Tính:
`1) (2/3)^4 :2^4`
`2) (2/3)^4 .9^2`
`3) (1/2)^3 . (1/4)^2`
`4) 120^6/40^3`
`5) 390^4/130^3`
Những câu hỏi liên quan
Thực hiện phép tính :
a) 40^4 / 120^4 : 130^3 / 390^3
b) (-2/5)^6 . (-2/5)^4 - (3/4)^3 . (4/3)^3
\(1.\)Tính
\(a)\frac{120^3}{40^3};\frac{390^4}{130^4};\frac{3^2}{0,375^2}\)
\(2.\)Tính giá trị các biểu thức sau :
\(a)\frac{45^{10}.5^{20}}{75^{15}}\) ; \(b)\frac{\left(0,8\right)^5}{\left(0,4\right)^6}\) ; \(c)\frac{2^{15}.9^4}{6^6.8^3}\)
1. sai dấu nhé
2.a, \(\frac{45^{10}.5^{20}}{75^{15}}=\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(5^2.3\right)^{15}}=\frac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)
b, \(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}=\frac{\left(\frac{4}{5}\right)^5}{\left(\frac{2}{5}\right)^6}=\frac{\left(\frac{2}{5}\cdot2\right)^5}{\left(\frac{2}{5}\right)^6}=\frac{\left(\frac{2}{5}\right)^5\cdot2^5}{\left(\frac{2}{5}\right)^5\cdot\frac{2}{5}}=2^5\div\frac{2}{5}=32\cdot\frac{5}{2}=80\)
c, \(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^2}{2^{15}}=3^2=9\)
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tính giá trị biểu thức(hợp li nếu có):
A=((5^2+55)-30).2+120
B=80.72-36.(-17)+36.23
C=1,25+3/1/9+2/1/21+4,75+3/1/4+2/3/4
D=((10/15-2/3):1/7).0,15-1/4
E=((40/130-12/13).40%+0,15):(-5/52)
tính
\(\frac{120^3}{40^3}\)
\(\frac{390^4}{130^4}\)
\(\frac{3^2}{\left(0,375\right)^2}\)
Các bạn giải gấp gìum mình nha viết cụ thể ra nha
1. Tính
123^3/ 40^3
390^4 / 130^4
3^2 / (0,375)^2
Tính:
(1/5)^5 . 5^3(0,125)^3 . 512(0,25)^4 . 1024120^3/40^3390^3/130^4
Tính nhanh nếu có thể: b)B=5/2 + 6/-11 + 3/8 - 7/2 + 6/8 + -5/11 c)C=4/3 + 3/5 +7/3 + 2/5 - -1/3 d)D=-5/6 . 4/19 + -7/12 . 4/19 - 40/57 e)E=1/3 . 4/5 + 1/-3 . 9/5 + 2/3
b: \(B=\dfrac{5}{2}-\dfrac{7}{2}+\dfrac{3}{8}+\dfrac{6}{8}+\dfrac{-6}{11}-\dfrac{5}{11}=-2-1+\dfrac{9}{8}=\dfrac{9}{8}-3=-\dfrac{15}{8}\)
c: \(C=\left(\dfrac{4}{3}+\dfrac{7}{3}+\dfrac{1}{3}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=4+1=5\)
d: \(D=\dfrac{4}{19}\left(\dfrac{-5}{6}-\dfrac{7}{12}\right)-\dfrac{40}{57}\)
\(=\dfrac{4}{19}\cdot\dfrac{-17}{12}-\dfrac{40}{57}=-1\)
e: \(E=\dfrac{1}{3}\left(\dfrac{4}{5}-\dfrac{9}{5}\right)+\dfrac{2}{3}=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
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a) \(\dfrac{120^3}{40^3}\);
b) \(\dfrac{390^4}{130^4}\);
c) \(\dfrac{3^2}{\left(0,375\right)^2}\)
Giải:
a) \(\dfrac{120^3}{40^3}=\left(\dfrac{120}{40}\right)^3=30^3=2700\)
b) \(\dfrac{390^4}{130^4}=\left(\dfrac{390}{130}\right)^4=30^4=810000\)
c) \(\dfrac{3^2}{\left(0,375\right)^2}=\left(\dfrac{3}{0,375}\right)^2=8^2=64\)
Đáp số: a) 2700; b) 810000; c) 64.
Chúc bạn học tốt!!!
