(7x−11)³ = 2⁵ . 5² + 200

(7x−11)³ = 32 . 25 + 200

(7x−11)³ = 1000

(7x−11)³ = 10³

7x−11 = 10

7x       = 10 + 11

7x       = 21

  x      = 21 : 7

  x = 3

giúp mik ik mik tic cho

(7x−11)³ = 2⁵ . 5² + 200

(7x−11)³ = 32 . 25 + 200

(7x−11)³ = 1000

(7x−11)³ = 10³

7x−11 = 10

7x       = 10 + 11

7x       = 21

  x      = 21 : 7

  x = 3

(7x-11)³ = 2⁵.5²+ 2³.5²

(7x-11)³ = 2³.5²( 2²+1)

(7x-11)³ = 2³.5³=(2.5)³ 

7x-11=10

x=3

ban anhduc1501 hinh nhu lam chua dung to nghi vay

(7x - 11)³ = 2⁵ . 5² + 200

(7x - 11)³ = 32 . 25 + 200

(7x - 11)³ = 800 + 200

(7x - 11)³ = 1000

(7x - 11)³ = 10³

7x - 11 = 10

7x = 21

x = 3

a) \(2^x\)\(-\)\(64\)\(=\)\(2^6\)

    \(2^x\)\(-\)\(2^6\)\(=\)\(2^6\)

           \(2^x\)          \(=\)\(2^6\)\(+\)\(2^6\)

           \(2^x\)          \(=\) \(64\)\(+\)\(64\)

            \(2^x\)         \(=\)        \(128\)

  \(\Rightarrow\) \(2^x\)          \(=\)         \(2^7\)

b) \(\left(7x-11\right)\)\(^3\)\(=\)\(2^5\)\(.\)\(5^2\)\(+\)\(200\)

    \(\left(7x-11\right)\)\(^3\)\(=\)\(32\)\(.\)\(25\)\(+\)\(200\)

    \(\left(7x-11\right)\)\(^3\)\(=\)           \(1000\)

    \(\left(7x-11\right)\)\(^3\)\(=\)            \(10^3\)

\(\Rightarrow\)\(7x-11\)\(=\)\(10\)

               \(7x\)       \(=\)\(10+11\)

               \(7x\)        \(=\)    \(21\)

                  \(x\)        \(=\) \(21\)\(:\)\(7\)

                 \(x\)         \(=\)      \(3\)

\(2^x-64=2^6\)

\(2^x-64=64\)

\(2^x=64+64\)

\(2^x=128\)

\(\)Vì \(128=2^7\) \(\Rightarrow x=7\)

a, 2^x-64=2⁶

=> 2^x-64=64

=> 2^x=64-64

=> 2^x=0

=> x=0

b, (7x-11)³=2⁵.5²+200

=> (7x-11)³=32.25+200

=> (7x-11)³=1000

=> (7x-11)³=10³

=> 7x-11=10

=> 7x=10+11

=> 7x=21

=> x=21:7

=> x=3

\(\left(7x-11\right)^3=2^5.5^2+200\)

=> \(\left(7x-11\right)^3=32.25+200\)

=>\(\left(7x-11\right)^3=800+200\)

=>\(\left(7x-11\right)^3=1000\)

=>\(\left(7x-11\right)^3=10^3\)

=> \(7x-11=10\)

=>\(7x=21\)

=>\(x=3\)

Vậy x = 3

\(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(7x=10+11\)

\(7x=21\)

\(x=21\div7\)

\(x=3\)

\(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\left(7x-11\right)^3=32\cdot25+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(7x-11=10\)

\(7x=21\)

\(x=3\)

Ta có: \(\left(7x-11\right)^3=2^5+5^2+200=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Trả lời:

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=32.25+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=3\)

Vậy\(x=3\)

Hok tốt!

Good girl

\(\left(7\text{x}-11\right)^3=2^5\text{ }.\text{ }5^2+200.\)

\(\left(7\text{x}-11\right)^3=32\text{ }.\text{ }25+200.\)

\(\left(7\text{x}-11\right)^3=800+200.\)

\(\left(7\text{x}-11\right)^3=1000.\)

\(\left(7\text{x}-11\right)^3=10^3.\)

\(\Rightarrow\text{ }\text{7x}-11=10.\)

\(\text{7x}=10+11\)

\(\text{7x}=21\)

\(x=21\div7\)

\(x=3\)

Vậy \(x=3\)

b) x^10=1x

=> x=0 ; 1

c)(2x-15)^5=(2x-15)^3

=> (2x-15)^4 = (2x-15)^2

=> (2x-15)^2 =1

=> 2x-15=1

=> x=8 

(7x-11)³=2⁵.5²+200

(7x-11)³=32.25+200

(7x-11)³=800+200

(7x-11)³=1000

(7x-11)³=10³

=> 7x-11=10

7x=10+11

7x=21

x=21/7

x=3

cảm ơn bạn nha

làm như nào nhỉ

720 : [41-(2x-5)] =2^3 . 5

<=> 41-(2x-5)=720:40=18

<=> 2x-5=41-18=23

<=>2x=23+5=28

<=> x=28:2=14

2^x-15=17

<=> 2^x=17+15=32

<=> 2^x=2^5

<=> x=5

(7x-11)^3= 2^5.5^2+200

<=> (7x-11)^3=1000

<=> (7x-11)^3=10^3

<=> 7x-11=10

<=> 7x=10+11=21

<=> x=21:7=3

2^x-15=17 nhe. Minh viet nham

e) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\cdot\left(2x-15\right)^2-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\cdot\left[\left(2x-15\right)^2-1\right]=0\)

\(\Rightarrow\left(2x-15\right)^3=0\) hoặc \(\left(2x-15\right)^2-1=0\)

+)TH1: \(\left(2x-15\right)^3=0\)

\(\Rightarrow2x-15=0\)

\(\Rightarrow2x=15\)

\(\Rightarrow x=\frac{15}{2}\)

+)TH2: \(\left(2x-15\right)^2-1=0\)

\(\Rightarrow\left(2x-15\right)^2=1\)

\(\Rightarrow\left[{}\begin{matrix}2x-15=1\\2x-15=-1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}2x=16\\2x=14\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)

Vậy \(x=\frac{15}{2}\) hoặc \(x=8\) hoặc \(x=7\)

a) \(2^x-17=15\Rightarrow2^x=32\)

Mà \(2^5=32\Rightarrow x=5\)

Vậy x = 5

b)\(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\Rightarrow\left(7x-11\right)^3=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Vậy x = 3

c)\(x^{10}=1^x\Rightarrow x^{10}=1\)(số 1 có luỹ thừa là bao nhiêu thì vẫn là 1 thui)\(\Rightarrow x=1\)

Vậy x = 1

d) \(x^{10}=x\Rightarrow x^{10}-x=0\)

\(\Rightarrow x\left(x^9-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x^9-1=0\)

+)TH1: \(x=0\)

+)TH2: \(x^9-1=0\Rightarrow x^9=1\Rightarrow x=1\)

Vậy x = 0 hoặc x = 1

tìm x:

a)

2^x= 2⁵

=> x = 5

b)

(7x−11)³= 32 . 25 + 200

(7x−11)³= 800+200

(7x−11)³= 1000

10³= 1000

=> (7x−11)^{3 =} 10³

7x-11 = 10

7x= 11+10

7x = 21

x = 21: 7 = 3

=> x = 3

c)

=> x = 1

Vì cơ số 1 với số mũ nào thì cũng bằng 1

d)