-18/91 = -0,19...

-23/114 = -0,20...

mà 0,20...>0,19... nên -0,19... > -0.20...

vậy -18/91 > - 23/114

18/91<23/114

-18/91 lớn hơn -23/114

Nếu đúng thì tisk đúng nhé

ayo tôi trl cả 2 r

Xem lại đi

a)  ( -18/91) < (-18/90)=-1/5

-23/114 > -23/115= -1/5

Vậy -18/91 < -23/114

\(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}\)

\(\frac{23}{114}>\frac{23}{115}=\frac{1}{5}\)

=> \(\frac{18}{91}< \frac{23}{114}\)

\(\frac{21}{52}=\frac{210}{520}=1-\frac{310}{520}\)

\(\frac{213}{523}=1-\frac{310}{523}\)

Vì \(\frac{310}{520}>\frac{310}{523}\)=> \(1-\frac{310}{520}< 1-\frac{310}{523}\)

=> \(\frac{21}{52}< \frac{213}{523}\)

\(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}=\frac{23}{115}< \frac{23}{114}\)

\(=>\frac{18}{91}< \frac{23}{114}\)

 ok

ta co:

-18/91 va 23/-114

vi -18/91=-18:91 mot so am chia cho so duong 

con 23/-114=23:114 mot so duong chia cho so am

nen -18/91<23/-114

\(\text{a)}\)\(\frac{-18}{91}\)\(\text{và}\)\(\frac{-23}{114}\)

  \(\text{ Ta có :}\)\(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}=\frac{23}{115}< \frac{23}{114}\)

   \(\text{Do đó : }\)\(\frac{-18}{91}>\frac{-23}{114}\)

\(\text{b)}\)\(\frac{-22}{35}\)\(\text{và}\)\(\frac{-103}{177}\)

       \(\text{Ta có :}\)\(\frac{22}{35}=\frac{110}{175}>\frac{103}{125}>\frac{103}{177}\)

      \(\text{Do đó :}\)\(\frac{-22}{35}< \frac{-103}{177}\)

quy đồng mẫu 

-18 x  114=-2052

-23  x 91=-2093

vậy -18/91  > -23/114