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1)180 : 12 - 3 mũ 2 2)2 . 5 mũ 2 - 36 : 3 mũ 2 3) 3 mũ 3 . 19 - 3 mũ 3 . 12 4) 3 . 5 mũ 2 - 16 : 2 mũ 2 5) 20 - [ 30 - ( 5 - 1) mũ 2] 6) ( 51 . 63 - 37 . 51) : 51 7) 120 - [130 - (5 - 1) mũ 3] 8) 150 - [ 10 mũ 2 -( 14 - 11 ) mũ 2 . 2007 mũ 0] 9) 3 mũ 2 . ( 200 : 4 + 13. 5 ) - 3 mũ 2 . 15 10) 25 . { 610 : [ 600 - ( 260 + 5.7) ] } 11) 2 mũ 2 + [ 10 mũ 5 : 10 mũ 4 -( 2 + 3.2) ] 12) 3 mũ 4 + [ 75 : 15 + ( 10 - 8 ) mũ 4 + 5 mũ 3 13) 130 - 2 . [ ( 30 + 15 ) : 3 + 6]
Đọc tiếp
1)180 : 12 - 3 mũ 2 =
2)2 . 5 mũ 2 - 36 : 3 mũ 2 =
3) 3 mũ 3 . 19 - 3 mũ 3 . 12 =
4) 3 . 5 mũ 2 - 16 : 2 mũ 2 =
5) 20 - [ 30 - ( 5 - 1) mũ 2] =
6) ( 51 . 63 - 37 . 51) : 51 =
7) 120 - [130 - (5 - 1) mũ 3] =
8) 150 - [ 10 mũ 2 -( 14 - 11 ) mũ 2 . 2007 mũ 0] =
9) 3 mũ 2 . ( 200 : 4 + 13. 5 ) - 3 mũ 2 . 15 =
10) 25 . { 610 : [ 600 - ( 260 + 5.7) ] } =
11) 2 mũ 2 + [ 10 mũ 5 : 10 mũ 4 -( 2 + 3.2) ] =
12) 3 mũ 4 + [ 75 : 15 + ( 10 - 8 ) mũ 4 + 5 mũ 3 =
13) 130 - 2 . [ ( 30 + 15 ) : 3 + 6]
22.32.5:22.3-32=3.5-32=15-9=62.52-22.32:32=2.(52-2)=2.(25-2)=46
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3. 33.19-33.12=33.(19-12)=33.7=189
4. 3.52-16:22=3.52-24:22=3.25-4=75-4=71
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Tính :
C= 1/5+1/10+1/20+1/40+...+1/1280D= 2/1*3+2/3*5+2/5*10+2/7*9+2/9*11+2/11*18+2/13*15E= 4/3*7+4/7*11+4/11*15+4/15*19+4/19*23+4/23*27G= 1/2+1/6+1/12+1/20+1/30+1/42+...+1/110H= 3/1*2+3/2*3+3/3*4+3/4*5+...+3/9*10Giúp mk nha *.*
1)C= 1/5+1/10+1/20+1/40+...+1/1280
\(=\frac{1}{5}\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^8}\right)\)
Đặt cái trong ngoặc là A ta có:\(2A=2+1+...+\frac{1}{2^7}\)
\(2A-A=\left(2+1+...+\frac{1}{2^7}\right)-\left(1+\frac{1}{2}+...+\frac{1}{2^8}\right)\)
\(A=2-\frac{1}{2^8}\).Thay A vào ta được:\(C=\frac{1}{5}\left(2-\frac{1}{2^8}\right)=\frac{1}{5}\cdot\frac{511}{256}=\frac{511}{1280}\)
2)D= 2/1*3+2/3*5+2/5*10+2/7*9+2/9*11+2/11*18+2/13*15
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}\)
\(=1-\frac{1}{15}\)
\(=\frac{14}{15}\)
3)E= 4/3*7+4/7*11+4/11*15+4/15*19+4/19*23+4/23*27
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}\)
\(=\frac{1}{3}-\frac{1}{27}\)
\(=\frac{8}{27}\)
4)G= 1/2+1/6+1/12+1/20+1/30+1/42+...+1/110
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{10.11}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{10}-\frac{1}{11}\)
\(=1-\frac{1}{11}\)
\(=\frac{10}{11}\)
5)H= 3/1*2+3/2*3+3/3*4+3/4*5+...+3/9*10
\(=3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=3\left(1-\frac{1}{10}\right)\)
\(=3\times\frac{9}{10}\)
\(=\frac{27}{10}\).Lần sau bạn đăng ít một thôi nhé
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