x\ne\pm2\)nên \(x^2-4\ne0\))
\(\Leftrightarrow x^2>4\)
\(\Leftrightarrow\orbr{\begin{cases}x>2\\x< -2\end{cases}}\)
Vậy để A không âm thì \(x>2\)hoặc \(x< -2\)