x + 90 = 360 + 30
( 2x + 13 ) : 5 = 17
360 : ( 11x - 7 ) = 90
30 : ( 3x - 7 ) = 15
\(\left(2x+13\right):5=17\)
\(\Rightarrow2x+13=17.5\)
\(\Rightarrow2x+13=85\)
\(\Rightarrow2x=85-13\)
\(\Rightarrow2x=72\Rightarrow x=\frac{72}{2}=36\)
\(360:\left(11x-7\right)=90\)
\(11x-7=\frac{360}{90}\)
\(\Rightarrow11x-7=4\)
\(\Rightarrow11x=4+7=11\)
\(\Rightarrow x=\frac{11}{11}=1\)
\(30:\left(3x-7\right)=15\)
\(\Rightarrow3x-7=\frac{30}{15}=2\)
\(\Rightarrow3x=2+7=9\)
\(\Rightarrow x=\frac{9}{3}=3\)
a,\(\left(2x+13\right):5=17\)
\(2x+13=17.5\)
\(2x=72\)
\(x=72:2\)
\(x=36\)
b,\(360:\left(11x-7\right)=90\)
\(11x-7=4\)
\(11x=11\)
\(x=1\)
c,\(30:\left(3x-7\right)=15\)
\(3x-7=2\)
\(3x=9\)
\(x=3\)
(2x + 13): 5 =17
2x + 13=85
2x=72
x=36
360 :(11x -7)=90
11x - 7=4
11x=11
x=1
30 : (3x - 7)=15
3x-7=2
3x=9
x=3
360:(x-7)=90
360:(x-7)=90
(x-7)=360:90
(x-7)=4
x=4+7
x=11
(x+13):5=12
360:(x-7)=90
360 : (x-7 ) = 90
( x - 7 ) = 360 : 90
x - 7 = 4
x = 4 + 7
x = 11
y + 60 = 360 + 90
y - 60 = 360 - 90
y + 60 = 360 + 90
y + 60 = 450
y = 450 - 60
y = 390
y - 60 = 360 - 90
y - 60 = 270
y = 270 + 60
y = 330
y + 60 = 360 + 90
y + 60 = 450
y = 450 - 60
y = 390
y - 60 = 360 - 90
y - 60 = 270
y = 270 + 60
y = 330
y+60=360+90
y+60=450
y =450-60
y =390.
y-60=360-90
y-60=270
y =270+60
y =330.
x x 30 = 360
x x 30 = 360
x = 360 : 30
x = 12
Tích nha!
x x 30 =360
x = 360 :30
x = 12 ai tk mk mk tk lai
360/x + 180/x+5 = 30/60
360/X + 180/X + 5 = 30/60
=> 2.180/X + 180/X + 5 = 1/2
=> 3.180/X = 1/2 -5 =-9/2
=> 540/X = -9/2
=> X = -540.2/9
=> X = -120
15+x+27+53=201
50*x+20617=80617
X*25+x*35=90*360
a) 15 + x + 27 + 53 = 201
=> x + ( 15 + 27 + 53 ) = 201
=> x + 95 = 201
=> x = 201 - 95
=> x = 106
Vậy x = 106
b) 50 * x + 20 617 = 80 617
=> 50 * x = 80 617 - 20 617
=> 50 * x = 60 000
=> x = 60 000 : 50
=> x = 1 200
Vậy x = 1 200
c) x * 25 + x * 35 = 90 * 360
=> x * ( 25 + 35 ) = 32 400
=> x * 60 = 32 400
=> x = 32 400 : 60
=> x = 540
Vậy x = 540
Tìm các giá trị lượng giác còn lại biết:
a) Cho sin \(x=-\dfrac{4}{5}\)và \(90^o< x< 180^o\)
b) Cho \(\sin x=\dfrac{\sqrt{3}}{2}\)và \(270^o< x< 360^o\)
c) Cho \(\cos x=-\dfrac{1}{3}\)và \(0^o< x< 90^o\)
a: Sửa đề: sin x=4/5
cosx=-3/5; tan x=-4/3; cot x=-3/4
b: 270 độ<x<360 độ
=>cosx>0
=>cosx=1/2
tan x=căn 3; cot x=1/căn 3
Chọn dấu thích hợp điền vào chỗ chấm: 23875 - 360 x 40 ... 1234 + 258 x 30
A. =
B. <
C. >
Ta có:
23875−360×40=23875−14400=9475
1234+258×30=1234+7740=8974
Mà: 9475>8974
Vậy: 23875−360×40>1234+258×30.
Đáp án C