a Ta có 

B= 1-2-3+4-5-6-7+8......+ 97 -98-99+100

  = ( 1-2-3+4)+ (5-6-7+8)+ .....+ ( 97-98-99+100)

=       0 +0+... +0 (25 cs 0)

=0 x25=0

a)B=0 

25 cs 0 là gì vậy ?

bai toan nay kho

Answer:

`B=1+3-5-7+9+11-....-397-399`

`=(1+3-5-7)+(9+11-13-15)+...+(393+395-397-399)`

`=(-8)+(-8)+...+(-8)`

`=(-8).100`

`=-800`

`C=1-2-3+4+5-6-7+...+97-98-99+100`

`=(1-2-3+4)+(5-6-7+8)+...+(97-98-99+100)`

`=0+0+...+0`

`=0`

\(D=2^{100}-2^{99}-2^{98}-...-2^2-2-1\)

\(\Rightarrow2D=2^{101}-2^{100}-2^{99}-...-2^3-2^2-2\)

\(\Rightarrow2D-D=\left(2^{101}-2^{100}-...-2^2-2\right)-\left(2^{100}-2^{99}-...-2-1\right)\)

\(\Rightarrow D=2^{101}-2^{100}-2^{100}+1\)

\(\Rightarrow D=2^{101}-2^{101}+1\)

\(\Rightarrow D=1\)

1. 1 + ( -2) +3 +(-4) + .........+ 19 + (-20)

= -1 + ( -1) +....+(-1)

= -1. 10

= -10

2. 1 – 2 + 3 – 4 + . . . + 99 – 100 

= ( -1) + (-1) +....+(-1)

= -1. 50

= -50

3. 2 – 4 + 6 – 8 + . . . + 48 – 50 

= (-2) + (-2) +....+ (-2)

= -2. 12 + 26

= -24 + 26

= 2

4. – 1 + 3 – 5 + 7 - . . . . + 97 – 99

= 2 + 2 +......+2

= 2.25

= 50

5. 1 + 2 – 3 – 4 + ... + 97 + 98 – 99 - 100

= (1+2-3-4) +......+ ( 97+98-99 -100)

= -4 . (-4).....(-4)

= -4. 25

= -100

Ta có : 

100² - 99² = ( 100 - 99 ) ( 100 + 99 ) =1 ( 100 + 99 ) = 99 + 100

98² - 97² = ( 98 - 97 ) ( 98 + 97 ) = 1.( 98 + 97 ) = 97 + 98

..........

2² - 1² = ( 2 - 1 ) ( 2 + 1 ) = 1 ( 2 + 1 ) = 1 + 2

=> 100² - 99² + 98² - 97 ² + ..... + 2² - 1² = 1 + 2 + 3 + ..... + 99 + 100 = 100.101/2 = 5050

Xem lại đề -....+ quy luật thay đổi ? thay đổi từ chỗ nào

\(B=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{99}{1}+\frac{98}{2}+...+\frac{2}{98}+\frac{1}{99}}\)

\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{98}{2}+1+\frac{97}{3}+1+...+\frac{2}{98}+1+\frac{1}{99}+1}\)

\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{100}{2}+\frac{100}{3}+...+\frac{100}{98}+\frac{100}{99}}\)

\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{100\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}\right)}=\frac{1}{100}\)

A= 99/1+98/2+...+2/98+1/99

<=>A= (99/1-98)+(98/2+1)+....+(2/98+1)+(1/99+1)

<=>A= 100/100+100/2+...+100/98+100/99

A= 100( 1/100+1/2+...+1/98+1/99)

Vậy B=1/100

-----------------------Good luck-------------------

B= \(\frac{1}{100}\)

2/  (1-2)+(3-4)+.....+(99-100)

=-1+(-1)+....+(-1) có 50 số -1

=-1x50

=-50

số số hạng là : (100-1):1+1=100 số

suy ra ta chia thành 50 nhóm

=(1-2)+(3-4)+....+(99-100)         

=-1+(-1)+....+(-1)          (25 số)

=-1.25

=-25

nhớ tích mh nha bạn