\(\dfrac{58}{21}=2\dfrac{16}{21}=2+\dfrac{16}{21}=2+\left(1-\dfrac{5}{21}\right)=3-\dfrac{5}{21}\)

\(\dfrac{61}{22}=2\dfrac{17}{22}=2+\dfrac{17}{22}=2+\left(1-\dfrac{5}{22}\right)=3-\dfrac{5}{22}\)

Ta có

\(\dfrac{5}{21}>\dfrac{5}{22}\Rightarrow3-\dfrac{5}{21}< 3-\dfrac{5}{22}\Rightarrow\dfrac{58}{61}< \dfrac{61}{22}\)

\(\dfrac{8}{9}\) < \(\dfrac{7}{5}\) , vì :

\(\dfrac{8}{9}\) < 1 , \(\dfrac{7}{5}\) > 1

8/9 < 7/5 

Vì \(\dfrac{8}{9}\) 75 nên \(\dfrac{8}{9}< \dfrac{7}{5}\)

2002/2004= 1 - 2/2004

2004/2006= 1 - 2/2006

Vì: 2/2004> 2/2006 

nên: 1 - 2/2004 < 1 - 2/2006

Vậy: 2002/2004 < 2004/2006

\(A=\dfrac{2002}{2004}=\dfrac{2004-2}{2004}=1-\dfrac{2}{2004}\)

\(B=\dfrac{2004}{2006}=\dfrac{2006-2}{2006}=1-\dfrac{2}{2006}\)

Vì \(\dfrac{2}{2004}>\dfrac{2}{2006}\)  (So sánh 2 phân số cùng tử)

Nên A < B

A=20042002​=20042004−2​=1−20042​

B=20042006=2006−22006=1−22006B=20062004​=20062006−2​=1−20062​

Vì 22004>2200620042​>20062​  (So sánh 2 phân số cùng tử)

Nên A < B

ko hiểu

=90033

sai rồi bạn ơi 

12 48   =   9 36

\(\frac{2000}{2001}=1-\frac{1}{2001}\)

\(\frac{2001}{2002}=1-\frac{1}{2002}\)

\(2001< 2002\Rightarrow\frac{1}{2001}>\frac{1}{2001}\)

                             \(\Rightarrow1-\frac{1}{2001}< 1-\frac{1}{2002}\)

                              \(\Rightarrow\frac{2000}{2001}< \frac{2001}{2002}\)

ta có:2000/2001=1-1/2001

2001/2002=1-1/2002

mà 2001<2002

suy ra 1/2001>1/2002

suy ra 1-1/2001<1-1/2002

vậy 2000/2001<2001/2002

Trả lời:

Ta có: \(\frac{2000}{2001}=\frac{2001-1}{2001}=\frac{2001}{2001}-\frac{1}{2001}=1-\frac{1}{2001}\)

          \(\frac{2001}{2002}=\frac{2002-1}{2002}=\frac{2002}{2001}-\frac{1}{2002}=1-\frac{1}{2002}\)

Ta thấy: \(2001< 2002\)

\(\Leftrightarrow\frac{1}{2001}>\frac{1}{2002}\)

\(\Leftrightarrow-\frac{1}{2001}< -\frac{1}{2002}\)

\(\Leftrightarrow1-\frac{1}{2001}< 1-\frac{1}{2002}\)

\(\Leftrightarrow\frac{2000}{2001}< \frac{2001}{2002}\)

Vậy ....

\(\frac{43}{171}\)và \(\frac{45}{169}\)Phân số trung gian là: \(\frac{43}{169}\)

Ta thấy: \(\frac{43}{171}\)< \(\frac{43}{169}\)< \(\frac{45}{169}\)nên \(\frac{43}{171}\)< \(\frac{45}{169}\)

tk nhé

Ta có:\(\frac{43}{171}< \frac{43}{169}\)

Mà \(\frac{43}{169}< \frac{45}{169}\Rightarrow\frac{43}{171}< \frac{45}{169}\)