tìm x
a,2.3^x+1=10.3^12+8.3^12
b,2^x+2^x+3=144
tìm x
2.3x = 10.312 + 8.312
2 . 3x = 10 . 312 + 8 . 312
2 . 3x = ( 10 + 8 ) . 312
2 . 3x = 18 . 312
3x = 18 . 312 : 2
3x = 312 . 9
3x = 312 . 32
3x = 314
=>x = 14
\(\text{( đó là cách thuận tiện, lấy 18 : 2 = 9 cho thuận tiện nha )}\)
2.3\(^x\)=10.3\(^{12}\)+8.3\(^{12}\)
2.3\(^x\)=3\(^{12}\).(10+8)
2.3\(^x\)=18 .3\(^{12}\)=2.3\(^2\).3\(^{12}\)=2.3\(^{14}\)
vậy x=14
2.3x=10.312+8.312
2.3x=10.312+8.312
=>2.3x=18.312
=>2.3x=2.32.312
=>3x=314
=>x=14
2.3x =10.312+8.312
2.3x= 312.(10+8)
2.3x=312. 18
2.3x=312 . 32.2
2.3x=314.2
x=14
Tìm x
a)\(5^{\left(x-2\right).\left(x+3\right)}=1\)
b)\(\left(7-x\right)^{x+1}-\left(x-7\right)^{x+11}\ne0\)
c)\(x.\left(6-x\right)^{2003}=\left(6-x\right)^{2003}\)
d)\(2.3^x=10.3^{12}+8.3^{12}\)
e)\(5^x+5^{x+2}=650\)
a)5(x-2)(x+3)=1
=>5(x-2)(x+3)=50
=>(x-2)(x+3)=0
=>x-2=0=>x=2.
Và x+3=0=>x=-3.
Vậy x=2 và x=-3.
b)Câu này mik ko làm dc.
c)x.(6-x)2003=(6-x)2003
=>x=(6-x)2003:(6-x)2003
=>x=1.
Vậy x=1.
d)2.3x=10.312+8.312
=>2.3x=2.
1 Tìm x
a (19.x.1.2.5^2).14=(13-8)^2-4^2
b 2.3^x=10.3^12+8.27^4
Bài 1: tìm x
a) 2^2x.2^4=1024
b) 2.3^x=10.3^12+8.27^4
c) 5^8.25^x+1=5^17
d) 3^x-1+3^x-4=28.243
e) (2x-4)^5=(2x-4)^3
a) \(2^{2x}.2^4=1024\)
\(2^{2x}=1024:2^4\)
\(2^{2x}=1024:16\)
\(2^{2x}=64\)
\(2^{2x}=2^6\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
vay \(x=3\)
b) \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)
\(2.3^x=2.5.3^{12}+2^3.3^{12}\)
\(2.3^x=2.3^{12}.\left(5+2^2\right)\)
\(2.3^x=2.3^{12}.9\)
\(2.3^x=2.3^{12}.3^2\)
\(2.3^x=2.3^{14}\)
\(\Rightarrow x=14\)
vay \(x=14\)
c) \(5^8.25^x+1=5^{17}\)
\(5^8.\left(5^2\right)^x+1=5^{17}\)
\(5^8.5^{2x}+1=5^{17}\)
\(5^{8+2x}=5^{17}-1\)
e) \(\left(2x-4\right)^5=\left(2x-4\right)^3\)
\(\left(2x-4\right)^5-\left(2x-4\right)^3=0\)
\(\left(2x-4\right)\left[\left(2x-4\right)^2-1\right]=0\)
\(\left(2x-4\right)\left(2x-4-1\right)\left(2x-4+1\right)=0\)
\(\left(2x-4\right)\left(2x-5\right)\left(2x-3\right)=0\)
\(\Rightarrow2x-4=0\)hoac \(\orbr{\begin{cases}2x-5=0\\2x-3=0\end{cases}}\)
\(\Rightarrow2x=4\)hoac \(\orbr{\begin{cases}2x=5\\2x=3\end{cases}}\)
\(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
vay \(x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
tìm số tự nhiên x biết
a)2^x-15=17
b)(7^x-11)^3=2^5.5^2+200
c)2.3^x=10.3^12+8.27^4
d)(2x-150^5=(2x-15)^3
2\(^x\)- 15 = 17
\(\Rightarrow\)2\(^x\) = 32
\(\Rightarrow\)x = 5
2^x-15=17
=>2^x=17+15
=2^x=32
=>2^x=2^5
=>x=5
1 ) tìm x
a) (19.x +2.52):14=(13-8)2-42
b)2.3x-10.312+8.272
Please help me
a) (19.x + 2.52): 14 = 9
19.x +2.52 = 9.14 =126
19.x+ 50 =126
19.x =126-50 =76
x = 76 :19 = 4
Câu b sao ko có đáp án tìm x vậy bn
minh lam lun nha ko ghi lai de dau
a, (19x + 2.25): 14 = 5^2 - 4^2 (25-16)
( 19x + 50) = 9. 14
19x+50= 126
19x=126-50
x= 76:19
x= 4
muc b ko co kt qua lam sao ma lam
tìm x:
a. (19x+2.52):14=(13-8)2-42
b) 2.3x=10.312+8.274
tìm x 2.3^x=10.3^12+8.27^4
\(2.3^x=10\cdot3^{12}+8.27^4\)
\(10.3^{12}+8.27^4=10.3^{12}+8.3^{12}\)
\(10.3^{12}+8.3^{12}=3^{12}\cdot\left(10+8\right)=3^{12}\cdot18=3^{12}\cdot2\cdot3^2=3^{14}\cdot2\)
=>x = 14