tim x
(x+1)+(x+3)+(x+5)=100
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100x + y = x.y
=> xy - x - y = 0
=> (xy - x) - y + 1 = 1
=> x(y - 1) - (y - 1) = 1
=> (x - 1)(y - 1) = 1
=> x - 1 = y - 1 = 1 hoặc x - 1 = y - 1 = -1
=> x = y = 2 hoặc x = y = 0
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
tim x biet 3/5 - 1/4 : x = 25/100
3/5-1/4:x=25/100
1/4:x=25/100+3/5
1/4:x=17/20
x=17/20x1/4
x=17/80
Vậy x=17/80
3/5-1/4:x=25/100
tim x
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{1}{4}:\frac{7}{20}\)
\(x=\frac{1}{4}.\frac{20}{7}\)
\(x=\frac{5}{7}\)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{1}{4}:\frac{7}{20}\)
\(x=\frac{5}{7}\)
tim x giup to voi 1+3+5+7+....+x =100
x = 100 : 5 - 1
x = 20 - 1
x = 19
Vậy x = 19
1+3+5+7+...+x=100 Tim x
Tổng của n số tự nhiên lẻ chính bằng bình phương của n số đó.
nên ta có
1+3+5+7+...+x=100
<=> n^2=100
<=> n=10
Vậy x=19
Tim x:
a) 6 x X - 5 = 613 b) 12 x X + 3 x X = 30
C) 125 - 25 x (X - 1) = 100 d) ( X - 2 ) x 9 X - 4) = 0
`#040911`
`a)`
`6 \times x - 5 = 613`
`=> 6 \times x = 613 + 5`
`=> 6 \times x = 618`
`=> x = 618 \div 6`
`=> x = 103`
Vậy, `x = 103`
`b)`
`12 \times x + 3 \times x = 30`
`=> x \times (12 + 3) = 30`
`=> x \times 15 = 30`
`=> x = 30 \div 15`
`=> x = 2`
Vậy, `x = 2`
`c)`
`125 - 25 \times (x - 1) = 100`
`=> 25 \times (x - 1) = 125 - 100`
`=> 25 \times (x - 1) = 25`
`=> x - 1 = 25 \div 25`
`=> x - 1 = 1`
`=> x = 1 + 1`
`=> x = 2`
Vậy, `x = 2`
`d)`
`(x - 2) \times (9x - 4) = 0?`
`=>`
TH1: `x - 2 = 0`
`=> x = 0 + 2`
`=> x = 2`
TH2: `9x - 4 = 0`
`=> 9x = 4`
`=> x = 4/9`
Vậy, `x \in {2; 4/9}.`
\(a,6x-5=613\\ \Leftrightarrow6x=618\\ \Leftrightarrow x=103\\ b,12x+3x=30\\ \Leftrightarrow15x=30\\ \Leftrightarrow x=2\\ c,125-25\left(x-1\right)=100\\ \Leftrightarrow25\left(x-1\right)=25\\ \Leftrightarrow x-1=1\\ \Leftrightarrow x=2\\ d,\left(x-2\right)\cdot\left(9x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{4}{9}\end{matrix}\right.\)
tim x biet
1) 23x-1=32
2) 4.52x=5^7-5^6
3) x3(x2-1)=0
4) x100=x48
5) x100=x
6) x100=x2
7) (x-2015)2105=1
8) 100(x-3).(x-2)=1
1) Tim x biet :
a) - 12 (x - 5) + 7 . (3 - x) = 5
b) 30 . (x + 2) - 6 . (x - 5) - 24x = 100