Tính nhanh
3*2017+9*2017+20*2017+28*2017+38*2017+2017*2017
Những câu hỏi liên quan
so sánh A=2017^37+2016^2017+1/2017^38 và 2017^38+2016^2017+2/2017^39
So sánh
A=(2017^37+2016^2017+1)/2017^38
B=(2017^38+2016^2017+2)/2017^39
Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Chứng minh rằng
\(\frac{\sqrt[2016]{9}+\sqrt[2016]{16}+\sqrt[2016]{25}}{\sqrt[2016]{12}+\sqrt[2016]{15}+\sqrt[2016]{20}}>\frac{\sqrt[2017]{12}+\sqrt[2017]{15}+\sqrt[2017]{20}}{\sqrt[2017]{9}+\sqrt[2017]{16}+\sqrt[2017]{25}}\)
(x+17)+-(24+35)
(-32)-(y+20)+20
(3567-214)-3567
(-2017)-(28-2017)
(-269-357)+(269-357)
(123+345)+(456-123)-[2017-(-345)]
cho x + y + z = 2017
x , y , z khác 0
1 / x + 1 /y + 1/z = 1 / 2017
tính S = ( x^5 - 2017^5 ) * ( y^7 - 2017^7 ) * ( z^9 - 2017^9 )
2017^10 +1 / 2017^9 +1 và 2017^11 +1 / 2017^10+1
Tính nhanh
a) 2017 x 34 + 2017 x 65 + 2017
b) 3/5 x 7/9 - 3/5 x 2/9
a) 2017 x 34 + 2017 x 65 + 2017
= 2017 x ( 34+65+1)
= 2017 x 100
= 201700
b) 3/5 x 7/9 - 3/5 x 2/9
= 3/5 x ( 7/9- 2/9)
= 3/5 x 5/9
= 1/3
Đúng 3
Bình luận (0)
a) 2017 x 34 + 2017 x 65 + 2017
= 2017 x (34 + 65 + 1)
= 2017 x 100
= 201700
b) \(\dfrac{3}{5}\) x \(\dfrac{7}{9}\) - \(\dfrac{3}{5}\) x \(\dfrac{2}{9}\)
= \(\dfrac{3}{5}\) x \(\left(\dfrac{7}{9}-\dfrac{2}{9}\right)\)
= \(\dfrac{3}{5}\) x \(\dfrac{5}{9}\)
= \(\dfrac{1}{3}\)
Đúng 1
Bình luận (0)
\(a,=2017\times\left(34+65+1\right)=2017\times100=201700\)
\(b,\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{15}{45}=\dfrac{1}{3}\)
Đúng 1
Bình luận (0)
Xem thêm câu trả lời
a^2017+b^2017/c^2017+c^2017=a^2017-b^2017/c^2017-d^2017
so sánh A=2017^2017+2/2017^2017-1 và B=2017^2017/2017^2017-3