\(\sqrt{9999999999999999992}+\sqrt{\frac{12\cdot124}{123456}}-\frac{1}{2}\)
Những câu hỏi liên quan
\(\frac{1}{\sqrt{3}+\sqrt{2}}-\frac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}\)
\(\frac{1}{\sqrt{3+2\sqrt{2}}}+\frac{1}{\sqrt{5+2\sqrt{6}}}+\frac{1}{\sqrt{7+2\sqrt{12}}}+...+\frac{1}{\sqrt{199+2\sqrt{9900}}}\)
Rút gọn :Bfrac{6-6sqrt{3}}{1-sqrt{3}}+frac{3sqrt{3}+3}{sqrt{3}+1}Cfrac{3+sqrt{3}}{sqrt{3}}+frac{sqrt{6}-sqrt{3}}{1-sqrt{2}}Dfrac{sqrt{10}-sqrt{2}}{sqrt{5}-1}+frac{2-sqrt{2}}{sqrt{2}-1}Efrac{sqrt{15}-sqrt{12}}{sqrt{5}-2}+frac{1}{2-sqrt{3}}Fleft(frac{15}{sqrt{6}+1}+frac{4}{sqrt{6}-2}-frac{12}{3-sqrt{6}}right)left(sqrt{6}+11right)
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Rút gọn :
\(B=\frac{6-6\sqrt{3}}{1-\sqrt{3}}+\frac{3\sqrt{3}+3}{\sqrt{3}+1}\)
\(C=\frac{3+\sqrt{3}}{\sqrt{3}}+\frac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}\)
\(D=\frac{\sqrt{10}-\sqrt{2}}{\sqrt{5}-1}+\frac{2-\sqrt{2}}{\sqrt{2}-1}\)
\(E=\frac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\frac{1}{2-\sqrt{3}}\)
\(F=\left(\frac{15}{\sqrt{6}+1}+\frac{4}{\sqrt{6}-2}-\frac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)
B=\(\frac{6-6\sqrt{3}}{1-\sqrt{3}}+\frac{3\sqrt{3}+3}{\sqrt{3}+1}=\frac{6\left(1-\sqrt{3}\right)}{1-\sqrt{3}}+\frac{3\left(\sqrt{3}+1\right)}{\sqrt{3}+1}=6+3=9\)
C=\(\frac{3+\sqrt{3}}{\sqrt{3}}+\frac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}=\frac{3\left(1+\sqrt{3}\right)}{\sqrt{3}}+\frac{\sqrt{3}\left(\sqrt{2}-1\right)}{1-\sqrt{2}}=\sqrt{3}+1-\sqrt{3}=1\)
D=\(\frac{\sqrt{10}-\sqrt{2}}{\sqrt{5}-1}+\frac{2-\sqrt{2}}{\sqrt{2}-1}=\frac{\sqrt{2}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}+\frac{\sqrt{2}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}=\sqrt{2}+\sqrt{2}=2\sqrt{2}\)
E=\(\frac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\frac{1}{2-\sqrt{3}}=\frac{\sqrt{3}\left(\sqrt{5}-2\right)}{\sqrt{5}-2}+\frac{1}{2-\sqrt{3}}=\sqrt{3}+\frac{1}{2-\sqrt{3}}=\frac{2\sqrt{3}-1}{2-\sqrt{3}}\)
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Tính:Afrac{frac{sqrt{2+sqrt{3}}}{2}}{frac{sqrt{2+sqrt{3}}}{2}-frac{2}{sqrt{16}}+frac{sqrt{2+sqrt{3}}}{2sqrt{3}}}Bfrac{2left(frac{sqrt{2}+sqrt{3}}{6sqrt{2}}right)^{-1}+3left(frac{sqrt{2}+sqrt{3}}{4sqrt{3}}right)^{-1}}{left(frac{2+sqrt{16}}{12}right)^{-1}+left(frac{3+sqrt{6}}{12}right)^{-1}} P/s: Đề phức tạp vlin nên thớt giải k nổi :)) Pro nào giúp em dí ~
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Tính:
\(A=\frac{\frac{\sqrt{2+\sqrt{3}}}{2}}{\frac{\sqrt{2+\sqrt{3}}}{2}-\frac{2}{\sqrt{16}}+\frac{\sqrt{2+\sqrt{3}}}{2\sqrt{3}}}\)\(B=\frac{2\left(\frac{\sqrt{2}+\sqrt{3}}{6\sqrt{2}}\right)^{-1}+3\left(\frac{\sqrt{2}+\sqrt{3}}{4\sqrt{3}}\right)^{-1}}{\left(\frac{2+\sqrt{16}}{12}\right)^{-1}+\left(\frac{3+\sqrt{6}}{12}\right)^{-1}}\)P/s: Đề phức tạp vlin nên thớt giải k nổi :)) Pro nào giúp em dí ~
1) Rút gọn:
a) \(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}\)
b) \(\frac{5}{12\left(2\sqrt{5}+3\sqrt{2}\right)}-\frac{5}{12\left(2\sqrt{5}-3\sqrt{2}\right)}\)
2) Tính A:
A = \(\frac{1}{1-\sqrt{2}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{4}}-...+\frac{1}{\sqrt{99}-\sqrt{100}}-\frac{1}{\sqrt{100}-\sqrt{101}}\)
