96 – 3(x + 1) = 42

    3(x + 1) = 96 - 42

    3(x + 1) = 54

    x + 1 = 54:3

    x + 1 = 18

    x = 18 - 1

    x = 17

Vậy x = 17

96 - 3 ( x + 1 ) = 42 

3 ( x + 1 ) = 96 - 42 

3 ( x + 1 ) = 54 

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17  

\(96-3\left(x+1\right)=42\)

\(\Rightarrow3\left(x+1\right)=96-42=54\)

\(\Rightarrow x+1=54:3=18\)

\(\Rightarrow x=17\)

96 - 3(x - 1) = 42   

        3(x -1) = 96 - 42

        3(x - 1) = 54

        x - 1      = 54 :3

           x - 1   = 18

         x = 18 + 1

x = 19

\(96-3.\left(x+1\right)=42\)

\(3.\left(x+1\right)=96-42\)

\(3.\left(x+1\right)=54\)

\(x+1=54\div3\)

\(x+1=18\)

\(x=18-1\)

\(x=17\)

`[ ( 2 xx x - 11 ) : 3 + 1 ] xx 5 = 20`

`( 2 xx x - 11 ) : 3 + 1=20:5`

`( 2 xx x - 11 ) : 3 + 1=4`

`( 2 xx x - 11 ) : 3 =4-1`

`( 2 xx x - 11 ) : 3 =3`

`2xx x -11=3xx3`

`2xx x -11=9`

`2xx x =9+11`

`2 xx x=20`

`x=20:2`

`x=10`

Vậy `x=10`

`b,  x - 96 = ( 443 - x ) - 15`

`x-96=443-x-15`

` x+x=443-15+96`

`2x=524`

`x=524:2`

`x= 262`

Vậy `x=262`

\(#Nqoc\)

`a)`

\([ ( 2 \times x - 11 ) \div 3 + 1 ] \times 5 = 20\)

`(2 \times x - 11) \div 3 + 1 = 20 \div 5`

`(2 \times x - 11) \div 3 + 1 = 4`

`(2 \times x - 11) \div 3 = 4  - 1`

`(2 \times x - 11) \div 3 = 3`

`2 \times x - 11 = 3 \times 3`

`2 \times x - 11 = 9`

`2 \times x = 9 + 11`

`2 \times x = 20`

`x = 20 \div 2`

`x = 10`

Vậy, `x = 10`

`b)`

\(x - 96 = ( 443 - x ) - 15\)

`x - 96 = 443 - x - 15`

`x - 96 = 428 - x`

`x = 428 - x + 96`

`x = 524 - x`

`x - 524 + x = 0`

`(x + x) - 524 = 0`

`2x - 524 = 0`

`2x = 524`

`x = 524 \div 2`

`x = 262`

Vậy, `x = 262.` 

3( x + 23 ) + 6 = 96

3 ( x + 23 )      = 96 - 6

3 ( x + 23 )      = 90

     x + 23        = 90 : 3

     x + 23        = 30

     x                = 30 - 23

     x                = 7

3( x + 23 ) + 6 = 96

3 ( x + 23 )       = 96 - 6

3 ( x + 23 )       = 90

      x + 23         = 90 ÷ 3

      x + 23         = 30

      x                  = 30 - 23

      x                  = 7

3 ( x + 23 ) + 6 = 96 

3 ( x + 23 )       = 96 - 6

3 ( x + 23 )       = 90  

     x + 23          = 90 : 3

     x + 23          = 30

     x                  = 30 - 23

     x                  = 7

96 - 3( x + 1 ) = 42

      3( x + 1 )  = 96 - 42

      3( x + 1 )  = 54

          x + 1    = 54 : 3 = 18

                 x   = 18 - 1 

                 x   = 17 

cau 1 

96-3(x+1)=42

=> 3(x-1)=54

=> x-1=18

=> x=19

cau 2 

12x-33=3².3³

=> 12x-33=243

=> 12x=276

=> x=23

12x - 33 = 3² . 3³

12x - 33 = 3⁵ = 243

      12x  = 243 + 33

       12x = 276

          x  = 276 : 12

          x  = 23

a)12x-33=3².3³

12x-33=243

12x=243+33

12x=276

x=276/12

x=23

a) 12x - 33 = \(3^2.3^3\)

\(\Rightarrow12x-33=3^5\)

\(\Rightarrow12x-33=243\)

\(\Rightarrow12x=243+33\)

\(\Rightarrow12x=276\)

\(\Rightarrow x=276:12\)

\(\Rightarrow x=23\)

b 96 - 3 (x + 10) = 42

\(\Rightarrow3\left(x+10\right)=96-42\)

\(\Rightarrow3\left(x+10\right)=54\)

\(\Rightarrow x+10=54:3\)

\(=>x+10=17\)

\(\Rightarrow x=17-10\)

\(\Rightarrow x=7\)

a)  12x - 33 = 3^2 . 3^3

     12x - 33 = 243

        12x     = 243 + 33

         12x    = 276

            x     = 276 : 12

            x     =  23

b)   96 - 3( x + 10 ) = 42

             3( x + 10 ) = 96 - 42

             3( x + 10 ) = 54

                x + 10    = 54 : 3

                x + 10    = 18

                  x          = 18 - 10

                  x          = 8