\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)

\(=\frac{5}{8}+\frac{1}{32}\)

\(=\frac{21}{32}\)

21/32

3/4 nha bạn đúng thì k mk nha

A=1/2+1/6+1/12+1/24+…+1/192+1/384

Giải

Ta có:

A x 2 =(1/2+1/6+1/12+1/24+…+1/192+1/384) x 2

A x 2 = 1 + 2/6 + 2/12 + 2/24 + ... + 2/192 + 2/384

Rút gọn ta được:

A x 2 = 1 + 1/3 + 1/6 + 1/12 + ... + 1/96 + 1/192

A x 2 - A = 1 + 1/3 + 1/6 + 1/12 + ... + 1/96 + 1/192 - (1/2+1/6+1/12+1/24+…+1/192+1/384)

A = 1 + 1/3 - 1/2 - 1/384

A = 5/6 - 1/384

A = 319/384

ĐS: 319/384

Sao đề bài là 1/3 còn khi làm là1/2 hả

Đặt A=\(1-\frac{1}{3}-\frac{1}{6}-\frac{1}{12}-\frac{1}{24}\)

3A=\(3-1-\frac{1}{3}-\frac{1}{6}-\frac{1}{12}\)

3A+A=\(3-\frac{1}{24}\)

4A=\(\frac{71}{24}\)

A=\(\frac{71}{24}:4\)

A=\(\frac{71}{96}\)

c=21/32

=\(\frac{3}{8}\) bn ak

= \(\frac{3}{8}\).

Đúng 100% luôn!

Ai tk cho mình mình tk lại.

a: \(=\dfrac{-5}{8}+\dfrac{7}{12}=\dfrac{-15}{24}+\dfrac{14}{24}=\dfrac{-1}{24}\)

b: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{11}{12}=\dfrac{9}{12}-\dfrac{10}{12}+\dfrac{11}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)

c: \(=\dfrac{6}{36}-\dfrac{1}{36}=\dfrac{5}{36}\)

d: \(=\dfrac{5}{12}+\dfrac{5}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)

e: \(=\dfrac{-8}{56}-\dfrac{7}{56}=\dfrac{-15}{56}\)

f: \(=\dfrac{-5}{15}+\dfrac{3}{25}=\dfrac{-25}{75}+\dfrac{9}{75}=\dfrac{-16}{75}\)

a)7/18                                                                                                                                                                                          b)23/24

a) 7/18

b) 3/8