a) \(\sqrt{3+\sqrt{5}}\)\(-\sqrt{3-\sqrt{5}}\)\(=\frac{\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}}{\sqrt{2}}\)
\(=\frac{\sqrt{\left(\sqrt{5}+1\right)^2}-\sqrt{\left(\sqrt{5}-1\right)^2}}{\sqrt{2}}\)\(=\frac{\left|\sqrt{5}+1\right|-\left|\sqrt{5}-1\right|}{\sqrt{2}}\)\(=\)\(\frac{\sqrt{5}+1-\sqrt{5}+1}{\sqrt{2}}\)\(=\frac{2}{\sqrt{2}}=\sqrt{2}\)
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thực hiện phép tính:
a) \(-\sqrt{27}+6\sqrt{\frac{1}{3}}-\sqrt{12}\)
b) \(\sqrt{\frac{72}{9}}:\sqrt{18}-\frac{5}{6}\)
c) \(\frac{2}{3}\sqrt{3}-\frac{1}{4}\sqrt{18}+\frac{2}{5}\sqrt{2}-\frac{1}{4}\sqrt{12}\)
\(\frac{1}{\sqrt{16}-\sqrt{15}}-\frac{1}{\sqrt{15}-\sqrt{14}}+\frac{1}{\sqrt{14}-\sqrt{13}}-\frac{1}{\sqrt{13}-\sqrt{12}}+\frac{1}{\sqrt{12}-\sqrt{11}}-\frac{1}{\sqrt{11}-\sqrt{10}}+\frac{1}{\sqrt{10}-\sqrt{9}}\)
Với n > 0 Ta có:
\(\frac{1}{\sqrt{n+1}-\sqrt{n}}=\frac{\sqrt{n+1}+\sqrt{n}}{\left(\sqrt{n+1}-\sqrt{n}\right)\left(\sqrt{n+1}+\sqrt{n}\right)}=\frac{\sqrt{n+1}+\sqrt{n}}{n+1-n}\)
\(=\sqrt{n+1}+\sqrt{n}\)
\(\Rightarrow\frac{1}{\sqrt{16}-\sqrt{15}}-\frac{1}{\sqrt{15}-\sqrt{14}}+...+\frac{1}{\sqrt{10}-\sqrt{9}}\)
\(=\sqrt{16}+\sqrt{15}-\sqrt{15}-\sqrt{14}+...+\sqrt{10}+\sqrt{9}\)
\(\sqrt{16}+\sqrt{9}=3+4=7\)
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Tính 1. Afrac{frac{sqrt{2+sqrt{3}}}{2}}{frac{sqrt{2+sqrt{3}}}{2}-frac{2}{sqrt{16}}+frac{sqrt{2+sqrt{3}}}{2sqrt{3}}}2. Bfrac{2left(frac{sqrt{2}+sqrt{3}}{6sqrt{2}}right)^{-1}+3left(frac{sqrt{2}+sqrt{3}}{4sqrt{3}}right)}{left(frac{2+sqrt{6}}{12}right)^{-1}+left(frac{3+sqrt{6}}{12}right)^{-1}}P/s: Đề phức tạp vlin nên ứ làm đc đành phải nhờ mấy pro giúp :)) Tks nhìu nha 3
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Tính
1. \(A=\frac{\frac{\sqrt{2+\sqrt{3}}}{2}}{\frac{\sqrt{2+\sqrt{3}}}{2}-\frac{2}{\sqrt{16}}+\frac{\sqrt{2+\sqrt{3}}}{2\sqrt{3}}}\)
2. \(B=\frac{2\left(\frac{\sqrt{2}+\sqrt{3}}{6\sqrt{2}}\right)^{-1}+3\left(\frac{\sqrt{2}+\sqrt{3}}{4\sqrt{3}}\right)}{\left(\frac{2+\sqrt{6}}{12}\right)^{-1}+\left(\frac{3+\sqrt{6}}{12}\right)^{-1}}\)
P/s: Đề phức tạp vlin nên ứ làm đc đành phải nhờ mấy pro giúp :)) Tks nhìu nha <3
9 tháng 8 2020 lúc 8:01
\(\frac{2}{\sqrt{3}}+\frac{\sqrt{2}}{3}+\frac{2}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
\(\frac{2}{\sqrt{3}}+\frac{\sqrt{2}}{3}+\frac{2}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}=\frac{2\sqrt{3}}{3}+\frac{\sqrt{2}}{3}+\frac{2\sqrt{3}}{3}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
\(=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\sqrt{12}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\sqrt{12\left(\frac{5}{12}-\frac{1}{\sqrt{6}}\right)}\)
\(=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\sqrt{5-2\sqrt{6}}=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\cdot\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\)
\(=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\left|\sqrt{3}-\sqrt{2}\right|=\frac{2\sqrt{3}+\sqrt{2}}{3}+\frac{1}{3}\left(\sqrt{3}-\sqrt{2}\right)\)(vì \(\sqrt{3}-\sqrt{2}>0\))
\(=\frac{2\sqrt{3}+\sqrt{2}+\sqrt{3}-\sqrt{2}}{3}=\sqrt{3}\)
\(\frac{2}{\sqrt{3}}+\frac{\sqrt{2}}{3}+\frac{2}{\sqrt{3}}.\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
